Find the coordinates of the midpoint of the segment whose endpoints are given. W (-3, -7) and X (-8, -4)

Answers

Answer 1

Answer: Midpoint coordinates: x-coordinate: (-3+(-8))/2=-11/2
y-coordinate: (-7+(-4)/2=-11/2
So coordinates of the midpoint are: (-11/2, -11/2).

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alan participated ina car race in which he had to cover a distance of at least 50 kilometers. he had fuel in his car for a maximum distance of 53 kilometers. if the distance is given by S (t) = 3t + 47, where t is the time in hours, find the minimum and maximum number of hours for which alan can drive his car.

Answers

This problem has more holes than swiss cheese.

ASSUME that the time he drives only depends on the distance he covers,
and has nothing to do with his speed or how he drives.

The race rules say he has to cover at least 50 km,
so the minimum time he can drive is the solution to
[ 50 = 3t + 47 ]
Subtract 47 from each side:
3 = 3t
Divide each side by 3 :
1 = t minimum

He has fuel for exactly 53 km, so the maximum time
he can drive is the solution to
[ 53 = 3t + 47 ]
Subtract 47 from each side :
6 = 3t
Divide each side by 3 :
2 = tmaximum

What are the pattern conbination between these number 18 48 88 128 178 38 68

Answers

18+30=48
48+40=88
88+40=128
128+50=178

Thats all i found so far in the pattern
30,40,40,50
then it drops
by 140 then adds by 30..

I dont know how else to explain it

In a survey at a local university 35%, of students say that they get less than the recommended eight hours of sleep per night. In a group of 2000 students, how many would you expect get eight or more hours of sleep per night?

Answers

Answer:

1,500 students

Step-by-step explanation:

Since in the question it is mentioned that 35% of students get less than 8 hours of sleep

And, there is a group of 2,000 students

Now the number of students who get eight or more hours per night sleep is

Suppose the total percentage be 100

Now the students more than 8 hours is

= 100 - 35%

= 0.75

And, the total students is 2,000 students

So, the number of students who get eight or more hours is

= 2,000 students × 0.75

= 1,500 students

The same is to be considered

If log 6=a, then log 600= ?

Answers

$\log 600 = \log (100 \cdot 6)= \log 100 + \log 6 = \log 10^2 + \log 6 = \n 2 \log 10 +\log 6 =2+\log 6 = \boxed{a+2} \n \hbox{From formulas:} \n \log a + \log b = \log (ab) \n \log a^b = b\log a$

1)-3a²b² *3a²b5=
-
2) (-4 α²b6)³ =
3)-4m³h5.5n².m4=
4) (-3m²² h ²)4

Answers

1. -9a^4b^7
2.-64a^8b^216

3.-4m^7.5n^7

4.-12m^22h^2

sry if its wrong, i cant see the question clearly :)

Answer:

1. $-9a^(4)l^(7)$

2. $-64a^(6) b^(18)$

3. $-20m^(7)n^(7)$

4. $-64m^(28) h^(8)$

Step-by-step explanation:

Karissa eats 400 bananas per day. using f(x)=400x•422, where x is the amount of time in days, and f(x) is the amount of potassium in karissa's bones in Mg. how much radiation has she built up over 14 days, if there is 0.1 mSv of radiation per 422 milligrams of potassium.equation: f(x)=400x•422

Answers

Answer:

560 mSv of radiation

Step-by-step explanation:

To calculate how much radiation Karissa has built up over 14 days, we need to first calculate the amount of potassium in her bones after 14 days. We can do this using the function f(x):

$\sf f(x) = 400x \cdot 422$

where x is the amount of time in days, and f(x) is the amount of potassium in Karissa's bones in milligrams.

To calculate the amount of potassium in Karissa's bones after 14 days, we would simply substitute x = 14 into the function:

f(14) = 400 × 14 × 422

f(14) = 2363200 milligrams

Now that we know how much potassium is in Karissa's bones, we can calculate how much radiation she has built up.

We know that there is 0.1 mSv of radiation per 422 milligrams of potassium, so we can simply multiply the amount of potassium in Karissa's bones by 0.1 mSv/422 mg to calculate the amount of radiation she has built up:

$\begin{aligned} \textsf{Radiation amount }&= \sf 2363200 milligrams * 0.1 mSv/422 mg \n\n & = \sf 560 mSv \end{aligned}$

Therefore, Karissa has built up 560 mSv of radiation over 14 days.

Step-by-step explanation:

Substituting x = 14, we have f(14) = (400)(14)(422) = 2,363,200 mg of Potassium accumulated.

This is equivalent to (2363200)(0.1/422) = 560 mSv of radiation.

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