CHEMISTRY HIGH SCHOOL

Substances with a higher temperaturea. have less thermal energy.
b. have more molecular disorder.
c. become more orderly if heated more.
d. will move thermal energy to a hotter substance.

Answers

Answer 1
Answer: B. High temp = more thermal energy =more disorder as molecules move randomly = move from hot to colder substance(heat moves from hot to cold)
Answer 2
Answer:

Answer:

b is the corect awnser

Explanation:

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Answers

1. sales / marketing 

2. theoretical research / information chemist 

3. quality of life /environmental engineer 

4. finds practical applications / R&D 

5. manufacturing /production 

6. market research /product development 

7. short- and long-term objectives /corporate management 

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9. services equipment /technician 
The careers in chemistry should be closely related to working with chemical substances and the methods involved in experiments. Thus, the answers are finds practical applications information chemist and market research R&D.

How can an iceberg (temperature=0 Celsius) have more energy than a burning match head (temperature=230 Celsius)?

Answers

A burning match head whose temperature is 230 degree Celsius have more energy than an iceberg whose temperature is 0 degree Celsius.

What is Kinetic energy ?

Kinetic energy is a form of energy in which an object possesses due to its motion. The kinetic energy of an object is depends up on both the velocity and mass.  The S.I unit of Kinetic energy is Joules.

The temperature of burning match head is given 230 degree Celsius and temperature of iceberg is given 0 degree Celsius. A burning match head has a higher temperature than the iceberg due to average molecule in the burning match head moves faster than the average molecule in the iceberg.

Thus, from above conclusion we can say that A burning match head whose temperature is 230 degree Celsius have more energy than an iceberg whose temperature is 0 degree Celsius.

Learn more about the Kinetic Energy here: brainly.com/question/114210

#SPJ2
temperature is the average energy of each particle and does not really give you an indication of the total internal energy.  That being said, total internal energy is the sum of all of the molecule's energy in a given object so it would make sense that an ice berg (having a huge number molecules at a lower average energy) would have more internal energy than a match head (having a much smaller number of molecules at a higher average energy).  Basically, the fact that ice bergs tend to be huge and contain much more molecules than a match head, means that ice bergs can have a larger total internal energy which means they store more energy.

I hope this helps.

Fe2O3 + H2 --> Fe + H2OA) what mass of hydrogen gas must be consumed to produe 10.0 g of iron metal?

B) what mass of iron(lll) oxide, Fe2O3, must be consumed to prepare 2.50g of iron metal

Answers

A) 10.0g of Iron is (10.0)/(55.8)=179mmol of Iron.

One mole of dihydrogen is required to form one mole of iron, hence you'll need 0.179*1.00=0.179g of dihydrogen.

B) Likewise : 2.50g of Iron is (2.50)/(55.8)=44.8mmol of Iron, hence we'll need 44.8*(3*16+2*55.8)=7.15g of Fe2O3.

What is the OH- concentration of a solution whose pH is 12.40?

Answers

pH + pOH = pKw = 14

12.40 + pOH = 14

pOH = 14 - 12.40

pOH = 1.6

[OH⁻] = 10 ^(-pOH)

[OH⁻] = 10 ^(-1.6)

[OH⁻] = 2.5x10⁻² M

hope this helps!

What evidence of a chemical reaction might you see dropping an alka seltzer

Answers

Bubbling if you put it in a liquid

Calculate the energy required to melt 12.4 g of ice at 0 oC. The molar heat of fusion for ice is 6.02 kJ/mol.

Answers

Answer:

Energy required is 4.147 kj.

Explanation:

Given data:

Mass of ice = 12.4 g

Temperature = 0°C

Molar heat fusion for ice = 6.02 kj/mol

Energy required to melt = ?

Solution:

Formula:

q = n ×ΔH

q = heat

n = number of moles

ΔH = enthalpy

First of all we will calculate the number of moles.

Number of moles = mass/ molar mass

Number of moles = 12.4 g/ 18 g/mol

Number of moles = 0.69 mol

Now we will put the values in formula.

q = n × ΔH

q = 0.69 mol × 6.02 kj/mol

q = 4.147 kj
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