Answer:
≈ 0.70 g/cm³ (answer rounded up to 2 decimal places)
Explanation:
The mass of empty cylinder is 20g
The mass of water filling the cylinder = 30g - 20g = 10g
The mass of unknown liquid filling the cylinder = 27g - 20g = 7g
Density of water = 997 kg/m³
Converting this density to g/cm³ we get;
1kg = 1000g , 1m³ = 1000000cm³
So density = g/cm³ = 0.997 g/cm³
So the volume of water occupied by 10g is;
10 × 0.997 = 9.97 cm³
This volume is also occupied by 7g of the unknown liquid.
Density = mass/volume
Density of the unknown liquid = 7g ÷ 9.97cm³ = 0.702106319 g/cm³ ≈ 0.70 g/cm³ (answer rounded up to 2 decimal places)
B. muscular endurance.
C. cardiovascular endurance.
D. power.
201 M
5.52 M
1. There are a number of ways to express concentration of a solution. This includes molarity. Molarity is expressed as the number of moles of solute per volume of the solution. The concentration of the solution is calculated as follows:
Molarity = 612 g (1 mol / 110.96 g) / 3.04 L
Molarity = 1.81 M
1.81 M is the polarity of a solution that contains 612 grams of CaCl2 in 3.04 liters of solution.
Explanation:
Sodium has atomic number of 11 with electronic configuration of :
Sodium loose it single electron to attain stability of noble gas configuration. While this process electron gets removed from the outer shell of the sodium atom and it gains positive charge of +1.
(Ionization)
Answer:
NaClO₄
Solution:
Let us calculate the oxidation state of Chlorine in each compound one by one;
1) NaClO
O.N of Na = +1
O.N of O = -2
So,
(+1) + (Cl) + (-2) = 0
1 + Cl - 2 = 0
Cl = -1 + 2
Cl = +1
2) NaClO₃
(+1) + (Cl) + (-2)3 = 0
(+1) + (Cl) - 6 = 0
1 + Cl - 6 = 0
Cl = -1 + 6
Cl = +5
3) NaClO₂
(+1) + (Cl) + (-2)2 = 0
(+1) + (Cl) + (-4) = 0
1 + Cl - 4 = 0
Cl = -1 + 4
Cl = +3
4) NaClO₄
(+1) + (Cl) + (-2)4 = 0
(+1) + (Cl) + (-8) = 0
1 + Cl - 8 = 0
Cl = -1 + 8
Cl = +7