A car depreciated $1500 each year it was owned and driven. What type of depreciation is this?

Answers

Answer 1

Answer: it is yearly depreciation

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a(1)= 3 5 a(n)=a(n−1)⋅(−9) What is the 3^{\text{rd}}3 rd 3, start superscript, start text, r, d, end text, end superscript term in the sequence?

Answers

Answer: -630

Step-by-step explanation:

Given the nth term of a sequence;

a(n)=a(n−1)⋅(−9) and the first term of the sequence a(1) as 35, the third term of the sequence can be gotten by using the formula at when n = 3

If n = 3 and a(1) = 35;

a(3) = 35(3-1)•(-9)

a(3) = 35×2×-9

a(3) = 70×-9

a(3) = -630

There the 3rd term of the series will give us -630 according to the nth term of the formula given.

Final answer:

The problem is about a recursive sequence where each term is the previous term multiplied by -9. After applying this rule twice, it is found that the 3rd term of the sequence is 243.

Explanation:

The problem provided indicates a recursive sequence, where each term is based on the previous term. The sequence is defined as a(1) = 3 and a(n) = a(n - 1) ⋅ (−9), which essentially means that each subsequent term is the previous term multiplied by -9.

To find the 3rd term, we apply this rule twice starting from the first term:

a(2) = a(1) * (-9) = 3 * (-9) = -27

a(3) = a(2) * (-9) = -27 * (-9) = 243

Therefore, the 3rd term of the sequence is 243.

Learn more about Recursive sequence here:

brainly.com/question/36771236

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Need help with function

Answers

The answer is B, according to the Rules / Laws of Functions.

B is a function because it is the only one that has 4 different x values, therefore passing the vertical line test.

27 is the relationship linear, exponential, or neither? Options: a. Linear b. Exponential c. Neither

Answers

Answer: Here's my answer

Step-by-step explanation:

The relationship given, 27, is neither linear nor exponential.

In a linear relationship, the dependent variable (y) changes at a constant rate for every unit increase in the independent variable (x). This results in a straight line when plotted on a graph. However, the given value, 27, does not provide any information about how the variable changes in relation to another variable. Without this information, we cannot determine if the relationship is linear.

In an exponential relationship, the dependent variable (y) changes at an increasing or decreasing rate based on a constant ratio for every unit increase in the independent variable (x). This results in a curved line when plotted on a graph. Since the given value, 27, does not provide any information about the rate of change or the constant ratio, we cannot determine if the relationship is exponential.

Therefore, based on the given information, the relationship 27 is neither linear nor exponential.

What numbers multiply to 6 and add up to 9

Answers

xy = 6
x + y = 9

x + y = 9
x - x + y = -x + 9
y = -x + 9

  xy = 6
  x(-x + 9) = 6
  x(-x) + x(9) = 6
-x² + 9x = 6
  -x² + 9x - 6 = 0
-1(x²) - 1(-9x) - 1(6) = 0
-1(x² - 9x + 6) = 0
-1 -1
x² - 9x + 6 = 0
x = -(-9) ± √((-9)² - 4(1)(6))
2(1)
x = 9 ± √(81 - 24)
2
x = 9 ± √(57)
2
x = 4.5 ± 0.5√(57)

x + y = 9
4.5 ± 0.5√(57) + y = 9
- (4.5 ± 0.5√(57)) - (4.5 ± 0.5√(57))
y = 4.5 ± 0.5√(57)
(x, y) = (4.5 ± 0.5√(57), 4.5 ± 0.5√(57))

The two numbers that multiply to 6 and add up to 9 are 4.5 ± 0.5√(57).

What is the square root of ab^2

Answers

Why that's just ( √a √b² ), which in turn is ( b √a ).

Which is a subset of {1, 2, 4, 5, 6}?{0, 1, 2}
{3, 4}
{5, 6, 7}
{2, 6}

Answers

{2,6} is a subset of set {1, 2, 4, 5, 6} which is correct option (D).

What is a set?

A set is defined as a group of objects in mathematics. Set names and symbols begin with a capital letter. According to set theory, a set's constituent parts can be included in anything.

What is a Subset?

A subset is defined as part of a given set subset (another set or the same set). The set notation to represent a set A as a subset of set B is written as A ⊆ B.

Given set as :

{1, 2, 4, 5, 6}

There are 2⁵ = 32 subsets

(which you know because there are 5 numbers in the set).

{},{1},{2},,{ 4},{ 5},{ 6},

{1,2},{1, 4},{1, 5},{1, 6}

{2, 4},{2, 5},{2, 6},

{ 4, 5},{ 4, 6},{ 5, 6},

,{1,2, 4},{1,2, 5},{1,2, 6}

,{1, 4, 5},{1, 4, 6},{1, 5, 6}

,{2, 4, 5},{2, 4, 6},{2, 5, 6}

,{ 4, 5, 6} {1,2, 4, 5, 6},