Which statement describes the particles of an ideal gas, based on the kinetic molecular theory

Answers

Answer 1
Answer: this is easy...to put it simply, gas particles go in a straight line until they hit something, then ricochetand travel in a new direction, still in a straight line. 

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A voltaic cell is set up and a chemical reaction proceeds spontaneously. Which of the following will not occur in this reaction? a. The electrons will migrate through the wire
b. The cations in the salt bridge will migrate to the anode half-cell
c. The cathode will gain mass
d. The anode will lose mass
e. Reduction will occur at the cathode

Answers

d. anode will lose mass
because anode has negative charge and electrons loss by cathode will move to anode through a circuit to external wire

If a person's gallbladder were removed by surgery, which of the following substances would he have the most difficulty digesting? a. carbohydrates b. nucleic acids c. fats d. proteins

Answers

Explanation:

Fats

The gallbladder stores bile ( made in the liver)  which is secreted into the digestive tract to aid in the digestion of dietary fats.

Elements are composed ofA) many type of atoms.

B) the same type of atom.

C) many different compounds.

D) the same type of compound.

Answers

The correct answer is B, 'the same type of atom'. By definition, an element is a single type of atom. They are the most basic forms of matter, and so they cannot be more than one kind of atom, and they also cannot be a compound, since compounds are made up of multiple atoms.

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An atom of element X has one more shell of electrons than an atom of beryllium, but it has one less valence electron than beryllium. Which element is element X?

Answers

Element X is sodium. Sodium has one less valence electron than beryllium and it has the electron configuration of 2,8,1, thus it has one more shell of electrons.

Answer:

sodium

Explanation:

Which three factors can affect gas pressure?

Answers

The three factors can affect gas pressure are temperature, its volume, and the number of its particles.

What is the gas pressure?

The force exerted by gaseous molecules as they collide with the walls of their container is referred to as gas pressure. If the volume and temperature of a gas container remain constant, increasing the number of gas particles causes an increase in pressure, and vice versa.

Automobiles have tires. These tires (or tyres in British English) must have air pressure. Inflatable beds and baloons are two additional examples.

The pressure rises as the number of gas particles in a container increases. The pressure increases as the volume of a container increases.

Thus, The enclosed gas's pressure is determined by the number of gas particles, the volume of the container, and the temperature of the gas.

To learn more about the gas pressure, follow the link;

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Answer:

Temperature, pressure, volume, and the amount of gas.

Explanation: I hope this helped you, have a blessed day in Jesus' name. Check out my Y   t channel, it's called Going Dauntless

A closed system initially containing 1×10^-3M H2 and 2×10^-3 at 448°C is allowed to reach equilibrium. Analysis of the equilibrium mixture show s that the concentration of HI is 1.87×10^ -3. Calculate Kc at 448°C for the reaction.

Answers

Answer:

1.74845

Explanation:

We have the following reaction:

I2 + H2 => 2 HI

Now, the constant Kc, has the following formula:

Kc = [C] ^ c * [D] ^ d / [A] ^ a * [B] ^ b

In this case I2 is A, H2 is B and C is HI

We know that the values are:

 H2 = 1 × 10 ^ -3 at 448 ° C

I2 = 2 × 10 ^ -3 at 448 ° C

HI = 1.87 × 10 ^ -3 at 448 ° C

Replacing:

Kc = [1.87 × 10 ^ -3] ^ 2 / {[2 × 10 ^ -3] ^ 1 * [1 × 10 ^ -3] ^ 1}

Kc = 1.87 ^ 2/2 * 1

Kc = 1.74845

Which means that at 448 ° C, Kc is equal to 1.74845

Answer:

K_c = 51

Explanation:

[H2] = 10^-3

[I2] = 2*10^-3

[HI] = 0

in equilbiirum

[H2] = 10^-3 - x

[I2] = 2*10^-3 -x

[HI] = 0 + 2x

and we know

[HI] = 0 + 2x = 1.87*10^-3

x = ( 1.87*10^-3)/2 =  0.000935

then

[H2] = 10^-3 - 0.000935 = 0.000065

[I2] = 2*10^-3 -0.000935 = 0.001065

                        H₂                +          I              ⇄              2 HI

Initially     1 × 10⁻³                       2 × 10⁻³

Change  -9.35 × 10⁻⁴               -9.35 × 10⁻⁴                +1.87 × 10⁻³

At equil   6.5 × 10⁻⁵                  1.06 5 × 10⁻³               1.87 × 10⁻³

HI increase by 1.87 × 10⁻³M

K_c = ([HI]^2)/([H_2][I_2]) \n\n= ((1.87*10^-^3)^2)/((6.5*10^-^5)(1.065*10^-3)) \n\nK_c = 51