In order to raise money for holiday gifts for your family, you are planning on starting a dog walking and car wash business. You earn $12 per hour while dog walking and $18 per hour washing cars. You need to earn at least $600 during the month of November.1.Assign a variable to represent the number of hours that you will spend dog walking in November. Write an expression to represent the amount of money you need to earn while dog walking.
2.Assign a variable to represent the number of hours that you will spend washing cars in November. Write an expression to represent the amount of money you need to earn while washing cars.
3.Write an algebraic model using inequalities that represents the total amount of money earned by dog walking and washing cars during the month of November.
4.Graph the algebraic model in the first quadrant only. Let the x-axis be the number of hours spent dog walking and the y-axis be the number of hours spent washing cars. Click here for a sheet of graph paper to print..
5.Use the graph and algebraic model to answer the following:
a.Why does the graph exist only in the first quadrant?
b.Are you able to earn exactly $600? Use the solutions of the system to find possible combinations of outcomes that equal exactly $600. Where do all of the combinations occur in the graph?
c.Is it possible to earn more than $600? Use the solutions of the system to find possible combinations of outcomes that are greater than $600. Where do all of the combinations occur in the graph?
d.If you work for 10 hours walking dogs and 10 hours washing cars, will you have earned enough money for the holiday gifts? Where does 10 hours walking dogs and 10 hours washing cars fall on the graph? Is this location representative of the solution to the algebraic model? Click here for a sheet of graph paper to print..
6.How would the algebraic model be different if you needed to earn more than $600? Adjust your algebraic model to show that you must earn more than $600. Would the graph of the model be different from the original? Would you include the line in the solution? What type of line represents "more than"? Graph your new algebraic model .
7.In complete sentences, explain the difference between a solid line and a dashed line when graphing an inequality. When graphing the two algebraic models, how did you determine which type of line to use?
8.How did you determine which part of the graph of the inequality to shade? What does the shaded area tell you? What does the area that is not shaded tell you?
Answers
#2. Let y be the number of hours spent washing cars, then the amount of money earned washing cars is 18y.
#3.
Answer:
1.
x= number of dog walking hours; x≈300
2.
y= number of car washing hours; y≈300
3.
Ax+By≥600
4.
The download
5.
a- The graph can only exist in the first quadrant because you cannot work a negative amount of hours and/or get a negative amount of money.
b- You are able to earn a exact $600 if you work 23 hours of dog walking and 18 hours of car washing.
23x12=276 18x18=324 276+324=600
c- It is possible to earn greter than $600.
30x12=360 22x18=396 360+396>600
all combinations that occur on the graph are in quadrant one
d- If you work for 10 hours walking dogs and 10 hours washing cars, you will not have enough money.
10x12=120 10x18=180 120+180=300 300<600
(10,10) is not on the line therefore it is not a possible solution for the equation
6.
The model would be changed from Ax+By≥600 to Ax+By>600 becuase you need to earn MORE than 600 so there should not be a line under the symbol. The graph of the model would not be changed because you still are earning $12 and/or $18 an hour. A dotted line and the shaded area under the line represents more than.
7.
The difference between a dotted line and a solid line is that a dotted line is either more than or less than, while a solid line is more than or equal to and less than or equal to. When graphing, you would use a dotted line for equations that are not equal to or more or less.
8.
You determine whether or not that a shaded area is either he solution to a problem or not the solution.
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c^2 = a^2 + b^2 -2abcos(C)
cos(C) = (a^2 + b^2 - c^2)/2ab
this formula will solve your problem
(−1, −2) and (3, 10).
y +__ = __(x + 1)
Answers
A(-1,-2)
B(3,10)
Firstly I will find slope of this linear function:
m=(y-yo) / (x-xo)
m=(-2-10)/(-1-3)
m=-12/-4
m=3
Replacing A(-1-2) :
(y-yo)=m(x-xo)
y+2 =3(x+1)
:D