Statistics can help decide the authorship of literary works. Sonnets by a certain Elizabethan poet are known to contain an average of μ = 8.9 new words (words not used in the poet’s other works). The standard deviation of the number of new words is σ = 2.5. Now a manuscript with six new sonnets has come to light, and scholars are debating whether it is the poet’s work. The new sonnets contain an average of x~ = 10.2 words not used in the poet’s known works. We expect poems by another author to contain more new words, so to see if we have evidence that the new sonnets are not by our poet we test the following hypotheses.H0 : µ = 8.88 vs Ha : µ > 8.88
Give the z test statistic and its P-value. What do you conclude about the authorship of the new poems? (Let a = .05.)
Use 2 decimal places for the z-score and 4 for the p-value.
a. What is z?
b.The p-value is greater than?
c.What is the conclusion? A)The sonnets were written by another poet or b) There is not enough evidence to reject the null.

Answers

Answer 1
Answer:

Answer:

We conclude that the sonnets were written by by a certain Elizabethan poet.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 8.9

Sample mean, \bar{x} =10.2

Sample size, n = 6

Alpha, α = 0.05

Population standard deviation, σ = 2.5

First, we design the null and the alternate hypothesis

H_(0): \mu = 8.88\nH_A: \mu > 8.88

We use One-tailed z test to perform this hypothesis.

a) Formula:

z_(stat) = \displaystyle\frac{\bar{x} - \mu}{(\sigma)/(√(n)) }

Putting all the values, we have

z_(stat) = \displaystyle(10.2 - 8.9)/((2.5)/(√(6)) ) = 1.28

Now, z_(critical) \text{ at 0.05 level of significance } = 1.64

b) We calculate the p value with the help of z-table.

P-value = 0.1003

The p-value is greater than the significance level which is 0.05

c) Since the p-value is greater than the significance level, there is not enough evidence to reject the null hypothesis and accept the null hypothesis.

Thus, we conclude that the sonnets were written by by a certain Elizabethan poet.

Answer 2
Answer:

Final answer:

The z-score is 1.86 and the p-value is 0.0314. As the p-value is less than the level of significance α (0.05), we reject the null hypothesis and conclude that the new sonnets were likely written by another author.

Explanation:

In this statistical testing scenario for authorship of literary works, we need to find out the z-score or z test statistic and then determine the p-value to check if the new sonnets could be the works of the known Elizabethan poet or not.

For calculating the z score, you use the formula z = (x~ - μ) / (σ / √n) = (10.2 - 8.9) / (2.5/ √6) = 1.86 to two decimal places. The p-value is determined from the standard normal distribution table which for a z-score of 1.86 is 0.0314.

Given that α = 0.05, since the p-value is less than α, we reject the null hypothesis H0 (that the works were by the Elizabethan poet). Therefore, we accept the alternative hypothesis Ha (the sonnets were written by another author).

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Steven wants to make some extra money using a CD account. He wants $22,000 in his account after 5 yearscompounded continuously. How much principal will he have to start with, at an interest rate of 6.625%?

Answers

Answer: You got to multiply 22,000 times 5 and that will equal 110,000

Step-by-step explanation:

Final answer:

To have a final balance of $22,000 in a CD account after 5 years with continuous compounding at an interest rate of 6.625%, Steven needs to initially deposit approximately $15,895.68.

Explanation:

To calculate how much principal Steven should start with in his CD account, we need to use the formula for continuous compounding, which is A = Pe^(rt), where:

  • A is the amount of money accumulated after n years, including interest.
  • P is the principal amount (the initial amount of money).
  • e is the base of the natural logarithm, approximately equal to 2.71828.
  • r is the annual interest rate (decimal).
  • t is the time the money is invested for in years.

In Steven's case, he wants A = $22,000 after t = 5 years, at an interest rate r of 6.625% or 0.06625 in decimal format. Substituting these values into our formula and solving for P, we get:

P = A / e^(rt)

P = 22000 / e^(0.06625 * 5)

After calculating this expression, we find that Steven needs to deposit approximately $15,895.68 into his CD account to have $22,000 after 5 years with continuousinterest compounding at 6.625%.

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Stephanie was doing a science experiment to see what brand of cereal with raisinsactually had more raisins. She scooped out one cup of cereal and counted 27 raisins. If
there were 12 cups of cereal in the box, predict about how many raisins should there
be in the box?

Answers

Answer:

counted 27 raisins. If

there were 12

The diagram below shows a mass suspended on a string called a pendulum.What energy transformation occurs as the mass moves from point A to B?

A-kinetic energy is converted to potential energy

B-potential energy is converted to kinetic energy

C-chemical energy is converted to electrical energy

D-gravitational energy is converted to chemical energy

Answers

Answer:

D-gravitational energy is converted to chemical energy

Step-by-step explanation:

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How many different simple random samples of size 5 can be obtained from a population whose size is 51​? The number of simple random samples which can be obtained is 281887200281887200. ​(Type a whole​ number.)

Answers

Answer:

2349060

Step-by-step explanation:

Given that :

Population size (n)= 51

Number of simple random samples (r) = 5

Using the combination formula :

nCr = n! ÷ (n-r)! r!

51C5 = 51! ÷ (51 - 5)!5!

51C5 = 51! ÷ 46!5!

51C5 = (51*50*49*48*47)*46! / 46! * (5*4*3*2*1)

51C5 = (51*50*49*48*47) / (5*4*3*2*1)

51C5 = 281887200 / 120

= 2349060

Packer Concrete Company pours concrete slabs for single-family dwellings. Wolff Construction Company, which operates outside Packer’s normal sales territory, asks Packer to pour 40 slabs for Wolff’s new development of homes. Packer has the capacity to build 300 slabs and is presently working on 250 of them. Wolff is willing to pay only $2,750 per slab. Packer estimates the cost of a typical job to include unit-level materials, $1,200; unit-level labor, $600; and an allocated portion of facility-level overhead, $1,000.Required:
a. Calculate the contribution to profit from the special order.

Answers

Answer:

The contribution to profit from the special order us $38,000.

Step-by-step explanation:

Consider the provided information.

We need to calculate the contribution on to profit from the special order.

Wolff Construction Company, which operates outside Packer’s normal sales territory, asks Packer to pour 40 slabs for Wolff’s new development of homes. Packer has the capacity to build 300 slabs and is presently working on 250 of them. Wolff is willing to pay only $2,750 per slab.

Sale = 40 × $2,750 = $110,000

To find the profit subtract the materials and labor cost from sale amount.

     Particulars                                              Amount

Sale (40 × $2,750)                                     $110,000

Less: Variable expense

Unit level materials (40× $1,200)              $48,000

Unit level labor(40× $600)                        $24,000

Contribution margin                                   $38,000

The overhead cost will not be considered while determine the contribution to profit from accepting the order of 40 slab.

Hence, the contribution to profit from the special order us $38,000.

A cardboard box without a lid is to have a volume of 4,000 cm3. Find the dimensions that minimize the amount of cardboard used. (Let x, y, and z be the dimensions of the cardboard box.)

Answers

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