A game has 3 possible outcomes, with probabilities p1, p2, and p3. The amount of money that you will win or lose for each outcome is v1, v2, and v3, respectively. What is the expression p1v1 + p2v2 + p3v3 equal to?

Answers

Answer 1

Answer: We have the following given
p1 - probability for outcome 1
p2 - probability for outcome 2
p3 - probability for outcome 3
v1 - amount of money that you will win or lose for outcome 1
v2 - amount of money that you will win or lose for outcome 2
v3 - amount of money that you will win or lose for outcome 3

Therefore,
p1v1 + p2v2 + p3v3 is the average money you win or lose in playing the game.

Answer 2

Answer:

Answer:

Option b) The average amount you will win (or lose) per game in the long run

Step-by-step explanation:

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Find the inverse of the following f(x)=-3x^2+3 X>0

Answers

Answer

f^-1(x) =√[(3-x)÷3]

Step-by-step explanation:

y=-3x^2+3

interchange 'y' with 'x'

x=-3y^2+3

make y the subject

3y^2=3-x

divide by '3' both sides

y^2=(3-x)÷3

apply square root both sides

√(y^2)=√[(3-x)÷3]

y=√[(3-x)÷3]

f^-1(x) =√[(3-x)÷3]

the inverse of the given function is

f^-1(x)=√[(3-x)÷3]

The John Jay Theater Dept has tickets at $6 for adults, $4 for teachers, and $2 for students. A total of 280 tickets were sold for one showing with a total revenue of $1010. If the number of adult tickets sold was twice the number of teacher tickets, how many of each type of ticket were sold for the showing?

Answers

Answer:

number of adults tickets sold = x = 90

number of teachers tickets = y = 45

number of students tickets = z = 145

Step-by-step explanation:

Cost of tickets

Adults = $6

Teachers = $4

Students = $2

Total tickets sold = 280

Total revenue = $1010

Let

x = number of adults tickets

y = number of teachers tickets

z = number of students tickets

x + y + z = 280

6x + 4y + 2z = 1010

If the number of adult tickets sold was twice the number of teacher tickets

x = 2y

Substitute x=2y into the equations

x + y + z = 280

6x + 4y + 2z = 1010

2y + y + z = 280

6(2y) + 4y + 2z = 1010

3y + z = 280

12y + 4y + 2z = 1010

3y + z = 280 (1)

16y + 2z = 1010 (2)

Multiply (1) by 2

6y + 2z = 560 (3)

16y + 2z = 1010

Subtract (3) from (2)

16y - 6y = 1010 - 560

10y = 450

Divide both sides by 10

y = 450/10

= 45

y = 45

Substitute y=45 into (1)

3y + z = 280

3(45) + z = 280

135 + z = 280

z = 280 - 135

= 145

z = 145

Substitute the values of y and z into

x + y + z = 280

x + 45 + 145 = 280

x + 190 = 280

x = 280 - 190

= 90

x = 90

Therefore,

number of adults tickets sold = x = 90

number of teachers tickets = y = 45

number of students tickets = z = 145

The order pair (0 , 0) is a solution to the inequality y < x -2 False
or
True

Answers

Answer:

true

Step-by-step explanation:

0 < -2

I hope that helped :)

Answer:

false

Step-by-step explanation:

I put it into a graphing calculator

PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!Find IJ.

Write your answer as an integer or as a decimal rounded to the nearest tenth.

IJ =

Answers

Yo sup??

we have to apply trigonometric ratios ie sine

sin63=IJ/HJ

IJ=HJ*sin63

=8.0

Hope this helps.

Answer:

The answer should be 8. Hope this help you out.

Vector AB has an initial point (4,3) and terminal point (-5,1). Determine the coordinates of the terminal point of AC if AC = -2ABA. (-9,-2)
B. (18,4)
C. (22,7)
D. (-4,-3)