Please Help me!!!!!! Its my last question! What is the value of x so that the line segment with endpoints A(x, 1) and B(2, −3) is parallel to the line segment with endpoints C(−5, 2) and D(−3, 5)?

x = start fraction two over three end fraction
x = 5
x = 4
x = four start fraction two over three end fraction

Answers

Answer 1
Answer: the reasonable answer is D makes since

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Orlo Jackman heard an ad on the radio for a weekend cruise to the Bahamas, available for $150 off the regular price this week only . This discount reflected a 25% markdown. What is the regular price of the cruise?

Answers

Answer:

$600

Step-by-step explanation:

Given :

Orlo Jackman heard an ad on the radio for a weekend cruise to the Bahamas, available for $150 off the regular price this week only .

This discount reflected a 25% markdown

To Find : . What is the regular price of the cruise?

Solution :

Let the original price be x

Since we are given that discount reflected a 25% markdown

(25)/(100)  x  is the off

And we are also given that there is an off of 150

(25)/(100) x =150

x =(150*100)/(25)

x =600{25}

Hence the original price of the cruise is $600


$600 because you must multiply. 150/ (25/100)... 1,500/25= 600

Which expression is equivalent to 28 + 12? (1 point) 4(7 + 3) 4(24 + 8) 7(4 + 12) 7(21 + 5)

Answers

Answer:

4(7+3)

Step-by-step explanation:

28 and 12 are both divisible by 4.

28 ÷ 4 = 7

12 ÷ 4 =  3

Answer:

4(7+3)

Step-by-step explanation:

4(7) = 28

4(3)= 12

28+12=28+12

Hope this helps!

F(x) = x - 6
g(x) = 3x2 + 5x – 5
Find: g(f(x))

Answers

Answer:

Step-by-step explanation:

g(x - 6)= 3(x - 6)^2 + 5(x - 6) - 5

          = 3(x^2 - 12x + 36) + 5x - 30 - 5

          = 3x^2 - 36x + 108 + 5x  - 35

          = 3x^2 - 31x + 73

   

The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line?

Answers

The equation of line passes through points \left({ - \,4, - \,3}\right) and \left({12,1}\right) in standard form is \boxed{{\mathbf{x - 4y = 8 }}}.

Further explanation:

It is given that a line passes through points \left({ - 4, - 3}\right) and \left({12,1}\right).

The slope of a line passes through points \left({{x_1},{y_1}}\right) and \left({{x_2},{y_2}}\right) is calculated as follows:

m=\frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}{\text{ }}   ......(1)

Here, the slope of a line is denoted as  and points are \left({{x_1},{y_1}}\right) and \left({{x_2},{y_2}}\right).

Substitute  for {x_1} , -3 for {y_1} , 12  for {x_2} and 1 for {y_2} in equation (1) to obtain the slope of a line that passes through points \left({ - 4, - 3}\right) and \left({12,1}\right).

\begin{aligned}m&=\frac{{1 - \left({ - 3}\right)}}{{12 - \left({ - 4}\right)}}\n&=\frac{{1 + 3}}{{12 + 4}}\n&=\frac{4}{{16}}\n&=(1)/(4)\n\end{aligned}

Therefore, the slope is  (1)/(4).

The point-slope form of the equation of a line with slope m passes through point \left({{x_1},{y_1}}\right) is represented as follows:

y - {y_1}=m\left({x - {x_1}}\right){\text{}}      ......(2)

Substitute  for {x_1} , 1 for {y_1} and (1)/(4) for m in equation (2) to obtain the equation of line.

\begin{aligned}y - 1&=(1)/(4)\left({x - 12}\right)\n4\left({y - 1}\right)&=x - 12\n4y - 4&=x - 12\nx - 4y&=8\n\end{aligned}

Therefore the standard equation of line that passes through points \left({ - 4, - 3}\right) and \left({12,1}\right) is x - 4y = 8.

Thus, theequation of line passes through points \left({ - 4, - 3}\right) and \left({12,1}\right) in standard form is \boxed{{\mathbf{x - 4y = 8 }}}

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Answer Details:

Grade: Junior High School

Subject: Mathematics

Chapter: Coordinate Geometry

Keywords:Coordinate Geometry, linear equation, system of linear equations in two variables, variables, mathematics,equation of line, line, passes through point

Find the Surface Area and Volume of Sphere with radius 12 cm.

Answers

Radius:r=12cm\n\nSurface\ area:\nA=4\pi r^2\to A=4\pi\cdot12^2=4\pi\cdot144=576\pi\ (cm^2)\n\nVolume:\nV=(4)/(3)\pi r^3\to V=(4)/(3)\pi\cdot12^3=(4)/(3)\pi\cdot1728=4\pi\cdot576=2304\pi\ (cm^3)
The surface area of a sphere is 4 pi R² = 576 pi = 1,809.6 cm² (rounded)

The volume of a sphere is 4/3 pi R³ = 2,304 pi = 7,238.2 cm³ (rounded)

Write a trinomial whose terms have a GCF of 2

Answers

(2x + 6x + 4) All you need to find is numbers that can all be divided by 2.

Final answer:

To write a trinomial with a GCF of 2, start by factoring out the GCF from each term. For example, the trinomial 4x^2 + 6xy + 8y^2 can be factored as 2(2x^2 + 3xy + 4y^2).

Explanation:

A trinomial is an algebraic expression with three terms. The greatest common factor (GCF) is the largest factor that all the terms share. To write a trinomial with a GCF of 2, we can start by factoring out the GCF from each term. Let's say the original trinomial is:

4x^2 + 6xy + 8y^2

The GCF of the trinomial can be found by listing the factors of each term and selecting the highest common factor. In this case, the factors of 4x^2 are 2 and 2x^2, the factors of 6xy are 2, 3, x, and y, and the factors of 8y^2 are 2^3 and y^2. The highest common factor is 2, so we can factor out 2 from each term:

2(2x^2 + 3xy + 4y^2)

This is a trinomial with a GCF of 2.

Learn more about  trinomial  here:

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