Answer:
Explanation:
That is a chemical property of alkali metals: they are highly reactive and react vigorously with water to produce the correspondant hydroxide and hydrogen gas.
These are some of those reactions:
The alkali metals are the elements of group 1 of the periodic table: Li, Na, K, Rb, Cs, and Fr. They have one valence electron which may lose easily to form an ion with charge +1.
Alkali metals react with water to produce hydrogen gas and a basic solution of the metal hydroxide (for instance, sodium hydroxide when lithium is in the reaction). This reaction signifies the easier oxidation of alkali metals compared to hydrogen.
When alkali metals react with water, they form hydrogen gas and a basic solution of the metal hydroxide. This vigorous reaction reveals that alkali metals are easier to oxidize than is hydrogen. For instance, considering the reaction of lithium with water:
2Li(s) + 2H₂O(l) --> 2NaOH(aq) + H₂(g)
The solid state (s) lithium reacts with liquid water to generate hydrogen gas and the ionic compound sodium hydroxide. This sodium hydroxide, which is a solid in its pure form, promptly dissolves in water.
The same kind of reaction occurs with other alkali metals and also some alkaline earth metals, although beryllium and magnesium are exceptions.
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Ketone bodies
The balanced chemical reaction is:
2Al2O3 = 4Al +3 O2
We are given the amount of the reactant. This will be the starting point of our calculations.
26.5 mol Al2O3 ( 3 mol O2 / 2 mol Al2O3 ) = 39.75 mol O2 needed
Thus, 0.014 mol of I2 is needed to form the given amount of NI3.
the balanced chemical equation for the decomposition of Al₂O₃ is as follows
2Al₂O₃ --> 4Al + 3O₂
stoichiometry of Al₂O₃ to O₂ is 2:3
when 2 mol of Al₂O₃ decomposes - 3 mol of O₂ are formed
therefore when 26.5 mol of Al₂O₃ decomposes - 3/2 x 26.5 mol = 39.75 mol
the number of moles of O₂ formed are 39.75 mol
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