CHEMISTRY HIGH SCHOOL

Which of the following is a single replacement reaction?2Al + 6H2O yields 2Al(OH)3 + 3H2
AgNO3 + NaCl yields AgCl + NaNO3
Fe2O3 + 3H2O yields 2Fe(OH)3
CH4 + 2O2 yields CO2 + 2H2O

Answers

Answer 1
Answer:

2Al +H2O yield 2Al(OH)3 + 3H2 (answer A)

is an example of single replacement reaction

This is because single replacement reaction involve an element reacting with a compound and take place of another element in that compound. Al an element react with to yield Al(OH)3 and H2. Al take place of H + therefore the reaction above is example of single replacement.
Answer 2
Answer: The answer is the first one. 2Al+6H2O yields 2Al(OH)3H2

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Covalent bonding is when atomstransfer electrons

drop electrons

share electrons

create electrons

Answers

The correct answer is the 3rd option. Covalent bonding is when atoms share electrons. It is a chemical bond that involves the sharing of electron pairs. These pairs are called bonding pairs. Examples of compounds that has covalent bonds are CO2, organic compounds, lipids and proteins.

its on usa test prep my frens

The specific heat of liquid ethyl alcohol is 2.42 j/g C and its density of 0.7893 g/mL. A piece of solid sliver (specific heat 0.24 J/g C) was heated to95 C and placed in 25.6 mL of ethyl alcohol that had a temp of 19.27 C. The final temp of alcohol and silver was 23.5 C. How many grams of silver were used?

Answers

The specific heat of liquid ethyl alcohol is 2.42 j/g C and its density of 0.7893 g/ml. The amount of silver used is 12.05 g.

What is specific heat?

Specific heat is defined as the amount of heat needed to raise the temperature of one gram of a substance by one degree Celsius.

It can also be defined as the quantity of heat energy necessary to raise a body's temperature per unit of mass.

Specific heat is expressed as

Q = mcΔT

As per the question

Q silver = Q alcohol

= m silver x Co silver x (T f - T silver) =  m alcohol x C p alcohol ( T f -T alcohol)

= m silver x 0.24 x (23.5-95) = 25.6 x 0.7893 x 2.42 x (23.5 - 19.27)

=  25.6 x 0.7893 x 2.42 x (23.5 - 19.27)  / (-0.24 x (23.5 - 95)

= 12.5 grams

Thus, the specific heat of liquid ethyl alcohol is 2.42 j/g C and its density of 0.7893 g/ml. The amount of silver used is 12.05 g.

To learn more about specific heat, refer to the link below:

brainly.com/question/11297584

#SPJ2
First off, as any good chemist would tell you, we have to know if this is an isolated system or not, or else there could be energy (namely heat) that could escape the system or matter from evaporation and stuff.

SOLUTION

25.6 (volume) * 0.7893 (density) = mass of the ethyl alcohol 
If it was heated to 19.27 degrees Celsius, this translates to 292.27 Kelvin. The specific heat of liquid ethyl alcohol is 2.42 j/(g*C), which is the same as 2.42 j/(g*K), therefore it has in total 2.42 * 292.27 * 25.6 * 0.7893 Joules of heat.

The silver has x grams, and its specific heat is 0.24 J/g*C = 0.24 J/g*K. If it was heated up to 95 degrees, that means it was heated to 368 degrees Kelvin. Therefore it 368 * 0.24 * x Joules of heat.

If the final temperature was 23.5 degrees Celsius of the entire thing, than the ethyl alcohol had 2.42 * 296.5 * 25.6 * 0.7893 Joules of heat. Getting the difference of the first state and the second state, we get 2.42 * (296.5 - 292.27) * 25.6 * 0.7893 Joules. This was added to the silver, which now has 296.5 * 0.24 * x Joules of heat. Subtracting the first state from the second state we get (296.5-368) * 0.25 * x Joules. The absolute value of this equals 2.42 * (296.5 - 292.27) * 25.6 * 0.7893 Joules. Doing all the math out, 206.84155853 = 17.16x.

Therefore x = 12.05 grams.

There are 12.05 grams of silver.

How would you solve this problem??

Answers

Calculate the pOH where [OH⁻]=4.7×10⁻³M:
pOH=-log[OH⁻]
pOH=-log(4.7×10⁻³)
pOH=2.33

Calculate [OH⁻] if the pOH is 1.34:
pOH=-log[OH⁻]
10^(-pOH)=[OH⁻]
[OH⁻]=10^(-pOH)
[OH⁻]=10^(-1.34)
[OH-]=0.0457M or [OH⁻]=4.57×10⁻²M

Calculate pH if the [OH⁻] is 1.74×10⁻²M:
[H⁺]=K(w)/[OH⁻]              or                  pOH=-log[OH⁻]
[H⁺]=(1×10⁻¹⁴)/(1.57×10⁻²)                   pOH=-log(1.74×10⁻²)
[H⁺]=6.369×10⁻¹³M                              pOH=1.759
pH=-log[H⁺]                                          pH=14-pOH
pH=-log(6.369×10⁻¹³)                           pH=14-1.759
pH=12.2                                               pH=12.2

I hope this helps.  Let me know if anything is unclear.

Which activity is the best demonstration of J. J. Thomson’s use of creativity in his work?

Answers

Through J.J. Thomson's creative mind, he proposed the "Plum Pudding Theory" which shows the scientific model of an atom wherein electrons are attached to the body of the atom as if it was like a raisin in a pudding. He also consolidates the properties of atoms at that time such as: electrons are negatively charge particles and and atom has neutral charge.

What happens when the kinetic energy of molecules increases so much that electrons are released by the atoms, creating a swirling gas of positive ions and negative electrons?

Answers

the answer is d in this case

Answer:

it's C

Explanation:

There are more hydroxide ions in a solution than hydrogen ions. The solution is acidic

basic

neutral

a salt

Answers

The hydroxide ion concentration is what is used to measure the POH of a substance (basicity) thus with more hydroxide that hydrogen ions, the solution is Basic. 
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