A material will float on the surface of a liquid if the material has a density less than that of the liquid. Given that the density of water is approximately 1.0 g/mL, will a block of material having a volume of 1.2 x 10^4 in^3 and weighing 350 lb float or sink when placed in a reservoir of water? [I just don't want the answer, I'd like to know how to solve this, please.]

Answers

Answer 1

Answer:

Density is defined as the ratio of mass to volume of a substance.

The density of water is generally known to be 1.0 g/mL. Substances that are less dense than water will float on water while substances that are denser than water will sink in water.

We have to calculate the density of the block material in units of g/ml.

Volume of the block = $1.2 x 10^4 in^3$ = 19.66 mL

Mass of the block = 350 lb = 158757 g

Density of the block = $(mass)/(volume)$

Density of block = $(158757 g)/( 19.66 mL)$

= 8075.13 g/mL

Hence the block material will sink in water.

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Answer 2

Answer: Given:
density of water is approximately 1.0 g/mL
block of material
volume of 1.2 x 10^4 in^3
and weighing 350 lb

Required:
Which will float

Solution:
D = M/V where D is density, M is mass and V is volume

convert 1.2 x 10^4 in^3 into mL
1.2 x 10^4 in^3 (16.39 mL/ 1 in3) = 196,980 mL

convert 350 lb into grams
350 lb (454 grams/1 lb) = 158,900 grams

D = M/V = 158,900 grams/ 196,980 mL
D = 0.807 g/mL

The block will float in water because it is less dense than water

Answer:

3 US Cups = 720 ml.

Explanation:

Officially, a US Cup is 240ml (or 8.45 imperial fluid ounces.)
3 x 1 US Cup = 3 US Cups
1 US Cup = 240 ml.
∴ 3 US Cups = 3 x 240ml
= 720 ml.

Match the following definition to the type of solution it describes. unsaturated solution
saturated solution
supersaturated solution

A.
The amount of solute dissolved is less that the maximum amount the solution can hold.
B.
The amount of solute dissolved is the maximum amount the solution can hold.
C.
The amount of solute dissolved is more than the usual maximum amount.

Answers

unsaturated solution is The amount of solute dissolved is less that the maximum amount the solution can hold.

saturated solution is The amount of solute dissolved is the maximum amount the solution can hold.

supersaturated solution is The amount of solute dissolved is more than the usual maximum amount.

While driving your rental car on your trip to Europe, you find that you are getting 9.7 kilometers per liter of gasoline. What does this correspond to in miles per gallon?

Answers

The given value is $9.7 km/L$

Since, $1 km = 0.62 mile$ so:

$9.7 km = 9.7 km * 0.62 miles/km$ = $6.014 miles$

Since, $1 L = 0.2199 galon$ so:

$9.7 km/L = (6.014 miles)/(0.2199 galon)$

$27.35 miles/ galon$

Hence, 9.7 kilometers per liter of gasoline is $27.35 miles/ galon$ .

While driving your rental car on your trip to Europe, you find that you are getting 9.7 kilometers per liter of gasoline. We know that 1 mile is equal to 1.609 kilometers. So divide 9.7 kilometers by 1.609 kilometrs/mile and you will get 6.03 miles per gasoline

Which law states that the volume and absolute temperature of a fixed quantity of gas are directly proportional under constant pressure conditions?

Answers

$\boxed{{\text{Charles's law}}}$ states that volume occupied by a fixed quantity of a gas is directly proportional to the absolute temperature (Kelvin) at constant pressure.

Further Explanation:

Charles’s law:

Charles’s work showed that at constant pressure, the volume-temperature relationship for a fixed amount of gas is linear. In other words, Charles’s law can be stated that at constant pressure, the volume occupied by a fixed amount of a gas is directly proportional to its absolute temperature (Kelvin). This relationship is known as Charles’s law.

The mathematical representation of Charles’s law is,

${\mathbf{V}} \propto {\mathbf{T}}$ [P and n are constant]

Where,

V is volume occupied by the fixed quantity of gas.

T is the temperature of a gas.

P is the pressure of a gas.

n denotes the number of moles of gas.

The relationship can also be expressed as,

$\frac{{\mathbf{V}}}{{\mathbf{T}}}{\mathbf{ = constant}}$ [P and n are constant]

Or,

$\frac{{{{\mathbf{V}}_{\mathbf{1}}}}}{{{{\mathbf{T}}_{\mathbf{1}}}}}{\mathbf{ = }}\frac{{{{\mathbf{V}}_{\mathbf{2}}}}}{{{{\mathbf{T}}_{\mathbf{2}}}}}$ [P and n are constant]

Results of Charles’s law are as follows:

At constant pressure, if the volume of gas increases then the temperature also increases.

At constant pressure, if the volume of gas decreases then the temperature also decreases.

The volume (L) versus temperature (T) curve of Charles’s law is represented in the attached diagram.

Learn more:

1. Law of conservation of matter states: brainly.com/question/2190120

2. Calculation of volume of gas: brainly.com/question/3636135

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Ideal gas of equation

Keywords: Charles’s law, volume, temperature, pressure, volume temperature relationship, absolute temperature, constant pressure, relationship, V directly proportional to T, ideal gas, ideal gas equation number of moles, moles.

Charles's Law states that the volume and absolute temperature of a fixed quantity of gas are directly proportional under constant pressure conditions

Further explanation

There are several gas equations in various processes:

1. The general ideal gas equation

PV = nRT

PV = NkT

N = number of gas particles

n = number of moles

R = gas constant (8,31.10 ^ 3 J / kmole K

k = Boltzmann constant (1,38.10 ^ -23)

n = = N / No

n = m / M

n = mole

No = Avogadro number (6.02.10 ^ 23)

m = mass

M = relative molecular mass

2. Avogadro's hypothesis

In the same temperature and pressure, in the same volume conditions, the gas contains the same number of molecules

So it applies: the ratio of gas volume will be equal to the ratio of gas moles

V1: V2 = n1: n2

2. Boyle's Law

At a fixed temperature, the gas volume is inversely proportional to the pressure applied

p1.V1 = p2.V2

3. Charles's Law

When the gas pressure is kept constant, the gas volume is proportional to the temperature

V1 / T1 = V2 / T2

4. Gay Lussac's Law

When the gas is heated in a tube whose volume does not change, the gas pressure in the tube is proportional to its absolute temperature

P1 / T1 = P2 / T2

5. Law of Boyle-Gay-Lussac

Combined with Boyle's law and Gay Lussac's law

P1.V1 / T1 = P2.V2 / T2

P1 = initial gas pressure (N / m2 or Pa)

V1 = initial gas volume (m3)

P2 = gas end pressure

V2 = the final volume of gas

T1 = initial gas temperature (K)

T2 = gas end temperature

So the correct answer is Charles' Law, where at constant pressure, the volume of gas will be inversely proportional to its temperature

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Why is HBrO a weaker acid than HBrO3? A. The HO bond in HBrO is less polar than the HO bond in HBrO3 B. The HO bond in HBrO is more polar than the HO bond in HBrO3 C. The HBr bond in HBro is weaker than the HBr in HBrO3 D. The HBr bond in HBrO is stronger than the HBr bond in HBrO3 E. The HO bond in HBrO is weaker than the HO bond in HBrO3

Answers

Ans: A)

HBrO and HBrO₃ are oxyacids where the acidic strength increases with the increase in the number of atoms attached to the central atom.

In both acids, oxygen is the most electronegative atom. In HBrO, the B atom is linked to only one O atom. In contrast, there are 3 electronegative O atoms surrounding the central B atom in HBrO₃ which would make the OH bond more polar and easily accessible. Thus, HBrO₃ tends to lose a proton readily than HBrO making the former more acidic.

HBrO is a weaker acid than HBrO3 because the H-O bond in HBrO is less polar than the H-O bond in HBrO3. In a series of oxyacids with similar formulas, the higher the electronegativity of the central atom, the stronger is the attraction of the central atom for the electrons of the oxygen(s), making the acid stronger.

The acid strength of HBrO is weaker than HBrO3 because the H-O bond in HBrO is less polar than the H-O bond in HBrO3 (Option A). In a series of oxyacids with similar formulas, the higher the electronegativity of the central atom, the stronger is the attraction of the central atom for the electrons of the oxygen(s). This stronger attraction of oxygen for the electrons in the O-H bond makes the hydrogen more easily released, resulting in a stronger acid (Option E). Therefore, HBrO3 is a stronger acid than HBrO.

Learn more about Oxyacids here:

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Which of the following group 18 elements would be most likely to form a compound with fluorine?. . HE. NE. AR. KR

Answers

The one that is most likely to form a compound with fluorine is : Kr

out of the options, Kr is the largest atom and it contains more energy cells than the others, which make the fluorine more attracted to the Kr Nucleus

Hope this helps

Final answer:

Among He, Ne, Ar, and Kr, krypton (Kr) would be most likely to form a compound with fluorine. It's one of the heavier noble gases, which can form compounds with highly reactive elements like fluorine due to their slightly less firm hold on outermost electrons.

Explanation:

The elements in Group 18 are noble gases: helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). These gases are known for their low reactivity because they have fully filled valence shells. However, the three heaviest noble gases - krypton, xenon, and radon - can react with fluorine to form fluorides, with xenon fluorides being the most well-researched among other noble gas compounds.

Among the options provided (He, Ne, Ar, Kr), krypton (Kr) would be the most likely to form a compound with fluorine. This is due to krypton's bigger size as it descends the periodic table, which slightly decreases the grip on its outermost electrons, making it marginally more likely to react with extremely reactive elements like fluorine.