Which two metals would react with aluminium nitrate in a displacement reaction?

Answers

Answer 1

Answer:

Answer:

potassium and sodium

Explanation:

There are many metals that can react with aluminium nitrate in a displacement reaction. these metals are higher than aluminium in the electrochemical series of elements where metals are arranged based on their reactivity and therefore tend to displace aluminium in any chemical reaction. However the most reactive of these metals are potassium(K) and sodium(Na). Others are calcium(Ca), magnesium(Mg), lithium(Li), strontium (Sr).

Answer 2

Answer: what are your choices? potassium? sodium? calcium? lithium? magnesium? add your choices please

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You fill a rigid steel cylinder that has a volume of 20.0 L with nitrogen gas to a final pressure of 2.00 *10^4 Kpa at 28c How many kilograms of N2 does the cylinder contain

Answers

The quantity of nitrogen the cylinder contains is 4477.8 g

What is pressure?

Pressure is a force exerted in a perpendicular direction in any item.

By ideal gas law

PV = nRT

$P =(w)/(M) =(RT)/(V)\n$

w = mass

Volume is 20.0 l

Pressure is $2.00 * 10^4 \;Kpa$

The molar mass of nitrogen is 28 g/mol

R is gas constant = 0.0821

Temperature is 28 converted into kelvin that is 301 k

Putting the values

$197.6 =(w)/(28) =(0.0821 * 301 )/(20\;l)\n\nw = 4477.8 g$

Thus, the mass of nitrogen is 4477.8 g.

Learn more about pressure, here:

brainly.com/question/356585

Answer : The mass of $N_2$ gas is, 4477.8 g

Solution :

using ideal gas equation,

$PV=nRT\n\nP=(w)/(M)* (RT)/(V)$

where,

n = number of moles of gas

w = mass of gas

P = pressure of the gas = $2* 10^4Kpa=197.6atm$

conversion : $1atm=101.2Kpa$

T = temperature of the gas = $28^oC=273+28=301K$

M = molar mass of $N_2$ gas = 28 g/mole

R = gas constant = 0.0821 Latm/moleK

V = volume of gas = 20 L

Now put all the given values in the above equation, we get the mass of gas.

$197.6atm=(w)/(28g/mole)* (0.0821Latm/moleK* 301K)/(20L)$

$w=4477.8g$

Therefore, the mass of $N_2$ gas is, 4477.8 g

What is the mass (in grams) of 1.95 moles of water

Answers

Answer:

35.10 g is the mass of 1.95 moles of water.

Explanation:

Moles of water = 1.95 mol

Mass of 1 mol of water = 18 g

Then the mass of 1.95 moles of water:

Mass of 1.95 mol = $1.95* 18 g = 35.10 g$

35.10 g is the mass of 1.95 moles of water.

Given:
1.95 moles of H20

Required:
mass in grams

Solution:
The molar mass of water is 18.02 grams per mole

1.95 moles of water (18.02 grams / mole of water) = 35.1 grams of water

Which of these statements about mixtures is true?Mixtures are made up of elements bonded together.
Elements and compounds are types of mixtures.
Pure substances are made up of mixtures combined in specific ratios.
Mixtures are classified based on the distribution of particles in them.

Answers

Answer: Option (d) is the correct answer.

Explanation:

When two or more different substances are mixed together then it results in the formation of a mixture.

Mixture are of two types, that is, homogeneous mixture and heterogeneous mixture.

In homogeneous mixture, the constituent particles are distributed evenly throughout the mixture.

Whereas in heterogeneous mixture, the constituent particles are non-uniformly distributed.

Thus, we can conclude that mixtures are classified based on the distribution of particles in them.

The best answer from the choices would be the last option. Mixtures are classified based on the distribution of particles in them. The classification are called homogeneous and heterogeneous mixtures. The former type describes a mixture where all components are distributed evenly. The latter type is a mixture where the components do not have uniformity in the mixture.

SE DESEA OBTENER UNA SOLUCION 0.3 MOLARIDAD DE HIDROXIDO DE POTASIO DISOLVIENDO 60 GRAMOS DE HIDROXIDO -¿QUE VOLUMEN DE SOLUCION SE OBTENDRA QUIMICA

Answers

Answer:

3.56L will be the obtained volume

Explanation:

0.3 M → Molarity

These are the moles of solute (for this case, the solute is KOH) that are contianed in 1L of solution

We dissolved 60 g of solute, so let's determine the moles:

60 g . 1 mol/ 56.1 g = 1.07 moles

Molarity(mol/L) = Mol / Volume(L)

Let's replace data: 0.3M = 1.07 mol / Volume(L)

0.3 mol/L = 1.07 mol / volume

Volume = 1.07 mol / 0.3mol/L = 3.56 L

What is the best way to learn measurements and how to add and multipy them

Answers

Answer:

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Explanation:

Concentrated hydrogen peroxide solutions are explosively decomposed by traces of transition metal ions (such as Mn or Fe): 2H2O2(aq) ---> 2H2O(l) + O2(g)What volume of pure O2(g), collected at 27C and 746 torr, would be generated by decomposition of 125 g of a 50.0% by mass hydrogen peroxide solution?

Answers

Answer:

23.0733 L

Explanation:

The mass of hydrogen peroxide present in 125 g of 50% of hydrogen peroxide solution:

$Mass=\frac {50}{100}* 125\ g$

Mass = 62.5 g

Molar mass of $H_2O_2$ = 34 g/mol

The formula for the calculation of moles is shown below:

$moles = (Mass\ taken)/(Molar\ mass)$

Thus, moles are:

$moles= (62.5\ g)/(34\ g/mol)$

$moles= 1.8382\ mol$

Consider the given reaction as:

$2H_2O_2_((aq))\rightarrow2H_2O_((l))+O_2_((g))$

2 moles of hydrogen peroxide decomposes to give 1 mole of oxygen gas.

Also,

1 mole of hydrogen peroxide decomposes to give 1/2 mole of oxygen gas.

So,

1.8382 moles of hydrogen peroxide decomposes to give $\frac {1}{2}* 1.8382 mole of oxygen gas. Moles of oxygen gas produced = 0.9191 molGiven: Pressure = 746 torrThe conversion of P(torr) to P(atm) is shown below:[tex]P(torr)=\frac {1}{760}* P(atm)$