MATHEMATICS HIGH SCHOOL

5. What is a cubic polynomial function in standard form with zeros 1, –2, and 2? (1 point)= x3 + x2 – 3x + 4
= x3 + x2 – 4x – 2
= x3 + x2 + 4x + 4
= x3 – x2 – 4x + 4

Answers

Answer 1
Answer:

Answer:

Option D is correct

The cubic polynomial function in standard form is :

x^3-x^2-4x+4

Step-by-step explanation:

Given the zeroes of the polynomial function 1 , -2 and 2.

i.e,   x = 1 , -2 and 2  where x is the zero of the polynomial function.

we can write this as

x - 1 = 0,

x + 2 = 0 or

x - 2 = 0  

(x - 1)(x + 2)(x - 2) =0  

Using identities (a+b)(a-b) =a^2-b^2

then;

(x-1)(x^2-4)=0

Multiply the first term of the first expression with second expression;

x (x^2-4) =x^3-4x

also,

Multiply the second term of the first expression with second expression;

1(x^2-4) = x^2 -4

Now, subtract x^3-4x and x^2 -4

we get;

x^3-4x-x^2+4

then, we have;

x^3-x^2-4x+4=0

Cubic function is any function of the form y = ax^3 + bx^2 + cx + d, where a, b, c, and d are constants and a≠0

therefore, the given function is cubic function;

so, the cubic function f(x) = x^3-x^2-4x+4
Answer 2
Answer: Hello,

Answer D
(x-1)(x+2)(x-2)=(x-1)(x²-4)=x^3-x²-4x+4

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Answers

Answer:

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Hi iwas wonder what is the square root of 1,607,597,000

Answers

The square root of 1607597000 is 40094.85.

What is square root?

The square root of a number is a component of a number that yields the original number when multiplied by itself.

The given number is 1607597000.

The square root of the number is:

√1607597000

= 40094.85

Hence, the square root of 1607597000 is 40094.85.

Learn more about square roots:

brainly.com/question/3120622

#SPJ2
Hello,

n=1607597000

1607591<n/1000=1607597<1607603

n/1000 is prime

√n=10*√16075970 ≈40094,85004....

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Answers

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-2x. -2x
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X=-4

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Answers

Answer:

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A=12

Description:

The area of a triangle is A=1/2*b*h

Meaning the area of the triangle is 12.

A=1/2*(8)*(3)

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Please mark brainliest

Hope this helps.

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Answers

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Answers

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Answer:

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