Please help me determine the wedge/dash molecular structure, (R)-5,5-dibromo-3-fluoro-2-methyl-3-hexanol.

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Answer 1

Answer: lol this makes absolutly no sense in my mind, what do even half of the words mean? XD

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Fiona and Camilla took a load of peaches to the farmer’s market. During the first hour, they sold ½ of the peaches plus ½ of a peach. In the second hour, they sold 1/3 of the remaining peaches plus 1/3 of a peach. In the third hour, they sold ¼ of what was left plus ¾ of a peach. During the final hour, they sold 1/5 of the peaches that were left plus 1/5 of a peach. Fiona and Camilla went home with 19 whole peaches. How many peaches did they take to the market?
PLEASE HELP!Find the domain, period, range, and amplitude of the cosine function.y = -6 cos 4xA. domain = -1/2 ≤ x ≤ 1/2; period = 6; range:- -6 ≤ y ≤ 6; amplitude = 1/2 B. domain = all real numbers; period = π/2 ; range:- -6 ≤ y ≤ 6; amplitude = 6 C. domain = all real numbers; period = π/2 ; range: -6 ≤ y ≤ 6; amplitude = -6 D. domain = -1/2 ≤ x ≤ 1/2; period = 6π; range: -6 ≤ y ≤ 6 ; amplitude = 1/2
Anybody can help on anyone of these please quick !!!
If we divide the polynomial x4 + 4x3 + 2x2 + x + 4 by x2 + 3x, what will be the remainder?
Solve for x. −4/9 x 7=−71/8 x 9

A ball is thrown into the air with an upward velocity of 44 ft/s. Its height h in feet after t seconds is given by the function $h=-16t ^(2) +44t+9$ . What is the height of the ball after 2 seconds?

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$h=-16t^2+44t+9\n\nsubstitute\ t=2:\n\nh=-16\cdot2^2+44\cdot2+9=-16\cdot4+88+9=-64+97=33\n\nAnswer:33\ feets.$

$the\ function:\ \ h(t)=-16t^2+44t+9\n \n h=2\ \ \ \Rightarrow\ \ \ h(2)=-16\cdot 2^2+44\cdot 2+9=-16\cdot4+88+9=33\n \nAns.\ the\ height\ of\ the\ ball\ after\ 2\ seconds\ is\ 33\ feets$

Simplify this step by step
$(-5jk)/(35j^2k^2)$

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$\frac { -5jk }{ 35{ j }^( 2 ){ k }^( 2 ) } \n \n =-\frac { 5 }{ 35 } \cdot \frac { j }{ { j }^( 2 ) } \cdot \frac { k }{ { k }^( 2 ) } \n \n =-\frac { 1 }{ 7 } \cdot \frac { 1 }{ j } \cdot \frac { 1 }{ k } \n \n =-\frac { 1 }{ 7jk }$

Remember that:

$\frac { j }{ { j }^( 2 ) } =\frac { 1 }{ j } \cdot \frac { j }{ j } =\frac { 1 }{ j } \cdot 1=\frac { 1 }{ j } \n \n \frac { k }{ { k }^( 2 ) } =\frac { 1 }{ k } \cdot \frac { k }{ k } =\frac { 1 }{ k } \cdot 1=\frac { 1 }{ k }$

$(-5jk)/(35j^2k^2)=-(1)/(7jk)$

6r+7=13+7r
how do you solve this?

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Simplifying 6r + 7 = 13 + 7r Reorder the terms: 7 + 6r = 13 + 7r Solving 7 + 6r = 13 + 7r Solving for variable 'r'. Move all terms containing r to the left, all other terms to the right. Add '-7r' to each side of the equation. 7 + 6r + -7r = 13 + 7r + -7r Combine like terms: 6r + -7r = -1r 7 + -1r = 13 + 7r + -7r Combine like terms: 7r + -7r = 0 7 + -1r = 13 + 0 7 + -1r = 13 Add '-7' to each side of the equation. 7 + -7 + -1r = 13 + -7 Combine like terms: 7 + -7 = 0 0 + -1r = 13 + -7 -1r = 13 + -7 Combine like terms: 13 + -7 = 6 -1r = 6 Divide each side by '-1'.

Twelve less than the product of three and a number is less than 21.

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the answer is 11

11x3= 33

33-12=21

Determine whether the sequence converges or diverges. if it converges give the limit. 48, 12, 3, 3/4, ...

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The sequence converges.
The limit of the sequence is 0.

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This is a geometric sequence with the first term a = 48 and r = 1/4 = 0.25 as the common ratio. Since |r| < 1, this means that the terms are steadily getting smaller and smaller. The terms will approach 0 but not actually get there.

Note: if you added up all the terms of this infinite sequence, then the sum would be S = a/(1-r) = 48/(1-0.25) = 64

Wat does y2-y1 / x2-x1 have to do with sequences??!!

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It doesn't. That's the formula to calculate the gradient of a line (of the form y=mx+c).

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Simplify. |–4.1| = Thanks!

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Question 1 Which expression is the simplified form of the square root 150 times b cubed? 6 times b times the square root of 5 times b 5 times b times the square root of 6 6 times b times the square root of 5 5 times b times the square root of 6 times b