How many moles of I2 will form 3.58 g of NI3?

Answers

Answer 1
Answer:

1.       The balanced chemical reaction is:

 

N2 +3 I2 = 2NI3

 

We are given the amount of product formed. This will be the starting point of our calculations.

 

3.58 g NI3 ( 1 mol NI3 / 394.71 g NI3 ) ( 3 mol I2 / 2 mol NI3 ) = 0.014 mol I2.

 

Thus, 0.014 mol of I2 is needed to form the given amount of NI3.


Related Questions

In any redox reaction, the substance that undergoes reduction will(1) lose electrons and have a decrease in oxidation number(2) lose electrons and have an increase in oxidation number(3) gain electrons and have a decrease in oxidation number(4) gain electrons and have an increase in oxidation number
Write the balanced molecular equation and net ionic equation for the neutralization reaction between hydrochloric acid and strontium hydroxide. Include the phase of each species.
2H2 + O2 mc002-1.jpg 2H2O The number of moles of hydrogen that is needed to produce 0.253 mol of water is
Describe What are some possible benefits of single-stream recycling vs. regular recycling?
Glycerol boils at a higher temperature than water. What does this indicate about the attractive forces of glycerol?

Which of the following have the most similar properties?A. Sodium and Magnesium
B. Carbon and Silicon
C. Argon and Chlorine
D. Potassium and Calcium

I need help Plz. ASAP

Answers

Answer:

             Option-B (Carbon and Silicon)

Explanation:

                  Among the given pairs only carbon and silicon have the most similar properties. This is because,

Sodium and Magnesium belong to different groups. Sodium present in Group I has one electron in its valence shell and capable of transferring only one electron while, Magnesium present in Group II have two electrons in its valence shell and is capable of donating two electrons. Hence, both show different properties.

Example:

                                           2 Na  +  Cl₂    →     NaCl

                                           Mg  +  Cl₂    →    MgCl₂

As shown in reactions when Sodium and Magnesium are treated with Cl₂ they give a products with different proportions.

Carbon and Silicon show almost same properties because both belong to Group IV hence both are capable of forming four bonds. Also, they share the same property of self linkage in making a long chains.

Argon and Chlorine also belong to two different groups. Argon is present in Group VIII (Noble Gases) and Chlorine is present in Group VII (Halogens). Hence, Argon is an inert specie which is non reactive while Chlorine gives different reaction easily.

Potassium and Calcium belong to different groups. Potassium present in Group I has one electron in its valence shell and capable of transferring only one electron while, Calcium present in Group II have two electrons in its valence shell and is capable of donating two electrons. Hence, both show different properties.

Example:

                                           2 K  +  Cl₂    →     KCl

                                           Ca  +  Cl₂    →    CaCl₂

As shown in reactions when Potassium and Calcium are treated with Cl₂ they give a products with different proportions.

Andy is waiting at the signal. As soon as the light turns green, he accelerates his car at a uniform rate of 8.00 meters/second2. What is the displacement of Andy’s car after 30.0 seconds?

Answers

Answer:

7200 m

Explanation:

This problem is an example of an uniformly accelerated motion, in which the acceleration remains constant. As such, the formula for the displacement is:

D(t) = D₀ + v₀*t + 0.5*a*t²

Where D₀ is the initial displacement, v₀ is the initial velocity (in this case it's 0 m/s), a is the aceleration (8 m/s²) and t is the time, in seconds.

Using a t=30.0 s, we're left with:

D(t) = 0 m + 0 m/s * 30.0 s + 0.5 * 8.00 m/s² * (30.0 s)²

D(t) =  0.5 * 8.00 m/s² * (30.0 s)²

D(t) = 7200 m

1200 m/s squared, assuming the initial velocity is 0.

Which of the following would most likely act as a Bronsted-Lowry acid?

Answers

Answer:

HCN

Explanation:

answered right on edge

A Bronsted-Lowry acid is a proton donor (usually hydrogen ion). And a Bronsted-Lowry base is a proton acceptor (usually hydrogen ion). Consider a chemical reaction between HCl and NaOH. We have the reaction HCl + NaOH à NaCl + H2O. The hydroxide ions in the NaOH are bases because they accept hydrogen ions from acids to form water. And an acid produces hydrogen ions in solution by giving a proton to the water molecule. Therefore, the answer is d. a Bronsted-Lowry base.

Find the pH of the following solution. 1.2 L of a solution containing 5.0x10^-4 grams of hydrobromic acid.

Answers

The HBr is a strong acid, that is, it is fully consumed in the reaction

molar mass HBr = 80.91 g/mol

number of moles = 5.0 x 10⁻⁴ / 80.91 = 6.17 x 10⁻⁶ moles

molarity = 6.17 x 10⁻⁶ / 1.2 = 5.14 x 10⁻⁶ M

HBr -------------------  H
₃O⁺   +           Br ⁻
↓                                 ↓                     ↓
  5.14 x 10⁻⁶                0                     0
5.14 x 10⁻⁶             5.14 x 10⁻⁶   5.14 x 10⁻⁶ 
_____________________________________
0                             5.14 x 10⁻⁶ M         5.14 x 10⁻⁶ M

PH = - log [ H
₃O⁺ ]

PH = - log [ 5.14 x 10⁻⁶ ]

PH = 5.82

What are ionic compounds typically composed of?a metal anion and a nonmetal cation

two metal anions

a metal cation and a nonmetal anion

two nonmetal cations

Answers

ionic compounds are held together by ionic bonds are formed by the transfer of electrons from a metal to a non metal

Ionic bond is formed by the electrostatic attraction between the oppositely charged ions.

metals give out electrons and becomes positively charged. positively charged ions are called cations. so these are called metal cations

the electrons given out are taken in by non metals and become negatively charged. negatively charged ions are called anions. then they are called non metal anions.

so ionic compounds are formed by the electrostatic attraction between metal cations and non metal anions.

therefore ionic compounds are composed of a metal cation and a nonmetal anion

Ionic compounds are typically composed of a metal cation and nonmetal anion.

As the result of experimental work, a student finds the density of a liquid to be .137 g/ml. the known density of the liquid is .1478 g/ml. find the student's experimental error (ee) and percentage error (pe).

Answers

the known density of the liquid is

d_known = 0.1478 g /ml

the density of a liquid

d_calculated = 0.137 g /mol

experimental error = d_known – d_calculated

= 0.1478 – 0.137 = 0.0108 g /mL

Thus, experimental error of 0.0108 g /mL is present.


Percentage error = [ (d_known – d_calculated) / (d_known) ] * 100

=[ (0.0108) / 0.1478 ] * 100

= 7.31 %

Thus, Percentage error of 7.31 % is present.