Which is the equivalent of 750 joules? a. 0.750 kJ b. 7.50kJ c.75.0 kJ d. 750.kL

Answers

Answer 1
Answer: 1 kJ = 1000 J.
The equivalent of 750 joules is 0.750 kJ.

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When should you avoid looking directly at magnesium burning?

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Answer:

Magnesium also reacts with nitrogen in the air to produce some magnesium nitride (Mg3N2). Safety: Do not look directly at the burning magnesium due to the intensity of the light. A dry-powder fire extinguisher should be available. Disposal: Once cooled the solid magnesium products can be thrown in the trash.

Explanation:

How does the hydrogen atom produce light

Answers

when energy is put into an atom, the electrons can use the energy to go to a higher energy state (n value) which is called an exited state.  when the electron goes back down to where it started (called the ground state) it releases the energy it gained in the form of a photon which is why it produces light.  
A common way to get hydrogen gas to produce light is by passing an electric current through the sample.

How many primary oxygen systems are there? One Five Three Ten

Answers

The answer is three.
There are three type types of oxygen therapy system. The Compressed Oxygen Cylinders or commonly known as green tanks, the Oxygen Concentrators, and the Liquid Oxygen Systems. The type of oxygen system you need varies on the amount oxygen you need. 

The Haber process can be used to produce ammonia (NH3) from hydrogen gas (H2) and nitrogen gas (N2). The balanced equation for this process is shown below. 3H2 N2 Right arrow. 2NH3 The molar mass of NH3 is 17. 03 g/mol. The molar mass of H2 is 2. 0158 g/mol. In a particular reaction, 0. 575 g of NH3 forms. What is the mass, in grams, of H2 that must have reacted, to the correct number of significant figures? 0. 1 0. 102 0. 10209 0. 1021.

Answers

Answer:

B

Explanation:

We are given that ammonia can be produced from hydrogen gas and nitrogen gas according to the equation:

\displaystyle 3\text{H$_2$} + \text{N$_2$} \longrightarrow 2\text{NH$_3$}

We want to determine the mass of hydrogen gas that must have reacted if 0.575 g of NH₃ was produced.

To do so, we can convert from grams of NH₃ to moles of NH₃, moles of NH₃ to moles of H₂, and moles of H₂ to grams of H₂.

We are given that the molar masses of NH₃ and H₂ are 17.03 g/mol and 2.0158 g/mol, respectively.

From the equation, we can see that two moles of NH₃ is produced from every three moles of H₂.

With the initial value, perform dimensional analysis:

\displaystyle \begin{aligned} 0.575\text{ g NH$_3$}& \cdot \frac{1\text{ mol NH$_3$}}{17.03\text{ g NH$_3$}} \cdot\frac{3\text{ mol H$_2$}}{2\text{ mol NH$_3$}} \cdot \frac{2.0158\text{ g H$_2$}}{1\text{ mol H$_2$}} \n \n & = 0.102\text{ g H$_2$}\end{aligned}

*Assuming 100% efficiency.

Our final answer should have three significant figures. (The first term has three, the second term has four (the one is exact), the third term is exact, and the fourth term has five. Hence, the product should have only three.)

In conclusion, our answer is B.

Technician A says that a soldering gun must be energized for several minutes before it warms up to the melting point of solder. Technician B says that a soldering torch is heated by burning butane gas. Who is right

Answers

Answer:

Both are right

Explanation:

A constant heat must be supplied for several minutes to soldering gun to overcome the melting point of solder. A butane torch is a type of soldering device powered (energised) by the burning of butane gas to melt and solder common metals

A gas is initially at a pressure of 225 kPa and a temperature of 245 K in a container that is 4.5 L. If the gas is compressed to a volume of 2.1 L and the temperature changes to 275 K, what is the new pressure?

Answers

Use the ideal gas equation PV=nRT. You can compare before and after using P1V1/n1T1=P2V2/n2T2. Since the number of moles remains constant you can disregard moles from the equation and use pressure, volume and temp. Make sure your pressure is converted to atmospheres, your volume is in liters, and your temperature is in kelvins.