It's urgent. I need help to know the oxidation numbers and what is the oxidation and reduction part of this equation Fe + H2SO4= Fe2(SO4)3 + H2

Answers

Answer 1
Answer: In the given equation: Fe + H2SO4 = Fe2(SO4)3 + H2

To determine the oxidation numbers, we assign oxidation numbers to each element in the equation.

1. Fe: The oxidation number of Fe is 0 since it is in its elemental form.

2. H2SO4:
- H has an oxidation number of +1.
- S has an oxidation number of +6 since it is in the sulfate ion (SO4)2-.
- O has an oxidation number of -2.

3. Fe2(SO4)3:
- Fe has an oxidation number of +3 since it is in the Fe2+ ion.
- S has an oxidation number of +6 since it is in the sulfate ion (SO4)2-.
- O has an oxidation number of -2.

4. H2:
- H has an oxidation number of 0 since it is in its elemental form.

Now, let's analyze the oxidation and reduction parts of the equation:

Oxidation: Fe is oxidized from an oxidation number of 0 to +3 in Fe2(SO4)3.

Reduction: H2SO4 is reduced. The sulfur (S) in H2SO4 goes from an oxidation number of +6 to +4 in Fe2(SO4)3, and the hydrogen (H) in H2SO4 goes from an oxidation number of +1 to 0 in H2.

Overall, in this equation, Fe is oxidized, and H2SO4 is reduced.

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Use the ideal gas law to calculate the pressure in atmospheres of 0.21 mol of helium (He) at 16°C & occupying 2.53 L. You must show all of your work to earn credit. **Don't forget to convert your Celsius temperature to Kelvin***picture attached !!*

Answers

Answer:

The answer to your question is 2.32 atm

Explanation:

Data

P = ?

n = 0.214

V = 2.53 L

T = 61°C

R = 0.082 atm L/mol°K

Formula

PV = nTR

solve for P

P = nRT/V

Process

1.- Calculate the temperature in K

°K = °C + 273

°K = 61 + 273

    = 334

2.- Substitution

P = (0.214 x 0.082 x 334) / 2.53

3.- Simplification

P = 5.86/2.53

4.- Result

P = 2.32 atm

Which of the following is not an acid-base neutralization reaction? (3 points)NH3 + HCl yields NH4Cl

NaOH + CH3COOH yields Na CH3COO + H2O

2HNO3 + Ca(OH)2 yields Ca(NO3)2 + 2H2O

H2SO4 + 2NaCl yields 2HCl + Na2SO4

Answers

fourth option...
H2SO4 + 2NaCl yields 2HCl + Na2SO4


is the correct answer...
because neutralisation reaction yields salt n water but here acid is produced so the solution isn't neutralized......



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what is the molarity of a concentrated hbr solution if the solution is 27.7% hbr by mass and has a density of 1.24 g/ml

Answers

The final answer is 4.246 Molar. For a given volume of the solution, let's say 100mL, the following calculations can be made:

Given:
Molar Mass HBr = 80.904g/mol
Density solution = 1.24 g/mL
27.7%(wt/wt) HBr


Total mass of solution = volume(density) = 100mL (1.24 g/mL) = 124 g solution

Mass HBr in solution = 124g(0.277) = 34.348 g HBr

Moles HBr in solution = 34.348/80.904 = 0.4246 moles HBr

Molarity = moles solute/L solution = 0.4246 moles HBr/0.1 L solution
Molarity = 4.246 M

Which organic reaction produces rubber and plastics? A) polymerization B) esterification C) saponification D) fermentation

Answers

Answer: Option (A) is the correct answer.

Explanation:

When monomers in a chemical reaction combine together then it results in the formation of long chains. This process is known as polymerization.

For example, rubber and plastic are formed by polymerization.

Esterification is defined as a process in which esters are formed when an acid is heated with alcohol.

Saponification is defined as a process in which aqueous alkali is heated with a fat or oil resulting in the formation of a soap.

Fermentation is a process in which bacteria like microorganisms, yeast etc help in the breakdown of a substance into simpler substances.

Thus, we can conclude that polymerization is an organic reaction which produces rubber and plastics.

The answer would be, A) Polymerization.


What prefix is used to indicate that the main chain of a hydrocarbon contains four carbon atoms?

Answers

The prefix is used to indicate that the main chain of a hydrocarbon contains four carbon atoms is "but-". Examples of carbon compounds with four carbons in the main chain are: butane, butanol, butyl, butene, etc. It can be observed that all of the compounds have a common prefix of "but".

What part of a divers body is most effected by pressure?

Answers

The lungs are most affected by the pressure.
It makes breathing difficult pressure get higher and it compresses the diver's lungs.