Name three human activities that are changing the natural world. Why do these activities make it important to understand evolution?

Answers

Answer 1

Answer: The three human activities that are changing the natural world are:
1. Deforestation. Cutting of trees results to the endangered habitats of animals and the soil compaction is becoming less and less.
2. Hunting. Killing animals mercilessly and selling them off reduces their numbers and increase the fear of humans
3. Genetic engineering. Modifying the cell structure of a plant or animal increases possible risk of cancer, toxicity in the soil and others.

Answer 2

Answer:

Habitat degradation and fragmentation, introduction of exotic species and over harvesting.

These activities disrupt the natural function of a variety of species.

Humans must understand evolution to assess the effect these activities can have on various species and the environment

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A moving company is called into a building and asked to relocate 520 bricks to a location 15 meters above the ground. If each brick is 4 kilograms, what amount of work will be needed to accomplish the task? A. 305,760 J B. 229,320 J C. 203,840 J D. 588,000 J

Answers

Work = Force * distance (aka Weight * height lifted)

Work to lift 1 brick:
W = mgh = (4 kg)(9.8 m/s²)(15 m) = 588 J

Work to lift 520 bricks:
W = 520(588 J) = 305,760 J

I just took the test, the answer is A. 305,760 J, good luck.

How is an average mass different from a weighted average mass?

Answers

The weighted average mass of the atoms in a naturally occurring sample of an element is the average atomic mass, also known as atomic weight.

What is atomic mass?

The average mass of an element's atoms expressed in atomic mass units is known as its atomic mass (amu, also known as daltons, D).

The mass of each isotope is multiplied by its abundance to produce the atomic mass, which is a weighted average of all the isotopes of that element.

Any element has a variety of isotopes, thus to take into consideration the fact that each isotope has a different mass, a weighted average mass is used.

A weighted average takes into account the potential that an element's average mass, as calculated from a random sample, will most likely coincide with the average mass of its more common isotopes.

The weighted average masswill therefore be closest to that of the more prevalent isotopes.

To learn more about Atomic mass, refer to the below link:

brainly.com/question/13058602

# SPJ2

With any element, there are a range of isotopes . . . a weighted average mass is used because there exist different isotopes of that element, each of varying mass. A weighted average accounts for the fact that the average mass (that may likely be measured from a random sample of the element) will most likely reflect the average mass of the more abundant isotopes. So the weighted average mass will be most comparable to the more abundant isotopes.

Who is wise president of india?
________________________

Answers

The vise president of India is M. Venkaiah Naidu

A gas at 255 kilopascals and 45°C has an initial volume of 2.00L. The pressure of the gas increases to 805 kilopascals as the temperature is raised to 255°C. What will be the new volume?1.05 liters
2.28 liters
1.25 liters
0.44 liters
1.50 liters

Answers

Answer : The correct option is, (a) 1.05 liters

Solution :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$(P_1V_1)/(T_1)=(P_2V_2)/(T_2)$

where,

$P_1$ = initial pressure of gas = 255 kpa

$P_2$ = final pressure of gas = 805 kpa

$V_1$ = initial volume of gas = 2 L

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $45^oC=273+45=318K$

$T_2$ = final temperature of gas = $255^oC=273+255=528K$

Now put all the given values in the above equation, we get the final volume of gas.

$(255kpa* 2L)/(318K)=(805kpa* V_2)/(528K)$

$V_2=1.05L$

Therefore, the final or new volume of gas will be, 1.05 liters

The amount of oxygen formed when 12.26 g of KClO3 is heated is ________.

Answers

Answer:

approximately 4.8 grams of oxygen gas is formed.

Explanation:

To determine the amount of oxygen (O2) formed when 12.26 grams of potassium chlorate (KClO3) is heated, we need to consider the chemical reaction that occurs during this process. When KClO3 is heated, it decomposes into potassium chloride (KCl) and oxygen gas (O2).

The balanced chemical equation for this reaction is:

2 KClO3(s) → 2 KCl(s) + 3 O2(g)

From the equation, we can see that 2 moles of KClO3 produce 3 moles of O2.

Calculate the molar mass of KClO3:

K: 39.10 g/mol

Cl: 35.45 g/mol

O: 16.00 g/mol

Molar mass of KClO3 = (39.10 + 35.45 + 3 * 16.00) g/mol = 122.55 g/mol

Calculate the number of moles of KClO3 in 12.26 grams:

Moles of KClO3 = (12.26 g) / (122.55 g/mol) = 0.1 moles

Now, we can determine the number of moles of O2 produced using the mole ratio from the balanced equation:

Moles of O2 = (0.1 moles of KClO3) * (3 moles of O2 / 2 moles of KClO3) = 0.15 moles

Finally, convert moles of O2 to grams:

Mass of O2 = (0.15 moles) * (32.00 g/mol for O2) = 4.8 grams

So, when 12.26 grams of KClO3 is heated, approximately 4.8 grams of oxygen gas is formed.

Calculate the percentage of yield when 20 grams of sodium chloride solution reacts with an excess amount of silver nitrate solution knowing that 45 grams of silver chloride precipitated