This formula equation is unbalanced.P4(s) + Cl2(g)  PCl3(l) 

Which coefficient should be placed in front of PCl3 to balance this equation?
1246

Answers

Answer 1
Answer:

 In order to balance this, you have to count each element where the elements in the reactants side and the product side should have equal number of molecules. The balanced reaction is as follows:

P4(s) + 6Cl2(g) =  4PCl3(l) 

Thus, the answer is 4.

 


Answer 2
Answer:

Answer:

4

Explanation:

I got it right on edge


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Solid aluminum and gaseous oxygen react in a combination reaction to produce aluminum oxide: In a particular experiment, the reaction of 2.5 g of Al with 2.5 g of O2 produced 3.5 g of Al2O3. The % yield of the reaction is __________.

Answers

Answer:

The % yield of the reaction is 73.8 %

Explanation:

To solve this, we list out the given variables thus

Mass of aluminium in the experiment = 2.5 g

mass of oxygen gas in the experiment = 2.5 g

Molar mass of aluminium = 26.98 g/mol

molar mass of oxygen O₂ = 32 g/mol

The reaction between aluminium and gaseous oxygen can be written as follows

4Al + 3O₂ → 2Al₂O₃

Thus four moles of aluminium forms two moles of aluminium oxide

Thus (2.5 g)÷(26.98 g/mol) = 0.093 mole of aluminium and

(2.5 g)÷(32 g/mol)  = 0.078125  moles of oxygen

However four moles of aluminium react with three moles of oxygen gas O₂

1  mole of aluminum will react with 3/4 moles of oxygen O₂ and 0.093 mole of aluminium will react with 0.093*3/4 moles of O₂ = 0.0695 moles of Oxygen hence aluminium is the limiting reagent and we have

1 mole of oxygen will react with 4/3 mole of aluminium

∴ 0.078125 mole of oxygen will react with 0.104 moles of aluminium

Therefore 0.093 mole of aluminium will react with O₂ to produce 2/4×0.093 or 0.0465 moles of  2Al₂O₃

The molar mass of 2Al₂O₃ = 101.96 g/mol

Hence the mass of 0.0465 moles = number of moles × (molar mass)

= 0.0465 moles × 101.96 g/mol = 4.74 g

The  of aluminium oxide Al₂O₃ is 4.74 g, but the actual yield = 3.5 g

Therefore the Percentage yield = (actual yield )/(theoretical yield) ×100 = (3.5)/(4.74) × 100 = 73.8 % yield

Methane (CH4, 16.05 g/mol) reacts with oxygen to form carbon dioxide (CO2, 44.01 g/mol) and water (H2O, 18.02 g/mol). Assume that you design a system for converting methane to carbon dioxide and water. To test the efficiency of the system in the laboratory, you burn 5.00 g methane. The actual yield is 6.10 g water. What is your percent yield?

Answers

Answer:

The percent yield of reaction is 54.32%.

Explanation:

CH_4+3O_2\rightarrow CO_2+2H_2O

Moles of methane = (5.00 g)/(16.05 g/mol)=0.3115 mol

According to reaction, 1 mole of methane gives 2 moles of water .

The 0.3115 moles of methane will give:

(2)/(1)* 0.3115 mol=0.623 mol of water

Mass of 0.9345 moles of water = 0.623 mol × 18.02 g/mol = 11.23 g.

Theoretical yield of methane = 11.23 g.

Experimental yield of methane = 6.10 g.

The percent yield of reaction:

\%(Yield)=\frac{\text{Experimental yield}}{\text{Theoretical yield}}* 100

The percent yield of reaction is :

\%(Yield)=(6.10 g )/(11.23 g)* 100=54.32\%

Answer:54.5

Explanation:

5. This lab examines the relationship between the density of a beverage and its sugar content. What assumption is madeconcerning the other ingredients in the beverage and their effect on its density? Is this a valid assumption? Why or why
not?

Answers

The characteristics of the density we can find that the answer for the effect of sugar is;  

  • Densityincreases with increasing amount of sugar,
  • The other costituents is not reaction with the sugar.

Density is the relationship between the mass and the volume of a body, this is a very useful relationship for fluid mechanics exercise.

                 \rho = (m)/(V)

Where ρ is the density, m the mass and V the volume

In this laboratory the liquid is possibly water since a solution is formed with the sugar, the volume of the solution does not change with the introduction of the solute (sugar), therefore the introduction of sugar creates a change in the mass of the solution.

Consequently, if the mass increases and the volume remains constant, the density should increase, possibly in a linear fashion with increasing mass.

The most important assumption is that the effect of the other ingredients of the drink is that it does not react with the sugar.

In conclusion using the density characteristics we find that the response for the sugar effect is;

  • Density increases with increasing amount of sugar, assuming that there is no reaction between the sugar and the other constituents of the solution.

Learn more about density here:

brainly.com/question/14940265

Final answer:

The assumption is that other ingredients do not noticeably affect the density of the beverage, and changes in density are attributed solely to sugar content. The validity of this assumption would depend on various factors such as the densities and quantities of the other ingredients.

Explanation:

The assumption in this lab is that the other ingredients in the beverage do not significantly impact its density. This would imply that the changes in density observed are due solely to the sugar content. The validity of this assumption would depend on several factors. For instance, if the other elements are in relatively small quantities, or their densities are similar to that of the primary component (water in most beverages), the assumption may hold true. Nonetheless, it's important to point that this is an approximation, as in reality, every ingredient may contribute to the overall density.

Learn more about Density-Sugar Relationship here:

brainly.com/question/30493160

#SPJ3

What is the Celsius temperature of 1 mole of a gas that has an average kinetic energy of 3,866 joules?

Answers

Temperature can be calculated using the average kinetic energy. The ideal gas equation is being related to the average molecular kinetic energy.

PV = nRT
PV = (2/3) N(0.5mv^2)

By substituting and simplifying, we eventually get the equation.

KE = (3/2)RT

T = 3866 x 2 / 8.3145 x 3 = 309.98 K or 36.83 degrees Celsius

Which element has the greatest density at STP?(1) scandium (3) silicon
(2) selenium (4) sodium

Answers

Answer:

            Selenium has the greatest density at STP.

Explanation:

                   According to Ideal gas equation,

                                                P V  =  n R T

where;

             n =  m/M

Therefore,

                                                P V  =  m R T / M

Rearranging,

                                                P M  =  (m/V) R T

Also,

             m/V  =  density  = d

So,

                                                P M  =  d R T

Solving for density,

                                                d  =  P M / R T

According to this equation density is directly proportional to Molar mass of a substance. Hence, the Atomic masses of given compounds are listed below,

                                                Scandium =  44.96 g.mol⁻¹

                                                Selenium  =  78.97 g.mol⁻¹

                                                Silicon  =  28.09 g.mol⁻¹

                                                Sodium  =  22.99 g.mol⁻¹

Therefore, selenium having the greatest Atomic Mass will have the greatest density. The densities of given elements are as follow;

                                                Scandium =  2.98 g.cm⁻³

                                                Selenium  =  4.81 g.cm⁻³

                                                Silicon  =  2.33 g.cm⁻³

                                                Sodium  =  0.96 g.cm⁻³

\boxed{\left( 2 \right){\text{ Selenium}}}  has the greatest density at STP.

Further Explanation:

Ideal gas law is the equation of state for any hypothetical gas. The expression for the ideal gas equation is as follows:

{\text{PV}} = {\text{nRT}}               …… (1)                                                                

Here,

P is the pressure.

V is the volume.

T is the absolute temperature.

n is the number of moles.

R is the universal gas constant.

The formula to calculate the number of moles is as follows:

{\text{n}}=\frac{{\text{m}}}{{\text{M}}}        ...... (2)                                                                              

Here,

n is the number of moles.

m is the mass.

M is the molar mass.

Substitute the value of n from equation (2) in equation (1).

{\text{PV}} = \frac{{{\text{mRT}}}}{{\text{M}}}      …… (3)                                                        

Rearrange equation (3) as follows:

{\text{PM}} = \frac{{{\text{mRT}}}}{{\text{V}}}      …… (4)

                                                       

The formula to calculate density is as follows:

{\rho }} = \frac{{\text{m}}}{{\text{V}}}     ...... (5)                                                                                    

Here,

{\rho }} is the density.

m is the mass.

V is the volume.

Substitute equation (5) in equation (4).

{\text{PM}} = \rho{\text{RT}}      …… (6)                                                                      

Rearrange equation (6) to calculate the density.

{\rho }} = \frac{{{\text{PM}}}}{{{\text{RT}}}}     ...... (7)                                                                      

At STP, T and P remain constant, R is already a constant. So according to equation (7), density of substance is directly proportional to the molar mass of the substance.

The molar mass of scandium is 44.96 g/mol.

The molar mass of selenium is 78.97 g/mol.

The molar mass of silicon is 28.09 g/mol.

The molar mass of sodium is 22.99 g/mol.

The molar mass of selenium is the highest among the given elements so its density will be the greatest.

Learn more:

1. Which statement is true for Boyle’s law: brainly.com/question/1158880

2. Calculation of volume of gas: brainly.com/question/3636135

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Ideal gas equation

Keywords: P, V, n, R, T, ideal gas, pressure, volume, selenium, sodium, scandium, silicon, 22.99 g/mol, 78.97 g/mol, 28.09 g/mol, 44.96 g/mol, density, molar mass.

A sample of 0.3257 g of an ionic compound containing the bromide ion (Br−) is dissolved in water and treated with an excess of AgNO3. If the mass of the AgBr precipitate that forms is 0.7165 g, what is the percent by mass of Br in the original compound?

Answers

Answer:

Explanation:

Given parameters:

Mass of ionic compound = 0.3257g

Mass of AgBr precipitate = 0.7165g

Unknown:

Percent mass of Br in the original compound.

Solution

The percent mass of Br in original compound = (mass of  Br  in the sample)/(mass of sample)

Now we have to find the mass of Br⁻:

We must note that the same mass of Br⁻ would move through the ionic sample to form the precipitate.

Mass of Br in AgBr = (Atomic mass of Br)/(Molar mass of AgBr)  x mass of precipitate

Mass of Br =  (80)/(80 + 108)  x 0.7165

Mass of Br = 0.426 x 0.7165 = 0.305g

Percent mass of Br = (0.305)/(0.3257) x 100 = 93.7%