C6H14 has a boiling point than C11H24.

Answers

Answer 1

Answer: The correct statement to complete the thought of the sentence is "lower boiling point". C6H14 or hexane has a lower boiling point than C11H24 since hexane has lower number of atoms than the latter. Lower number of atoms means less bond which results to lower bonds to break.

Answer 2

Answer:

C6H14 has a lower boiling point than C11H24.

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The mass of 69Ga is 68.7200 amu . The mass of 71Ga is 70.9200 amu .

Answers

I'm not sure if what this question is asking but ill be assuming that the average molecular mass is required. An assuming that the abundance of each isotope is 50% the average molecular mass is 69.82 amu.

12. A salt used as a fertiliser has the empirical formula H4N2O3.Suggest the formulae of the ions present in this salt

Answers

Final answer:

The formula H4N2O3 represents a salt containing ammonium (NH4+) and nitrate (NO3-) ions. These ions are often present in fertilisers because they effectively deliver nitrogen to plants.

Explanation:

The empirical formula H4N2O3 represents a salt used in fertilisers and it contains hydrogen, nitrogen, and oxygen. In this salt, the ions present are the ammonium ion (NH4+) and the nitrate ion (NO3-). Hydronium and nitrogen dioxide might also be present in the compound. However, the most relevant ions are generally the ammonium and the nitrate ions, because they are often used in fertilizers due to their abilities to effectively deliver nitrogen to plants.

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The empirical formula H4N2O3 suggests that in this salt, there are two nitrogen (N) atoms, three oxygen (O) atoms, and four hydrogen (H) atoms. To determine the formulae of the ions present, we can consider that hydrogen usually forms H+ ions, while nitrogen can form N3- ions, and oxygen can form O2- ions.

Based on this, the formulae of the ions present in this salt could be:

- Cation: H+
- Anions: N3- and O2-

So, the salt might consist of H+ cations and a combination of N3- and O2- anions, depending on the specific compound.

Balance this equation please.

Answers

2K + 2H2O = 2KOH + H2

2K + 2H2O = 2KOH + H2 Actually Really what That other guy said

An anvil-shaped heard is a feature of a mature thunderstorm : true false

Answers

True! The anvil is a surefire sign of a mature thunderstorm

A liquid mixture in which particles can be seen and easily separated by settling or filtration is aa. solution.
b. suspension.
c. solvent.
d. solute.

Answers

The answer for this statement is letter B. suspension. The liquid mixture in which particles can be seen and easily separated by settling or filtration is a suspension.

Answer:

suspension

Explanation:

Calculate the volume of each of the following gases at STP 7.6 mol Ar 0.44 mol C2,H3

Answers

For Ar :

1 mol ------------ 22.4 L ( at STP )
7.6 mol ---------- x L

x = 7.6 * 22.4

x = 170.24 L
-----------------------------------------------------------------
For C2H3:

1 mol ------------ 22.4 ( at STP)
0.44 mol --------- y L

y = 0.44 * 22.4

y = 9.856 L

hope this helps !.

The volume of 0.44 moles of ethylene gas at STP is approximately 10.33 liters.

To calculate the volume of gases at Standard Temperature and Pressure (STP), we can use the ideal gas law:

PV = nRT

Where:

P = Pressure (at STP, it's 1 atmosphere, or 1 atm)

V = Volume (in liters)

n = Number of moles

R = Ideal gas constant (0.0821 L·atm/mol·K)

T = Temperature (at STP, it's 273.15 K)

Let's calculate the volume for each gas:

For 7.6 moles of Ar (argon):

P = 1 atm

n = 7.6 moles

R = 0.0821 L·atm/mol·K

T = 273.15 K

Now, plug these values into the ideal gas law:

V = (nRT) / P

V = (7.6 moles * 0.0821 L·atm/mol·K * 273.15 K) / 1 atm

V ≈ 172.75 liters

So, the volume of 7.6 moles of argon gas at STP is approximately 172.75 liters.

For 0.44 moles of C2H3 (ethylene):

P = 1 atm

n = 0.44 moles

R = 0.0821 L·atm/mol·K

T = 273.15 K

Now, plug these values into the ideal gas law:

V = (nRT) / P

V = (0.44 moles * 0.0821 L·atm/mol·K * 273.15 K) / 1 atm

V ≈ 10.33 liters

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