Propanone is more soluble in water compared to 3 hexanol mainly because the propanone?

Answers

Answer 1

Answer:

Propanone is more soluble in water compared to propane mainly because propanone cannot hydrogen bond with themselves but can hydrogen bond with water molecules. One of the slightly positive hydrogen atoms in a water molecule can be sufficiently attracted to one of the lone pairs on the oxygen atom of propanone. In order for 3-hexanol to bond with water, the van der Waals forces must be broken and also the stronger hydrogen bonds of water molecules and it needs a great amount of energy.

Related Questions

Plz solve this i need helpprozac C17H18F3NO is a widely used antidepresent that inhibits the uptake of sertonin by the brain. how many molecules are in 3 grams of prozac?
What would most likely be included in the “Analysis” section of a lab report?
Which statement correctly describes whether a compound is a pure substance? A compound is not a pure substance because each of its molecules is made up of the atoms of two or more different elements. A compound is a pure substance because its molecule cannot be broken down into simpler particles by physical means. A compound is not a pure substance because it is not an element, and only elements are pure substances. A compound is a pure substance because it consists of two different elements, which are pure substances.
A camcorder has a power rating of 16 watts. If the output voltage from its battery is 8 volts, what current does it use?
when a log of wood burns, it undergoes a _______. a. physical change. b. chemical change. c. physical and a chemical change. d. no physical or chemical change.

What is the difference in the beginning between primary succession and secondary succession?a. secondary succession has water
b. secondary succession has soil
c. primary succession has soil
d. primary succession has water

Answers

Option B. secondary succession has soil

What turns colour in an acid and base

Answers

Answer:

Chemists use a solution called Universal Indicator to identify acids and bases. ... The Universal Indicator Color Guide shows that Universal Indicator turns red when it is added to a strong acid, it turns purple when it is added to a strong base, and it turns a yellowish-green when it is added to a neutral solution.

Explanation:

Answer:

Phenolphthalein

Explanation:

Enzymes are proteins that speed up chemical reactions in the body how do they workA. they increase the surface area of reactants
B.they increase the concentration of reactants
C.they decrease the concentration of products
D. They act as reactants

Answers

The answer would be D, Enzymes are soluble protein molecules that can speed up chemical reactions in cells. These reactions include respiration, photosynthesis and making new proteins. For this reason enzymes are sometimes called biological catalysts.

Answer:

D) They act as reactants

Explanation:

I took the test.

Hope this helps!!

Explain, in terms of electron configuration, why oxygen atoms and sulfur atoms form compounds with similar molecular structures

Answers

Oxygen atoms and sulfur atoms form compounds with similar molecular structures because if you look at these two, they both have six electrons in their valence shells. Therefore, they will generally react in much the same manner. I hope this helps you on your assignment.

Use electron transfer or electron shift to identify what is oxidized and what is reduced in each reaction :a) 2Na(s) + Br2(l) ----> 2NaBr(s)
b) H2(g) + Cl2(g) ----> 2HCl(g)
c) 2Li(s) + F2(g) ----> 2LiF(s)
d) S(s) + Cl2(g) ----> SCl2(g)
e)N2(g) + 2O2(g) ----> 2NO2(g)
f) Mg(s) +Cu(NO3)2(aq) = Mg(NO3)2(aq) + Cu(s)

For each reaction above, identify the reducing agent and the oxidizing agent

Answers

Answer :

Oxidation-reduction reaction : It is a type of reaction in which oxidation and reduction reaction occur simultaneously.

Oxidation reaction : It is the reaction in which a substance looses its electrons. In the oxidation reaction, the oxidation state of an element increases.

Reduction reaction : It is the reaction in which a substance gains electrons. In the reduction reaction, the oxidation state of an element decreases.

(a) The balanced chemical reactions is,

$2Na(s)+Br_2(l)\rightarrow 2NaBr(s)$

Half reactions of oxidation and reduction are :

Oxidation : $Na\rightarrow Na^(1+)+1e^-$

Reduction : $Br_2+2e^-\rightarrow 2Br^(1-)$

From this we conclude that, 'Na' is oxidized and $'Br_2'$ is reduced in this reaction. The reducing agent is, 'Na' and oxidizing agent is, $'Br_2'$ .

(b) The balanced chemical reactions is,

$H_2(g)+Cl_2(g)\rightarrow 2HCl(g)$

Half reactions of oxidation and reduction are :

Oxidation : $H_2\rightarrow H^(1+)+1e^-$

Reduction : $Cl_2+2e^-\rightarrow 2Cl^(1-)$

From this we conclude that, $'H_2'$ is oxidized and $'Cl_2'$ is reduced in this reaction. The reducing agent is, $'H_2'$ and oxidizing agent is, $'Cl_2'$ .

(c) The balanced chemical reactions is,

$2Li(s)+F_2(g)\rightarrow 2LiF(s)$

Half reactions of oxidation and reduction are :

Oxidation : $Li\rightarrow Li^(1+)+1e^-$

Reduction : $F_2+2e^-\rightarrow 2F^(1-)$

From this we conclude that, 'Li' is oxidized and $'F_2'$ is reduced in this reaction. The reducing agent is, 'Li' and oxidizing agent is, $'F_2'$ .

(d) The balanced chemical reactions is,

$S(s)+Cl_2(g)\rightarrow SCl_2(g)$

Half reactions of oxidation and reduction are :

Oxidation : $S\rightarrow S^(2+)+2e^-$

Reduction : $Cl_2+2e^-\rightarrow 2Cl^(1-)$

From this we conclude that, 'S' is oxidized and $'Cl_2'$ is reduced in this reaction. The reducing agent is, 'S' and oxidizing agent is, $'Cl_2'$ .

(e) The balanced chemical reactions is,

$N_2(g)+2O_2(g)\rightarrow 2NO_2(g)$

Half reactions of oxidation and reduction are :

Oxidation : $N_2\rightarrow N^(4+)+4e^-$

Reduction : $O_2+4e^-\rightarrow 2O^(2-)$

From this we conclude that, $'N_2'$ is oxidized and $'O_2'$ is reduced in this reaction. The reducing agent is, $'N_2'$ and oxidizing agent is, $'O_2'$ .

(f) The balanced chemical reactions is,

$Mg(s)+Cu(NO_3)_2(aq)\rightarrow Mg(NO_3)_2(aq)+Cu(s)$

Half reactions of oxidation and reduction are :

Oxidation : $Mg\rightarrow Mg^(2+)+2e^-$

Reduction : $Cu^(2+)+2e^-\rightarrow Cu$

From this we conclude that, $'Mg'$ is oxidized and $'Cu'$ is reduced in this reaction. The reducing agent is, 'Mg' and oxidizing agent is, 'Cu'.

a) Na is oxidised Br is reduced
b) H is oxidised Cl is reduced
c) Li is oxidised F is reduced
d)S is oxidised Cl is reduced
e) N is oxidised O is reduced
f) Mg is oxidised and N is reduced

Remember: Oxidation= loss and Reduction= gains

According to the periodic table, which statement correctly describes the change from a neutral atom of an element to its ion?

Answers

According to the periodic table, a sodium atom forms $Na^+^1$ ion by losing two electrons correctly describes the change from a neutral atom of an element to its ion.

What is a neutral atom?

A neutral atom is an atom where the charges of the electrons and the protons balance.

Atomic number 11.

Mass number 23.

Na Electron arrangement 2, 8 , 1 Will lose 1 electron to gain a full valence shell.

Since now 11 + and 10 –, the overall charge is 1+ So we write $Na^+^1$ or simply $Na^+$ .

Learn more about the neutral atom here:

brainly.com/question/5308494

#SPJ2

A sodium atom forms Na1+ ion by losing two electrons

Other Questions

The rate law for a reaction is rate = k[A]2. What is the overall order of this reaction, and which two varaibles, when graphed, will give a straight line for this reaction? A. first order, In[A]t versus t B. first order, 1/[A]t versus t C. second order, In[A]t versus t D. second order, 1/[A]t versus t

What happens in a reduction half-reaction?elements gain electronselements lose electronsoxygen is addedoxygen is lost

chlorine and element x have similar chemical properties an atom of element x could have an electron configuration of

If you travel from the Earth to the moon, which of the following measurements would change? Mass Weight Density Size