MATHEMATICS HIGH SCHOOL

If a point is on the perpendicular bisector of a segment, then it is:A. the midpoint of the segment.
B. equidistant from the endpoints of the segment.
C. equidistant from the midpoint and one endpoint of the segment.
D. on the segment.

Answers

Answer 1
Answer: To create a perpendicular bisector of a segment, it is a line drawn through the midpoint of the segment. Although one would immediately think that (A) would be the answer, just because a point is found on the perpendicular bisector, doesn't mean that it is immediately the midpoint. Although the midpoint is definitely found on the segment, there are numerous other points found on the segment. The midpoint is a point equidistant to both endpoints. Since the bisector passes through the midpoint, then any point on the bisector is equidistant to both endpoints. Therefore, the correct answer is B.
Answer 2
Answer:

Answer:

B

Step-by-step explanation:

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Solve for x 5 x − 9 = 3 x + 3

Answers

5x-9 = 3x+3

2x-9 = 3

2x = 12

x= 6

plz mark branliest, hopoe this helps :)

I need confirmation to this. I did it already. I just want to know if I’m right. Please work it out for me to see.

Answers

(a)

4x + 3y = 23

5x + 2y = 20

(b)

4x + 3y = 23   ⇒   -2(4x + 3y = 23)   ⇒    -8x - 6y = -46

5x + 2y = 20   ⇒    3(5x + 2y = 20)   ⇒   15x + 6y = 60

                                                                 7x          = 14

                                                                   x          = 2

5x + 2y = 20

5(2) + 2y = 20

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For every 10 yards on a football field, there is a boldly marked line labeled with the amount of yards. Each of those lines is perpendicular to both sidelines. What can be said about the relationship of the sidelines? Justify your answer. a. The sidelines are perpendicular to each other by the definition of the Transitive Property.

b. The sidelines are parallel by the Same-Side Interior Angles Theorem.

c. The sidelines are perpendicular by the Perpendicular Transversal Theorem

d. The sidelines are parallel because they are perpendicular to the same line.

Answers

The true statement about the sidelines would be that they are parallel because they are both perpendicular to each of the boldly marked line.

  • If the sidelines are perpendicular, then the boldly marked lines, then the boldly marked lines cannot be perpendicular to both sidelines

  • The fact that all the boldly marked lines forms a perpendicular line with both sidelines, then it is a must that both sidelines are perpendicular.

Therefore, since the sidelines are perpendicular to the same set of lines, then the sidelines would be parallel.

Learn more : brainly.com/question/12168715?referrer=searchResults
The sidelines are parallel to one another, because
they are perpendicular to the same line.

How do I solve this problem? 6m+3(2m+5)+7

Answers

The final expression will be 12m + 22 .

Given,

6m+3(2m+5)+7

Here,

6m+3(2m+5)+7

To solve the above expression firstly open the brackets by multiplying 3 inside the  bracket  .

So,

6m + 6m + 15 + 7

Now add the the terms having similar variables ,

So,

6m and 3m will be added,

= 12m

Now add the constant terms,

15 + 7 = 22

Thus the final expression will be ,

12m + 22

Know more about algebra,

brainly.com/question/953809

#SPJ6
1. Combine like terms. So, combine the numbers with a variable. Then the numbers without variables. (Also known as simplifying the expression)

6m+3(2m+5)+7
12m+22

use the given conditions to write an equation for the line in point slope form passing through (-5,7) and (-8,6)

Answers

point slope form is
y-y1=m(x-x1)
where slope=m
and (x1,y1) is a given point

slope=(y2-y1)/(x2-x1)
slope=(6-7)/(-8-(-5))=-1/(-8+5)=-1/-3=1/3

pick any point
(x,y)
(-5,7)

y-7=1/3(x+5) or
y-6=1/3(x+8)

Y=8 when x=20 find y when x= 30

Answers

Answer:

y=13

Step-by-step explanation:

if x=20 when y=8 (we can creat equation )

x=2y+4 (you can prove that the equation is correct by substitute )

so the question is if x=30 find the value of y

30=2y+4

30‒4=2y

26=2y

26/2=2y/2

13=y

i hope this helps you
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