CHEMISTRY HIGH SCHOOL

What is the value for ΔSºreaction for the following reaction, given the standard entropy values? Al2O3(s) + 3H2(g) → 2Al(s) + 3H2O(g) –35 J/mol*K +35 J/mol*/K +179 J/mol*K –179 J/mol*K

Answers

Answer 1
Answer: Let me help you by giving the formula as it will be more useful for you. delta S = Sum(n) (Delta S(products)) - Sum(m)(Delta S(reactants)). There are m and n in formula that are coefficients of the reactants and products that are given in the equation.
Answer 2
Answer:

The answer is C just got it right

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What is the mass of 1 mole of Na3,PO4?

Answers

Answer:

163.940671 grams

Explanation:

You can view more details on each measurement unit: molecular weight of Na3PO4 or grams This compound is also known as Trisodium Phosphate. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Na3PO4, or 163.940671 grams.

6. Explain why the boiling point of water is a characteristic physical property, but the temperature and volume of a glass of water are not.

Answers

The physical property is a physical characteristic of a substance at some given conditions

for example

The density of water is 1 g/ mL at STP

The boiling point of water is 373K at 1 atm pressure

so boiling point of water is its physical property. It does not change with amount of the substance. The boiling point of water will remain the same for 1g and 1kg etc

now temperature is an instant measurement, the temperature may vary from sample to sample. Some water sample can be cool or some can be hot. So we cannot define that temperature of all water sample at a given pressure will be the same.

similarly the volume is a not a physical property. It will change from amount to amount.

1g of water sample will have different volume and 100g of water will have different volume while the density of water will remain the same.

A physical property is a property that does not change the original substance, meaning that it does not break any bonds, nor for any new ones. Though, a physical property can be changing the substances state of matter. 

When you are boiling water, you are changing its state to go from a liquid to a gas. The temperature is not a characteristic physical property because it doesn't help us know a lot about that substance, in other words, it isn't significant to the substance. Same goes for volume. 

How can you tell when a solution is formed?

Answers

You may tell when a solution os formed when the item or particle, such as sugar or salt,
dissolves completely in the solvent, such as water. 

Basically, you know when a solution is formed when the material you have placed in the solvent disappears :P
When the solute is completely dissolved into the solvent.

Which one of the following statements about absolute zero is correct? (a) At absolute zero, the volume of an ideal gas is zero.
(b) At absolute zero, ideal gases freeze to give solids.
(c) At absolute zero, solid and liquid water are at equilibrium.
(d) Absolute zero is the lowest temperature so far reached in the laboratory

Answers

The statement labeled as (a) is the correct one on that list.

Which provides evidence to support the big bang theory? A.
the change in carbon dioxide levels in the atmosphere

B.
the composition of the sun

C.
the red-shift of distant galaxies

D.
the magnetization of rocks on the ocean floor

Answers

A. 
the change in carbon dioxide levels in the atmosphere 

hope that's right and hope i helped

A 10.00 g sample of a compound containing only carbon, hydrogen, and oxygen forms 23.98 g CO2 and 4.91 g H2O upon complete combustion. What is the empirical formula of the compound?

Answers

There are three major steps for finding an empirical formula from a combustion reaction.
1.) Determine the grams of carbon and hydrogen from the given data.

C: 23.98 g x (12.011 g / 44.01 g) = 6.54 g C
H: 4.91 g x (2.0158 g / 18.02 g) = 0.55 g H
Determine the grams of oxygen in the sample by subtracting the mass of the compound given from the total mass solved earlier.
O: 10.0 - (6.54 + 0.55) = 2.91 g O

2) Convert the values in step 1 to moles.

C: 6.54 g / 12.01 g / mol = 0.54 mol
H: 0.55 g / 1.01 g/mol = 0.54 mol
O: 2.91 g / 16.00 g/mol = 0.18 mol

3) Divide each  by the lowest value calculated in step 2

C:  0.54 mol / 0.18 mol = 3
H:  0.54 mol / 0.18 mol = 3
O: 0.18 mol / 0.18 mol = 1

Thus, the empirical formula is C3H3O.
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