If the contents of a cell have a solute concentration of 0.04 percent which of these solutions would cause it to swell? A.) 10-percent solute concentration B.) 1-percent solute concentration C.) 0.1 percent solute concentration D.) 0.01 percent solute concentration.

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Answer 1

Answer: If the contents of a cell have a solute concentration of 0.04 percent, the solution that would cause it to swell is D) 0.01 percent solute concentration.

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What is single kind of organism that can reproduce on its own?

Answers

A cell will reproduce on its own

A single cell organism can reproduce on its own, and a cell can reproduce on its own

What is an example of a high amplitude sound, and an example of a low amplitude sound?

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Rock concerts and whispers are examples of a high-amplitude sound and a low-amplitude sound.

The largest displacement of sound wave constituents from their resting positions is referred to as amplitude. It stands for the loudness or intensity of a sound, to put it simply. Here are some illustrations of both high and low-amplitude sounds:

High Amplitude Sound: An illustration of a high amplitude sound is a rock concert with loudspeakers blaring songs at full intensity. The concert speakers produce sound waves with a tremendous amplitude, creating a powerful, strong sound that can be heard from a great distance.

Low Amplitude Sound: A low amplitude sound is something like the sound of a whisper. The sound created when someone whispers is calm and soft and not as loud as a rock concert, since the sound waves produced have a tiny amplitude.

In both cases, how loud or soft the sound is perceived by our ears depends on the amplitude of the sound waves. Low-amplitude sounds are soft and quiet, but high-amplitude sounds are strong and loud.

Hence, rock concerts and whispers are examples of a high-amplitude sound and a low-amplitude sound.

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High amplitude is a sound of high loudness like that of traffic, DJ, and earthquake volcano etc.

Low amplitude is feeble sound like that of light breeze, or that of whispering

An average person can reach a maximum height of about 60 cm when jumping straight up from a crouched position. during the jump itself, the person's body from the knees up typically rises a distance of around 50 cm. to keep the calculations simple and yet get a reasonable result, assume that the entire body rises this much during the jump.

Answers

Final answer:

The question is related to Physics and deals with kinematic equations. With the supplied information, one can calculate elements such as velocity or applied force in the jump.

Explanation:

The subject of the question pertains to the field of Physics, specifically the area of kinematic equations which deal with the motion of objects. The provided information in the question pertains to the rise of a person's body during a jump. Given the average height of 60cm that a person typically attains and the approximate rise of the body from the knees up being 50cm, these figures can be used in a Physics context to determine different factors of the jump such as velocity or force applied.

For example, using the equation of motion (height = 0.5 * gravity * time^2) where gravity is around 9.8 m/s^2, you can calculate the time taken to reach maximum height. We can calculate this using the initial velocity combined with the gravity force. Furthermore, the force applied can be calculated knowing the mass of the person and the acceleration (which is the initial velocity divided by the time).

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Two cars leave towns 680 kilometers apart at the same time and travel toward each other. one car's rate is 10 kilometers per hour less than the other's. if they meet in 4 hours, what is the rate of the slower car?

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D = distance between the cars at the start of time = 680 km

v₁ = speed of one car

v₂ = speed of other car = v₁ - 10

t = time taken to meet = 4 h

distance traveled by one car in time "t" + distance traveled by other car in time "t" = D

v₁ t + v₂ t = D

(v₁ + v₂) t = D

inserting the values

(v₁ + v₁ - 10) (4) = 680

v₁ = 90 km/h

rate of slower car is given as

v₂ = v₁ - 10

v₂ = 90 - 10 = 80 km/h

Final answer:

The slower car travels at 75 km/hr while the faster car travels at 85 km/hr. They meet up after both traveling for 4 hours, thereby covering the 680 kilometers between them.

Explanation:

The subject of this question is algebra - specifically involving rates of speed and time. Here's how you would find the answer:

Begin by understanding that it is not two separate trips but merely one trip where they are traveling towards each other. This means collectively they've traveled 680 kilometers.
Denote the slower car's rate as 'r'. The faster car would then have a rate of 'r + 10' km/hr.
Since they are traveling towards each other for the same duration, you can set up the formula 'distance = rate * time' for BOTH cars, i.e.:
4r (slower car's distance covered) + 4(r + 10) (faster car's distance covered) = 680km.
Solve the equation for 'r'.

The result would be 75 km/hr for the slower car and 85 km/hr for the faster car. They meet up after both traveling for 4 hours, thereby covering the 680 kilometers between them.

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4 points Two cylindrical resistors R, and R2 made from the same material are connected in parallel in a circuit. Both resistors are at the same temperature when the circuit is operational. Resistor R, has length and diameter d. Resistor R has length 8l and has a diameter d/1. Determine by what factor is the resistance R greater than R.St. your answer as an integer with no decimal place. Type your answer...

Answers

To determine the factor by which the resistance of resistor R2 is greater than resistor R1, we can use the formula for resistance of a cylindrical resistor:

R = ρ * (L/A)

Where R is the resistance, ρ is the resistivity of the material, L is the length of the resistor, and A is the cross-sectional area of the resistor.

Since both resistors are made from the same material and are at the same temperature, the resistivity ρ is the same for both resistors.

Let's calculate the resistance for R1 and R2 separately.

For resistor R1 (length = L and diameter = d), the cross-sectional area A1 is given by:

A1 = π * (d/2)^2

For resistor R2 (length = 8L and diameter = d/1), the cross-sectional area A2 is given by:

A2 = π * ((d/1)/2)^2

Simplifying the equations:

A1 = π * (d/2)^2 = π * (d^2/4)

A2 = π * ((d/1)/2)^2 = π * (d^2/4)

As we can see, both resistors have the same cross-sectional area A.

Now, let's calculate the resistance for R1 and R2:

R1 = ρ * (L/A1) = ρ * (L / (π * (d^2/4)))

R2 = ρ * (8L/A2) = ρ * (8L / (π * (d^2/4)))

Simplifying the equations further:

R1 = (4ρL) / (πd^2)

R2 = (32ρL) / (πd^2)

Now, let's find the factor by which the resistance R2 is greater than R1:

Factor = R2 / R1 = ((32ρL) / (πd^2)) / ((4ρL) / (πd^2))

Canceling out common terms:

Factor = (32ρL * πd^2) / (4ρL * πd^2)

Factor = 32 / 4

Factor = 8

Therefore, the resistance R2 is 8 times greater than the resistance R1.

The resistance of second resistor R2, is 16 times greater than the resistance of the first resistor R1.

The resistance of a cylindrical resistor is given by R = ρL/A, where ρ is the resistivity, L is the length, and A is the cross-sectional area (which is πd²/4 for a cylinder). For R1, it has length L and diameter d. For R2, it has length 8L and diameter d/1. The resistance of R2 is therefore:

R2 = ρ(8L)/(π(d/1)²/4)

By comparing R2 to R1, we find that R2 is 16 times the resistance of R1.

The resistance of second resistor R2, is 16 times greater than the resistance of the first resistor R1.

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Which of the four regions of the Sun has the lowest temperature?

Answers

It would be the Photosphere, because the farther out you go with the layers, it actually gets hotter, and the DEEPEST and coldest out of the layers is the Photosphere. ;-)
I hope I helped! =D

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