The weight of male Americans between the ages of 18 and 25 is normally distributed, with a mean of 164.5 lb and a standard deviation of 26 lb. One definition of obesity states that a person is obese if the z-score of his or her weight is greater than 2.What is the obesity threshold weight for a young adult American male? Round your answer to the nearest tenth.

Answers

Answer 1

Answer: Z- score equal to 2 means 2 standard deviations greater than the mean.
Mean + 2 z = 164.5 + 2 * 26 = 164.5 + 52 = 216.5
Answer: the obesity threshold weight for a young adult American male is 216.5 lb.

Answer 2

Answer:

Answer:

216 is correct!

Step-by-step explanation:

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give you 300 dollars if u get this right. you have my word The lifetimes of 20,000 light bulbs are normally distributed. The mean lifetime is 230 days. The standard deviation is 40 days. Find the values defined by the standard deviation in a normal distribution for 3 standard deviations.

The diameter of a circle is a chord that _______ passes through the center of the circle. A. always
B. sometimes
C. never

Answers

The answer is A. Always.
The diameter of a circle is a line that goes from one side to the other hence passing through the center!
Hope this helped!

Answer:

The answer is A. always

Step-by-step explanation:

Name the corresponding part if RST WXY.

∠ S =

Answers

Answer: ∠S = ∠X.

Step-by-step explanation:

Since we have given that

∠RST and ∠WXY

WE need to find the corresponding part of ∠S.

As we have given RST and WXY,

Corresponding part means a pair of matching sides or angles that are in the same side in two different shapes.

So,According to question,

Corresponding angle to ∠S is ∠X.

Hence, ∠S = ∠X.

The corresponding part is <X

Solve 2 log2 2 + 2 log2 6 − log2 3x = 3.

Answers

Answer:

x = 6

Step-by-step explanation:

Given : $2\:log_2\:2\:+\:2\:log_26−\:log_2\:3x\:=\:3$

We have to solve the given expression $2\:log_2\:2\:+\:2\:log_26−\:log_2\:3x\:=\:3$

Subtract $2\log _2\left(2\right)+2\log _2\left(6\right)$ both sides , we have,

$2\:log_2\:2\:+\:2\:log_26-\:log_2\:3x-(2\log _2\left(2\right)+2\log _2\left(6\right)):=\:3-(2\log _2\left(2\right)+2\log _2\left(6\right))$

Simplify, we have,

$\log _2\left(3x\right)=3-2\log _2\left(2\right)-2\log _2\left(6\right)$

Divide both side by -1, we have,

$(-\log _2\left(3x\right))/(-1)=(3)/(-1)-(2\log _2\left(2\right))/(-1)-(2\log _2\left(6\right))/(-1)$

Simplify, we have,

$\log _2\left(3x\right)=-3+2\log _2\left(2\right)+2\log _2\left(6\right)$

Apply log rule, $a=\log _b\left(b^a\right)$

$2\log _2\left(6\right)-1=\log _2\left(2^(2\log _2\left(6\right)-1)\right)=\log _2\left(18\right)$

When log have same base,

$\log _b\left(f\left(x\right)\right)=\log _b\left(g\left(x\right)\right)\quad \Rightarrow \quad f\left(x\right)=g\left(x\right)$

$\mathrm{For\:}\log _2\left(3x\right)=\log _2\left(18\right)\mathrm{,\:\quad solve\:}3x=18$

3x = 18

x = 6

log(base2)[2² * 6² / 3x] = 3
144 / 3x = 2^3 = 8
144/8 = 3x
18 = 3x
x = 6

The mean score on a calculus exam was 40, and the standard deviation was 5. The teacher decided to double everyone’s score and then added 7 points. What are the values of the mean and standard deviation of the distribution of transformed exam scores? (Options: mean = 80 and standard deviation = 5, mean = 80 and standard deviation = 10, mean = 87 and standard deviation = 5, mean = 87 and standard deviation = 10, mean = 87 and standard deviation = 17)