Suppose P is between M and N. If MN = 10, MP = x-3, and PN = x+1, what is the value of x?

Answers

Answer 1

Answer: MN = MP + PN

10 = (x - 3) + (x + 1)

10 = x + x - 3 + 1

10 = 2x - 2 (add 2 to each side)

12 = 2x (divide 2 from each side)

12/2 = x

6 = x
answer

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Express (x-1)(x+2)(x-3) in standard form

Answers

I hope this helps you

(x.x+2x-1.x-1.2)(x-3)

(x^2+x-2)(x-3)

x^2.x-3.x^2+x.x-3.x-2.x-2. (-3)

x^3-4x^2-5x+6

Answer:

x^3-2x^2-5x+6

Step-by-step explanation:

(x-3)(x-1)

(x^2-x-3x+3)(x+2)

x^3+2x^2-4x^2-8x+3x +6

now combine like terms

-8x + 3x = 5x

2x^2-4x^2= -2x^2

Which of the following is a multiple of 2? A. 847 B. 1,000 C. 2,461 D. 75

Answers

it would be B.) reason being 1,000 is the only even number. solving the problem you ar multiplying by two (even number) not an odd number.
Hope this helps

The 1000 is a multiple of 2, so the correct option is B.

Here to find the multiple of 2, we need to divide in following numbers:

The number are 847, 1000, 2461 and 75.

847/2 = 423.5.

1000/2 = 500.

2461/2 = 1230.5.

75/2 = 37.5.

Reason being 1,000 is the only even number, solving the problem multiplying by two (even number) not an odd number.

Therefore, the 1000 is a multiple of 2.

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During his workout, Elan spent 28% of the time on the treadmill. What fraction of his workout was on the treadmill?

Answers

Answer: $(7)/(25)$

Step-by-step explanation:

Given : During his workout, Elan spent 28% of the time on the treadmill.

We know that to convert percentage into fraction , we divide it by 100.

Thus , $28\%=(28)/(100)$

Now to reduce it into lowest term , divide numerator and denominator by 4, we get

$(28)/(100)=(7)/(25)$

Hence, the fraction of his workout was on the treadmill = $(7)/(25)$

A percent always mean something out of a 100. So, you write - 28/100. This ca be so pied further by 2. So, then the fractions becomes - 14/50. This cane further be simplified by 2, so the fraction is 7/25. And that is your final answer.

Find the domain and range of function y = √(−x^{2} −6x+2)

Answers

$y=√(-x^2-6x+2)\n\nD:-x^2-6x+2\geq0\n\na=-1;\ b=-6;\ c=2\n\n\Delta=b^2-4ac;\ iff\ \Delta \geq0\ then\ x_1=(-b-\sqrt\Delta)/(2a);\ x_2=(-b+\sqrt\Delta)/(2a)\n\n\Delta=(-6)^2-4\cdot(-1)\cdot2=36+8=44;\ \sqrt\Delta=√(44)=√(4\cdot11)=2√(11)\n\nx_1=(6-2√(11))/(2\cdot(-1))=-3+√(11);\ x_2=(6+2√(11))/(2\cdot(-1))=-3-√(11)\n\nlook\ at\ the\ picture\n\nD:x\in\left<-3-√(11);-3+√(11)\right>$

If x2 = 10, what is the value of x?±square root of 10
±square root of 20
±5
±20

Answers

Answer:

x = ±√10

Step-by-step explanation:

Don't you mean x^2 = 10 or x² = 10?

Taking the square root of both sides, we get:

x = ±√10 (matches first answer)

Enter your answer and show all the steps that you use to solve this problem in the space provided. A.Solve a–9=20 B.Solve b–9>20 C.How is solving the equation in part a similar to solving the inequality in part b? D.How are the solutions different?

Answers

Answer:

A) The value of a is 29.

B) The value of b isgreater than 29.

C) In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.

D) The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.

Step-by-step explanation:

Solving for Part A.

Given,

$a-9=20$

We have to solve for a.

$a-9=20$

By using addition property of equality, we will add both side by 9;

$a-9+9=20+9\na=29$

Hence the value of a is 29.

Solving for Part B.

Given,

$b-9>20$

We have to solve for b.

$b-9>20$

By using addition property of inequality, we will add both side by 9;

$b-9+9>20+9\nb>29$

Hence the value of b isgreater than 29.

Solving for Part C.

In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.

Solving for Part D.

The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.

Final answer:

To solve a - 9 = 20, we add 9 to 20, which results in a = 29. For b - 9 > 20, it's similar; we add 9 to 20, resulting in b > 29. The process is similar for both, but an equation's solution (a) is a single number, while an inequality's solution (b) represents a range of numbers.

Explanation:

To solve part A, which is a - 9 = 20, we will need to isolate the variable 'a' on the left side of the equation. Doing so gives us a = 20 + 9 or a = 29.

For part B, which is to solve b - 9 > 20, the operation is similar, but the result is an inequality, not a specific number. Solving it gives us b > 20 + 9 or b > 29.

The process is similar for both because you are essentially isolating the variable on one side of the equation or inequality. The difference is that the solution for an equation (part A) is a specific number, while the solution for an inequality (part B) is a range of numbers.

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