In the following reaction, how many liters of carbon dioxide will be produced if 250 liters of oxygen is used in the combustion of sucrose, given that both gases are at STP

Answers

Answer 1
Answer: The balanced reaction would be:

C12H22O11 + 12O2 = 12CO2 + 11H2O

We are given the amount of oxygen used in the combustion. This will be the starting point of our calculation. We use the ideal gas equation to find for the number of moles.

n = PV / RT = 1.00(250 L) / (0.08206 atm L/mol K ) 273 K
n= 11.16 mol O2

11.16 mol O2 (12 mol CO2 / 12 mol O2) = 11.16 mol CO2

V = nRT/P =
11.16 mol CO2 x 273 K x 0.08206 atm L/mol K / 1 atm
V=250 L

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Determine the new temperature when the volume a gas at 1.56L and 20.0 ˚C changes to 2.02L. Please show work

Answers

Answer:

T₂ = 379.4 K

Explanation:

Given data:

Initial volume = 1.56 L

Initial temperature = 20°C (20+273 = 293 K)

Final volume = 2.02 L

Final temperature = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂  = V₂T₁ /V₁

T₂ = 2.02 L × 293 K / 1.56 L

T₂ = 591.86 L.K /  1.56 L

T₂ = 379.4 K

A physician has ordered 0.50 mg of atropine, intramuscularly. If atropine were available as 0.10 mg/mL solution, how many mL would u need to give?

Answers

x * 0.10 mg/mL = 0.50 mg

x = 0.50 mg / 0.10

x = 5.0 mL

hope this helps!

In real life, a given system can approach equilibrium from different starting points but will still have the same equilibrium constant. How is this possible? Explain your answer in complete sentences.

Answers

In real life, a given system can approach equilibrium from different starting points but will still have the same equilibrium constant. It is because the rate of reaction for product formation and reactants forming is the same. It came to a point where their reaction attains equilibrium.

Is the following a chemical change or a physical change? A pencil is sharpened in a pencil sharpener, leaving behind shaving. Physical Change Chemical Change

Answers

This is an example of physical change, because the pencil's chemical composition does not change.
*Physical Change.*
A physical change in a substance doesn't change what the substance is.
A Chemical change
, there is a chemical reaction, a new substance is formed and energy is either given off or absorbed.

The blue color of the sky results from the scattering of sunlight by molecules in the air. The blue light has a frequency of about 7.03 × 1014 Hz. Calculate the wavelength (in nm) associated with this radiation, and calculate the energy (in joules) of a single photon associated with this frequency. Enter your answers in scientific notation.

Answers

Answer:

λ = 426.7 nm

E = 4.66 x 10⁻¹⁹ J

Explanation:

The equation of frequency is:

f = v / λ

v: velocity

λ: wavelength

λ = v / f

λ = 3 x 10⁸ m.s⁻¹ / 7.03 x 10¹⁴ Hz

λ = 426.7 nm

The energy of a single photon is

E = hf

h: Plank's constant = 6.63 x 10⁻³⁴ m²kgs⁻¹

E =  6.63 x 10⁻³⁴ m²kgs⁻¹ x 7.03 x 10¹⁴ Hz

E = 4.66 x 10⁻¹⁹ J

The molar mass of I2 is 253.80 g/mol, and the molar mass of NI3 is 394.71 g/mol. How many moles of I2 will form 3.58 g of NI3?

Answers

The balanced chemical reaction is:

N2 +3 I2 = 2NI3

We are given the amount of product formed. This will be the starting point of our calculations.

3.58 g NI3 ( 1 mol NI3 / 394.71 g NI3 ) ( 3 mol I2 / 2 mol NI3 ) = 0.014 mol I2.

Thus, 0.014 mol of I2 is needed to form the given amount of NI3.