Light with a wavelength of 495 nm is falling on a surface and electrons with a maximum kinetic energy of 0.5 eV are ejected. What could you do to increase the maximum kinetic energy of electrons to 1.5 eV?

Answers

Answer 1

Answer:

Answer:

To increase the maximum kinetic energy of electrons to 1.5 eV, it is necessary that ultraviolet radiation of 354 nm falls on the surface.

Explanation:

First, we have to calculate the work function of the element. The maximum kinetic energy as a function of the wavelength is given by:

$K_(max)=(hc)/(\lambda)-W$

Here h is the Planck's constant, c is the speed of light, $\lambda$ is the wavelength of the light and W the work function of the element:

$W=(hc)/(\lambda)-K_(max)\nW=((4.14*10^(-15)eV\cdot s)(3*10^8(m)/(s)))/(495*10^(-9)m)-0.5eV\nW=2.01eV$

Now, we calculate the wavelength for the new maximum kinetic energy:

$W+K_(max)=(hc)/(\lambda)\n\lambda=(hc)/(W+K_(max))\n\lambda=((4.14*10^(-15)eV\cdot s)(3*10^8(m)/(s)))/(2.01eV+1.5eV)\n\lambda=3.54*10^(-7)m=354*10^(-9)m=354nm$

This wavelength corresponds to ultraviolet radiation. So, to increase the maximum kinetic energy of electrons to 1.5 eV, it is necessary that ultraviolet radiation of 354 nm falls on the surface.

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Write as ordinary number 3 x 10^0

Answers

Answer:

Explanation:

10⁰ = 1 because anything to the power of 0 is 1.

3×1= 3

2. Turn on Show current and select Electron flow. The moving dots represent a current of electrons—tiny, negatively charged particles—moving through the wire. Voltage is a measure of how much more potential energy an electron at one end of a battery has than an electron at the other end of the battery. A. How does changing the battery’s voltage affect the current? It makes the current get more electrons which causes more movement

Answers

Answer:

Changing the battery's voltage will also change the flow of electrons through the circuit. An increase in the voltage will produce more electron movement, and a reduction in the voltage will produce less electron movement.

Explanation:

The voltage is the potential energy between two points in an electric circuit. It is also the work done per unit charge to move a charge between these two points, this work is done against the resistance (analogous to frictional forces in the wire) of the wire. The potential energy is like the push required to move an electron through an electric circuit, and negatively charged particle (electron in the case of the wire) are pulled towards the higher potential, which is conventionally at the positive terminal. Current (flow of electrons) will not occur without any potential between two points.

Changing the battery's voltage will change the push that is experienced by the electrons. If the potential is increased, the electrons will experience more push, which means there will be more movement or flow of electrons through the circuit. Reducing the battery's voltage reduces the push experienced by the electrons; meaning a reduced flow or movement of these electrons through the circuit.

How can scientific method solve real world problems examples

Answers

The scientific method is nothing more than a process for discovering answers. While the name refers to “science,” this method of problem solving can be used for any type of problem

Imagine that you drop an object of 10 kg, how much will be the acceleration andhow much force causes the acceleration?

Answers

If you do this on Earth, then the acceleration of the falling object is 9.8 m/s^2 ... NO MATTER what it's mass is.

If its mass is 10 kg, then the force pulling it down is 98.1 Newtons. Most people call that the object's "weight".

An object has an average acceleration of +6.07 m/s2 for 0.250 s . At the end of this time the object's velocity is +9.64 m/s .What was the object's initial velocity?

Answers

Answer:

Explanation:

From the question we are given;

Acceleration a = 6.07m/s²

Time t= 0.25s

Final velocity v = 9.64m/s

Required

Initial velocity u

Using the equation of motion

v = u+at

9.64 = u+(6.07)(0.25)

9.64 = u+1.5175

u = 9.64-1.5175

u = 8.1225m/s

Hence the object's initial velocity is 8.1225m/s

A projectile is launched at some angle to the horizontal with some initial speed vi, and air resistance is negligible.(a) Is the projectile a freely falling body?Yes or No(b) What is its acceleration in the vertical direction? (Let up be the positive direction.)____? m/s2(c) What is its acceleration in the horizontal direction?

Answers

Answer:

A) No

B)-9,81 m/s^2

C)0 m/s^2

Explanation:

A free fallin object has only velocity on the vertical axis so any object that is moving in the Y and X axis has projetile motion not free falling, and when dealing with projectile motion the object is experiencing acceleration towards the ground of -9,81m/s^2 and in the Y axis, in the X axis there´s is only acceleration if the air is providing resistance, since it states that it isnot, then the accleration is 0.

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