Suppose is a semester that 38% of students at a college failed mathematics, 27% failed physics, and 9% failed both. A student is selected at random.a)If a student failed physics, what is the probability that he or she failed math?
b)If a student failed math, what is the probability he or she failed physics?
c)What is the probability that he or she failed math or physics?

Answers

Answer 1

Answer: Hello,

A) failed in Phys: 27 failed in Math ==> intersection : 9/27=1/3

B)Failed in Math 38 ,failed in Phys ==>9/38

C) M∪P=M+P-M∩P= (38+27-9)/100=56/100=14/25

Probabiliy is hard for me.

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What is the value of the underlined digit? 56.(1)23
What is the average of the integers from 25 to 41? 27, 33, 36, 66 ?
D/4 -7 =-12
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Kylie measured a swimming pool and made a scale drawing. She used the scale 1 inch = 1 foot. What is the scale factor of the drawing?Simplify your answer and write it as a fraction.

Answers

Answer:

40 meter

Step-by-step explanation:

Factor the trinomial in to 2 sets of parentheses
12a squared minus 13a minus 35

Answers

it can't be factored because there are no 2 numbers that when you multiply you get 35 and when you add you get 13.

Find the possible values for s in the inequality 12s – 20 ≤ 50 – 3s – 25.

Answers

12s - 20 < 50 - 3s - 25

12s - 20 < 50 - 3s - 25
+3s +3s
15s - 20 < 50 - 25
+ 20 + 20
15s < 70 - 25

15s < 45
÷ 15 ÷15
s < 3

The value of s is less than or equal to 3. So s can be 3, 2, 1, 0, and negative numbers.

s = 3 ⇒ 12(3) - 20 < 50 - 3(3) - 25 ; 36 - 20 < 50 - 9 - 25 ; 16 < 16
s = 2 ⇒ 12(2) - 20 < 50 - 3(2) - 25 ; 24 - 20 < 50 - 6 - 25 ; 4 < 19

A taxicab starts at (1, -2) on the grid. It goes 4 blocks south and 3 blocks east to pick up a passenger. Then it goes 6 blocks west and 5 blocks north and drops off the passenger. How many blocks is the taxicab from its starting position

Answers

Answer:

The cab is -1/3 west of north.

( from the starting point it goes 1 block to the north and 3 blocks to the west . Cab is at (-2,-1))

Step-by-step explanation:

It is given that:

A taxicab starts at (1, -2) on the grid.

It goes 4 blocks south and 3 blocks east to pick up a passenger.

This implies that the cab will reach at a point (4,-6)

( Since going south means it will go some units down and similarly going east means it will go some units to the right.

Hence, here going 4 blocks south and 3 blocks east means it will go to:

(1,-2) → (1+3,-2-4)=(4,-6) )

Then it goes 6 blocks west and 5 blocks north and drops off the passenger.

This means that the cab will drop the passenger at (-2,-1)

Since going north means it will go some units up and similarly going west means it will go some units to the left.

Hence, here going 6 blocks west and 5 blocks north means it will go to:

(4,-6) → (4-6,-6+5)=(-2,-1) )

Hence, the end point is (-2,-1)

Now the slope of the line joining the starting and the end point is:

i.e. line joining (1,-2) and (-2,-1) is:

$=(-1+2)/(-2-1)\n\n\n=(1)/(-3)\n\n\n=-(1)/(3)$

Hence, the taxicab is -1/3 block west of north.

i.e. from the starting point it goes 1 block to the north and 3 blocks to the west.

i.e. the cab is in west-north direction from the starting point.

Answer:

3 Blocks west, 1 block north

Step-by-step explanation:

17.The speed limit of a highway is 55 miles per hour. A car is traveling at least 65 miles per hour. How many miles per hour m over the speed limit is the car traveling?55 – m ≥ 65; m ≥ 10 m + 65 ≤ 55; m ≤–10 65 – m ≤ 55; m ≤ 10 55 + m ≥ 65; m ≥ 10**** 18. Chris earns $7.00 per hour working on the weekends. He needs at least $210.00 for a new cell phone. How many hours, h, does Chris need to work on the weekends to buy a new phone?
h/7.00 > 210.00; h> 30; 30 hours h/7.00 < 210.00; h < 30; 30 hours 7.00h≥ 210.00; h≥ 30; 30 hours** 7.00h≤ 210.00; h ≤ 30; 30 hours

Answers

Answer:

17.) D.) 55 + m ≥ 65; m ≥ 10

18.) C.) 7.00h≥ 210.00; h≥ 30; 30 hours

Explanation:

I took the test, also your answers were right.

17. 55 + m ≥ 55

18. 210 / 7 = 30 h

h ≥ 30 hours

Part 1: Find the tangent line approximation to cos x at x=π/4.Part 2: To one decimal place, estimate the maximum value of the error on the interval 0≤x≤π/2.

Answers

Equation of the tangent line is ${2}(y+x)= (\pi)/(4)+1$ and maximum value of the error is 1.3

Part 1: Equation of the tangent line is $y-y_(1) =m(x-x_(1) )$

Let y=cos(x) then

$y((\pi)/(4)) =cos((\pi)/(4)) \ny=(1)/(√(2) )$

Now, find a slope

$y=cos(x)\ny'=-sin(x)\ny'((\pi)/(4) ) =-(1)/(√(2) )$

Equation of the tangent line is:

$y-\frac{1}√(2) } =-(1)/(√(2) ) (x-(\pi)/(4) )\n{2}(y+x)= (\pi)/(4)+1$

Part 2: Tangent line to approximate the value at x=pi/2

$y=(-√(2) \pi)/(8)+(1)/(√(2) ) \ny=1.3$

The maximum value of error is 1.3

Learn more:brainly.com/question/15523943

Part 1: To find the tangent line, we need a point and a slope because we are using point slope form: y-y1=m(x-x1)
To get the y-value for our point, plug pi/4 into the original as x
y=cos(x)
y=cos(pi/4)
y=√2/2
Then to find a slope, we need to get the derivative:
y=cos(x)
y'=-sin(x) (and plug in pi/4 as x to find the slope at this point)
=-sin(pi/4)
=-√2/2

So the tangent line is y-√2/2=-√2/2(x-pi/4)

Part 2: I'm not positive on this but I think you're supposed to use this tangent line to approximate the value at x=pi/2 and find the degree of error.
y-√2/2=-√2/2(pi/2-pi/4)
y=-pi√2/8+√2/2
y=1.3 rounded to the nearest tenth

So since we know that cos(pi/2) is actually 0, the maximum value of error would be 1.3 (1.3-0=1.3)

Hope this helps

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