What is the daughter nucleus produced when 63 Zn undergoes electron capture? Replace each question mark with the appropriate integer or symbol.

Answers

Answer 1

Answer:

Answer: The daughter nuclei is $_(29)^(63)\textrm{Cu}$

Explanation:

Electron capture is defined as the process in which an electron is drawn to the nucleus where it combines with a proton to form a neutron and a neutrino particle.

$_Z^A\textrm{X}+e^-\rightarrow _(Z-1)^A\textrm{Y}+\gamma e$

The chemical equation for the reaction of electron capture of Zinc-63 nucleus follows:

$_(30)^(63)\textrm{Zn}+e^-\rightarrow _(29)^(63)\textrm{Cu}+\gamma e$

The parent nuclei in the above reaction is Zinc-63 and the daughter nuclei produced in the above reaction is copper-63 nucleus.

Hence, the daughter nuclei is $_(29)^(63)\textrm{Cu}$

Answer 2

Answer:

Final answer:

When Zinc-63 undergoes electron capture, it results in the creation of a Copper-63 daughter nucleus. This is due to the atomic number decreasing by one (from 30 to 29) during electron capture, but the mass number remaining unchanged.

Explanation:

Electron capture is a process where a proton-rich nucleus absorbs an inner shell electron, which results in a conversion of a proton into a neutron, and the emission of an electron neutrino. In doing so, the atomic number decreases by one, while the mass number stays the same. Therefore, in the case of 63 Zn (zinc-63), the atomic number is 30 prior to electron capture. After electron capture, the atomic number will decrease by one to become 29, leading to the production of 63 Cu (copper-63).

Remember that the atomic number (bottom number), also known as the proton number, determines the element. Therefore, in our example, Zn changes to Cu. The fact that the mass number (top number) remains the same is due to the total number of protons and neutrons (nucleons) being conserved.

Learn more about Electron Capture here:

brainly.com/question/11689871

#SPJ11

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How many moles of H2O are produced from 6.23g of C2H6 in the following reaction? 2C2H6+7O2 -> 4CO2+6H2O

Answers

Answer:

0.623 moles of H₂O.

Explanation:

balanced equation: 2C₂H₆ + 7O₂ -> 4CO₂+ 6H₂O

Given:

6.23g of C₂H₆

C₂H₆ molar mass is 30

solve for moles of C₂H₆

moles = mass/mr

moles = 6.23/30

moles = 0.2077

solve for moles of H₂O using molar ratio

2C₂H₆ : 6H₂O

2 : 6

0.2077 : 0.623

Therefore, found that 0.623 moles of H₂O is produced.

Which choice(s) include(s) d-orbital contribution in the hybridization scheme: pcl3, no3─, i3─, h2se ?

Answers

Among all three PCl₃, NO₃⁻ , I₃⁻, H₂Se only I₃⁻ will involve participation of d-orbitals in hybridization as bonding in I₃⁻ will include, s, p and d orbital as shown in the image attached. there will be sp³d hybridization, there will be presence of three lone pairs and 2 bonds as

I⁻ has 8 valence electrons and 2 neighbours atoms which will need one electron each to satisfy their valency.

so the number of electrons on central atom will be:

8-1-1=6

That 6 electrons will make 6/2 =3 lone pairs.

how many grams of F2 are needed to react with 3.50 grams of Cl2 Equation needed for question- Cl2+3F2-->2ClF3 please explain how to get the answer.

Answers

Answer:

5.62 g of F2

Explanation:

We have to start with the chemical reaction:

$Cl_2~+~3F_2~-->~2ClF_3$

We have a balanced reaction, so we can continue with the mol calculation. For this, we need to know the molar mass of $Cl_2$ (70.906 g/mol), so:

$3.5~g~Cl_2(1~mol~Cl_2)/(70.906~g~Cl_2)=0.049~mol~Cl_2$

Now, with the molar ratio between $Cl_2$ and $F_2$ we can convert from moles of $Cl_2$ and $F_2$ (1:3), so:

$0.049~mol~Cl_2(3~mol~F_2)/(1~mol~Cl_2)=0.148~mol~F_2$

Finally, with the molar mass of $F_2$ we can calculate the gram of $F_2$ (37.99 g/mol), so:

$0.148~mol~F_2(37.99~g~F_2)/(1~mol~F_2)=5.62~g~F_2$

I hope it helps!

Which element is a halogen?chlorine (Cl)
oxygen (O)
carbon (C)
radon (Rn)

Answers

The element that has been a halogen from the given elements have been Chlorine. Thus, option A is correct.

Halogen has been given as the group of metallic compounds that have been consisted of the one valence electrons in their last orbitals.

The halogens have been the most reactive elements and belong to group 18 of the periodic table. From the given set of elements, the number of valence electrons in the following has been:

Chlorine = 1 valence electron
Oxygen = 6 valence electrons
Carbon = 4 valence electrons
Radon = 8 valence electrons

Since the element having 1 valence electron has been Chlorine. Thus, the element that has been a halogen from the given elements have been Chlorine. Thus, option A is correct.

For more information about halogen, refer to the link:

brainly.com/question/2288388

Answer is chlorine (Cl)

Consider the generic chemical equation below. X + Ymc021-1.jpg W + Z Reactant X contains 199.3 J of chemical energy. Reactant Y contains 272.3 J of chemical energy. Product W contains 41.9 J of chemical energy. If the reaction loses 111.6 J of chemical energy as it proceeds, how much chemical energy must product Z contain?

Answers

The reaction is:

X + Y → W + Z

Chemical energy of reactant X = 199.3 J = Ux

Chemical energy of reactant Y = 272.3 J = Uy

Chemical energy of Product W = 41.9 J = Uw

Chemical energy of Product Z = ? = Uz

Where reaction loses energy = 111.6 J = ΔU

By using the equation:

(Ux + Uy) – (Uw + Uz) = ΔU

Ux + Uy – Uw – Uz = ΔU

Uz = Ux + Uy – Uw –ΔU

Uz = 199.3 + 272.3 – 41.9 – 111.6

Uz = 318.1 J

Product Z must contain 318.1 J chemical energy.

Answer:

person above me is correct

Explanation:

What is the most likely position for the hurricane indicated by the wind readings from the three weather stations shown?

Answers

Here's the answer, I remember doing this problem last year.

23.5 degrees north, 77 degrees west

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