CHEMISTRY COLLEGE

Classify each substance based on the intermolecular forces present in that substance.A. Hydrogen bonding, dipole dipole, and dispersion
B. Dipole dipole and dispersion only
C. Dispersion only
1. H2O
2. CH4
3. CO
4. CH2Cl

Answers

Answer 1

Answer:

Intermolecular forces

When H2O- Hydrogen bonding, dipole-dipole, and also dispersion
Then CH4- Dispersion only
After that CO- Dispersion only
Then CH2Cl- Dipole-dipole and also dispersion only

Explanation:

When Dipole-dipole interactions exist only in molecules that have a dipole moment such as water and also that dichloromethane.
After that Water experiences intermolecular hydrogen bonding in addition to dipole-dipole interaction and also that dispersion forces due to the O-H bond in the molecule.
Thus, Nonpolar compounds only have dispersion forces acting between their molecules.

Find out more information about dispersion here:

brainly.com/question/3224009

Answer 2

Answer:

H2O- Hydrogen bonding, dipole dipole, and dispersion

CH4- Dispersion only

CO- Dispersion only

CH2Cl- Dipole dipole and dispersion only

Explanation:

Dipole- dipole interactions exist only in molecules that have a dipole moment such as water and dichloromethane. Water experiences intermolecular hydrogen bonding in addition to dipole-dipole interaction and dispersion forces due to the O-H bond in the molecule.

Nonpolar compounds only have dispersion forces acting between its molecules.

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How can you remove sand from salt? Which physical property of sand was used in the process?

Answers

Answer:

You could collect the mixture and pour it in water, stir it , ad filter out the sand. This uses the physical property of solubility.

Explanation:

The salt dissolved, the sand didn't.

When the reaction mixture is worked-up, it is first washed three times with 5% sodium bicarbonate, and then with a saturated nacl solution. explain why?

Answers

Solution:

After the reaction of mixture is worked-up Washing three times the organic with sodium carbonate helps to decrease the solubility of the organic layer into the aqueous layer. This allows the organic layer to be separated more easily.

And then the reaction washed by saturated NACL we have The bulk of the water can often be removed by shaking or "washing" the organic layer with saturated aqueous sodium chloride (otherwise known as brine). The salt water works to pull the water from the organic layer to the water layer.

A concentration cell is constructed using two Ni electrodes with Ni2+ concentrations of 1.0 M and 1.00 � 10�4 M in the two half-cells. The reduction potential of Ni2+ is �0.23 V. Calculate the potential of the cell at 25�C if the more dilute Ni2+ solution is in the anode compartment.

Answers

Answer: The cell potential of the cell is +0.118 V

Explanation:

The half reactions for the cell is:

Oxidation half reaction (anode): $Ni(s)\rightarrow Ni^(2+)+2e^-$

Reduction half reaction (cathode): $Ni^(2+)+2e^-\rightarrow Ni(s)$

In this case, the cathode and anode both are same. So, $E^o_(cell)$ will be equal to zero.

To calculate cell potential of the cell, we use the equation given by Nernst, which is:

$E_(cell)=E^o_(cell)-(0.0592)/(n)\log ([Ni^(2+)_(diluted)])/([Ni^(2+)_(concentrated)])$

where,

n = number of electrons in oxidation-reduction reaction = 2

$E_(cell)$ = ?

$[Ni^(2+)_(diluted)]$ = $1.00* 10^(-4)M$

$[Ni^(2+)_(concentrated)]$ = 1.0 M

Putting values in above equation, we get:

$E_(cell)=0-(0.0592)/(2)\log (1.00* 10^(-4)M)/(1.0M)$

$E_(cell)=0.118V$

Hence, the cell potential of the cell is +0.118 V

The cell potential for the cell as calculated is 0.118 V.

What is the Nernst equation?

The Nernst equation can be used to obtain the cell potential of a cell under non- standard conditions. The standard cell potential in this case is zero owing to the fact that both cathode and anode are made of nickel.

Hence;

Ecell = E°cell - 0.0592/nlog Q

Ecell = 0 - 0.0592/2 log (1 00 * 10^-4/1)

Ecell = 0.118 V

The cell potential for the cell as calculated is 0.118 V.

Learn more about Nernst equation: brainly.com/question/721749

Two chemicals A and B are combined to form a chemical C. The rate, or velocity, of the reaction is proportional to the product of the instantaneous amounts of A and B not converted to chemical C. Initially, there are 100 grams of A and 50 grams of B, and for each gram of B, 2 grams of A is used. It is observed that 15 grams of C is formed in 7 minutes. How much is formed in 28 minutes

Answers

Answer: 60 grams.

Explanation:

Given data:

Chemical A = 100 grams

Chemical B = 50 grams

For each gram of B 2 grams of A is used = 1:2.

15 grams of C is formed in 7minutes.

Solution

How many grams would be formed in 28mins?

= 15grams / 7 minutes

= 2.1423 grams/minute

If 2.1423 grams is formed/minutes

= 28minutes x 2.1423grams

= 60grams

60 grams of solution C would be formed in 28 minutes.

A solution is dilute when?A. it has a lot of solute
B. has little solvent
C. it has a lot of solvent
D. has maximum solute

Answers

The answer to your equation is C. Hope this Helps!

C. It has more solvent
To dilute a solution means to add more solvent without the addition of more solute

A system absorbs 12 J of heat from the surroundings; meanwhile, 28 J of work is done on the system. What is the change of the internal energy ΔEth of the system?