Answer:99.33
Explanation:
together and PROTONS move from one object to the other.
Answer:
true
Explanation:
yes because I said so
Gravity is affected by mass and distance
Explanation:
Three resistors of resistances 2ohm,3ohm, and 6ohm respectively.
Let R1=2Ω
⇒R2=3Ω
⇒R2=6Ω
● A total resistance of 4Ω from three resistors of given resistances. Firstly, connect the two resistors of 3Ω and 6Ω in parallel to get a total resistance of 2Ω which is less than the lowest individual resistance.
●When R 2 and R 3 are connected in parallel with
R1 in series we get
⇒1/R=1/R2+1/R3
⇒1/R=1/3+1/6
⇒1/R=1/2
⇒R=2Ω
●Hence, the total resistance of the circuit is 4Ω.
Given: Takeoff Speed (u) = 28 m/s
Final velocity (v) = 0.0 m/s
Acceleration (a) = 1.9 m/s²
To calculate: The minimum length of runway (s) =?
Solution: Apply 3rd kinematic equation of motion
v² = u² - 2as
Or, s = ( u² - v²) / 2 a
Or, s = ( 28² - 0²) / 2 × 1.9 m
Or, s = 206.3 m
Hence, the required minimum length of the runway will be 206.3 m
To determine the minimum length of the runway a Cessna 150 airplane would need to take off, you can use a kinematic equation. Plugging in a final velocity of 28 m/s, initial velocity of 0 m/s (since the plane starts from rest), and acceleration of 1.9 m/s/s gives an answer of approximately 207.11 meters.
The subject of your question is related to physics, specifically, kinematics, which studies the motion of objects. In your case, a Cessna 150 airplane needs to accelerate from rest to a speed of 28 m/s for takeoff, with an average acceleration of 1.9 m/s/s, and you're trying to find out the minimum length of the runway required. For this, we can use a kinematic equation.
The equation we can use is the following: v^2 = u^2 + 2as, where v is the final velocity (28 m/s), u is the initial velocity (0 m/s since the plane starts from rest), a is the acceleration (1.9 m/s/s), and s is the distance we want to find out.
When you plug in the known values into the equation, you will get: (28)^2 = (0)^2 + 2 * 1.9 * s. After rearranging the equation, you will have s = [(28)^2 - (0)^2] / 2*1.9 = 207.11 m. Therefore, the minimum length of the runway required for the Cessna 150 airplane to take off is approximately 207.11 meters, assuming constant acceleration and no other factors interfering.
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B. Free electrons are concentrated in the P-type material and holes form in the N-type material.
C. The negative terminal of the source of voltage is connected to the N-type material within a reverse-biased setup.
D. Only a small current will flow through the diode in the forward-biased setup.
magnitude of Alpha Crucis is 0.77. Identify which star appears brighter when observed from
Earth. Explain your answer.
Answer:
Alpha centauri will be brighter than Alpha Crucis .
Explanation:
Apparent magnitude of a star measures how bright a star is .
This scale is reverse logarithmic ie , the brighter the star , the lower is its magnitude . A magnitude equal to 5 scale higher represents less magnitude by a factor of 1/ 100 . In this way a difference of 1 magnitude represents a brightness ratio of 2.512 . Hence a star of brightness magnitude of 7 is less bright by a factor 2.512 than that of a star magnitude of 6 .