A is a heterogeneous mixture in which the particles settle to the bottom.

Answers

Answer 1
Answer:

There are two types of mixture depending on the distribution of the components in the mixture. Homogeneous mixtures are mixtures which has uniform properties all throughout the solution while heterogeneous mixtures are the opposite they do not exhibit uniformity in any property. Example for a homogeneous is a salt solution where at any point you get a sample the properties are the same. For the heterogeneous mixture, a mixture of sand and salt where at any sampling point the properties are not the same.

Answer 2
Answer:

suspension should be correct

a suspension

the particles are big enough to settle

a colloid

the particles are too small to ever settle

a solution

homogeneous mixture of two or more substances


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I need help matching the problem
Can someone solve 5 ?

In which compound is the percent by mass of oxygen greatest?A. BeO
B. MgO
C. CaO
D. SrO

Answers

Answer: BeO

Explanation:

percent by mass of oxygen=\frac{\text {mass of oxygen}}{\text {Total mass of substance}}* 100\%

percent by mass of oxygen in BeO=(16g)/(25.01g/mol)* 100=63.97\%

percent by mass of oxygen in MgO=(16g)/(40.30g/mol)* 100=39.70\%

percent by mass of oxygen in CaO=(16g)/(56.08g/mol)* 100=28.53\%

percent by mass of oxygen in SrO=(16g)/(103.62g/mol)* 100=15.44\%

The answer is A
Hide the Oxygen for a minute
Mass of elements:
Be:9.012
Mg:24.305
Ca:40.078
Sr:87.62
Out of all these choices, Be is the lightest

Gabriella weighs 450 N. She climbs a flight of stairs to a height of 3 m. It takes her 5 seconds. How much work does Gabriella do when she climbs the stairs?A.
150 J

B.
270 J

C.
1350 J

D.
2250 J

Answers

The formula that can be applied in this problem is W = Fd where W is work, F is the force and d is distance. You have 450N and 3m, all you have to do is to multiply it.

W = Fd

W = (450N) (3m)

W = 1350J

The answer is letter C.

A sample of an unknown substance has a mass of 89.5 g. If 345.2 J of heat are required to heat the substance from 285 K to 305 K, what is the specific heat of the substance?

Answers

The specific heat of the unknown sample has been \rm \bold{0.192\;\;J/g^\circ C}.

Specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat (c) for a substance can be given by:

Q=mc\Delta T ......(i)

Where, the heat required by the substance, Q=345.2\;\text J

The mass of the substance has been, m=89.5\;\text g

The change in temperature of the system has been, \Delta T

The change in temperature has been given as:

\Delta T=T_f-T_i

The initial temperature of the substance, T_i=285\;\text K

The final temperature of the substance, T_f=305\;\text K

Substituting the values for the change in temperature, \Delta T:

\Delta T=305\;-\;285\;K\n\Delta T=20\;\text K

Substituting the values in equation (i):

345.2=89.5\;*\;c\;*\;20\n345.2=1,790c\nc=0.192\rm \;J/g^\circ C

The specific heat of the unknown sample has been \rm \bold{0.192\;\;J/g^\circ C}.

For more information about specific heat, refer to the link:

brainly.com/question/2094845

The specific heat is the heat needed per unit mass to raise the temperature by 1 degree celsius. So the specific heat = heat/(mass*ΔT) = 345.2/[89.5*(305-285)]=0.193 J/(g*℃). When using ΔT, the unit K and ℃ are the same.

At standard pressure when NaCl is added to water,the solution will have a

Answers

Answer: lower freezing point and a higher boiling point than water

Explanation:

Addition of a non volatile solute leads to elevation in boiling point and depression in freezing point.

This increase in boiling point arises because particles of the non-volatile solute occupy the surface of solution due to which solvent particles can not escape out of the solution.  Hence, high amount of heat is required for the solute particles to escape out of the solution. Therefore, an increase in boiling point will occur.

Also as vapor pressure of solution becomes less, the freezing point gets depressed as freezing point is the temperature at which vapor pressure of solid becomes equal to the vapor pressure of solution.

Thus at standard pressure when NaCl is added to water,the solution will have a lower freezing point and a higher boiling point than water

lower freezing point and a higher boiling point than water 

Planck's constant relates the Joules of energy absorbed/released by matter to the:A. atomic number of the element

B. observed wavelength of light

C. speed of light

D. mass of the particulate matter

Answers

Answer:   B. observed wavelength of light

Explanation:  The relation of Planck's constant relating the Joules of energy absorbed/released by matter is usually used to determine the energy of the photon. The mathematical expression is -

                            E= h c / \lambda

Thus as we can observe that the energy is directly proportional to the speed of light and inversely proportional to the wavelength of the light.

Thus , we can say that Planck's constant relates the Joules of energy absorbed/released by matter to the observed wavelength of light.

The right answer for the question that is being asked and shown above is that: "B. observed wavelength of light" Planck's constant relates the Joules of energy absorbed/released by matter to the B. observed wavelength of light

Mintu wants to increase the heat transfer between a metal iron and another piece of metal he wants to shape. He decides to increase the time the two metals are in contact, use a larger metal iron, and use a new metal material with a higher specific heat. Where is Mintu's error?A:Mintu should have decreased the size of the metal iron
B:Mintu should have decreased the time he touches the two metals
C:Mintu should have chosen a material with a lower specific heat
D:Mintu should have chosen a material the same temperature as the iron.

Answers

Answer: Option (C) is the correct answer.

Explanation:

The amount of heat necessary to raise the temperature of 1 gram of a substance by 1^(o)C is known as specific heat of a substance.

Mathematically,     q = mC \Delta T

where,    q = Heat energy

               C = specific heat

          \Delta T = change in temperature

Hence, smaller is the amount of heat required by a substance to raise the temperature of its 1 g by 1^(o)C more readily it will get hot.

Therefore, out of the given options specific heat of copper is small. So, copper will heat up quickly.

Thus, we can conclude that Mintu's error is that Mintu should have chosen a material with a lower specific heat.

Answer:

C - Mintu should have chosen a material with a lower specific heat.

Explanation:

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