The sum of pH and pOH for any aqueous solution equals

Answers

Answer 1

Answer: pH is a notion that expresses the concentration of hydrogen in a solution while pOH expresses the concentration of hydroxide in a solution. The sum of pH and pOH in a solution is 14.

Answer 2

Answer:

Answer: 14

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

Acids have pH ranging from 1 to 6.9, bases have pH ranging from 7.1 to 14 and neutral solutions have pH equal to 7.

$pH=-\log [H^+]$

$pOH=-\log[OH^-]$

$pH+pOH=14$

Thus the sum of pH and pOH is 14.

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What moves in or out of a substance during a change of state?
The rare earth elements include

Which properties increase when moving down a group of the periodic table?Select all that apply.

reactivity
valence electrons
atomic radii
atomic mass

Answers

Explanation:

When we move down a group then there will be increase in number of shells present in an atom. Due to this there will be increase in atomic radii of the atom.

As a result, there will be increase in atomic mass of the atom also. Whereas reactivity of metals increases on moving down the group as the valence shell moves away from the nucleus. So, it becomes easy for the metal atom to lose an electron.

On the other hand, reactivity of non-metals decreases on moving down the group.

So, we can conclude that properties increase when moving down a group of the periodic table are atomic radii and atomic mass.

Atomic Mass.

Reactivity decreases as you go down a group.

Atomic Radius also decreases as you go down a group.

Valence electrons are the same within a group.

Atomic mass, however, increases as you go down a group.

Hope this helps!

HELP!!!! The freezing of methane is an exothermic change. What best describes the temperature conditions that are likely to make this a spontaneous change? Any temperature, because entropy increases during freezing. Any temperature, because entropy decreases during freezing. Low temperature only, because entropy decreases during freezing. High temperature only, because entropy increases during freezing.

Answers

Answer: The correct statement is low temperature only, because entropy decreases during freezing.

Explanation:

The relationship between Gibb's free energy, enthalpy, entropy and temperature is given by the equation:

$\Delta G=\Delta H-T\Delta S$

Where,

$\Delta G$ = change in Gibb's free energy

$\Delta H$ = change in enthalpy

T = temperature

$\Delta S$ = change in entropy

It is given that freezing of methane is taking place, which means that entropy is decreasing and $Delta S$ is becoming negative. It is also given that the reaction is an exothermic reaction, this means that the $\Delta H$ is also negative.

For a reaction to be spontaneous, $\Delta G$ must be negative.

$-ve=-ve-[T(-ve)]\n\n-ve=-ve+T$

From above equations, it is visible that $\Delta G$ will be negative only when the temperature will be low.

Hence, the correct statement is low temperature only, because entropy decreases during freezing.

Answer:

Low temperature only, because entropy decreases during freezing.

Explanation:

Select the non-metals. N Br Ca Na Fe

Answers

N,Br

The elements which can donate their electrons are called metals
The elements which can adopt other's electrons to acquire noble gas configuration are called non metals

1. What is the empirical formula for a compound containing 63.8% N and 36.2% O?a. N₂O₅
b. N₂O₃
c. NO₂
d. NO
e. N2₂O

Answers

$M\ N_2=28g/mol\n 63,8\%--28g\n 100\%--x\n x=43,89g$

43,89g≈44g
44g == 2x 14g (N) + 1x 16x(O)
M N₂O = 44g

How many liters of 0.1107 M KCI contains 15.00 g of KCI (FW= 74.6 g/mol)

Answers

Answer:

1.81 liters of KCl solution

Explanation:

Molarity is expressed as:

$Molarity=(molesofsolute)/(litersofsolution)$

Solving for Liters of solution:

Liters of solution = $(molesofsolute)/(Molarity)$ (1)

Using the molecular weight fo the KCl to find the moles of solute:

$15.00gKCl*(1molKCl)/(74.6gKCl)=0.20molesKCl$

Replacing in the formula (1):

Liters of solution = $(0.20molesKCl)/(0.1107M)$

Liters of solution = 1.81 liters

Number of moles:

n = sample mass / molar mass

n = 15.00 / 74.6

n = 0.2010 moles of KCl

Therefore:

Molarity = moles / Volume

0.1107 = 0.2010 / V

V = 0.2010 / 0.1107

V = 1.815 L

A) How many moles of gold atoms are present in a 295-gram sample of gold? B) How many gold atoms would there be in the sample?

Answers

The molar mass of gold, Au, as seen on the periodic table, is 196.97 grams per mole. So, do this to find the number of moles in a 295 gram sample:

$(295g\ Au)((1mol\ Au)/(196.97g\ Au)) = 1.49769mol\ Au$

So, a 295 gram sample of gold has about 1.5 moles of gold in it.

To find the number of atoms, multiply the number of moles by Avogadro's number:

$(1.49769mol\ Au)((6.022*10^(23)\ atoms)/(mol)) = 9.02 * 10^(23)\ atoms\ Au$

5 gram of 197 Au contain 1.53*10^22 atoms. so just multiply that with 59 to get 295 grams :)

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