According to atomic theory: a. the nucleus is positively charged.
b. the nucleus contains both charged and uncharged particles.
c. the electrons contribute very little to the total mass of the atom.
d. the electrons are located in the atomic space outside the nucleus.
e. all of these

Answers

Answer 1
Answer:

Answer:

e. all of these

Explanation:

Let us check all the given options one by one:

a.The nucleus is positively charged.

Yes it is correct since nucleus contain protons and neutrons and protons are positively charged.

b.The nucleus contains both charged and uncharged particles.

Yes because protons are positively charged and neutrons are neutral in nature.

c.The electrons contribute very little to the total mass of the atom.

Yes we know all the mass of the atom is considered in center and mass of electron is negligible as compared to protons and neutrons.

d.The electrons are located in the atomic space outside the nucleus.

Yes, its a known fact.

e. All of these.

Since , all given options are correct .

Therefore , option e. is right .


Related Questions

It is possible for a particular element to have various number of neutrons
The concentration 12 g/L means there are 12 g of solute present in__________of solution.
Which of the following is a homogeneous mixture?a.sugar dissolved in waterb.oxygen and nitrogen gases in the airc.oil and vinegar salad dressingd.a silver mercury amalgam used to fill a tooth cavity
BRAINLEST IF RIGHTTechnician A says that the piston's most important function is to transfer the force produced by the burning air-and-fuel mixture into usable power. Technician B says that the piston size is used to help form a seal between the piston and the cylinder walls. Who is right? A. Neither Technician A nor B B. Technician A only C. Technician B only D. Both Technicians A and B
When a substance heats up, and the particles gain thermal energy and spread apart, what do scientists say about that substance? a) It becomes more dense. b) It undergoes a phase change. c) It expands. d) It contracts.

Ice is _______ dense than water.more

less

equally as

twice as

Answers

Ice is less dense than water. The orientation of hydrogens are further apart from each other.

Answer:

Ice is Less Dense than water

Explanation:

If you put ice in water the ice won't sink to the bottom because water is denser then ice.

:)

Which element would release the most energy while adding an electron to a neutral atom in the gas phase? The choices are the following: Na. . Al. . Br. . S

Answers

Br would release the most energy while adding anelectron to a neutral atom in the gas phase.

 

Bromine is a chemicalelement with symbol Br and atomic number 35. It is a halogen. The element wasisolated independently by two chemists, Carl Jacob Löwig and Antoine JérômeBalard.

 

The correct answer between allthe choices given is the third choice. I am hoping that this answer hassatisfied your query and it will be able to help you in your endeavor, and ifyou would like, feel free to ask another question.

Answer: Br

Explanation:

Br:35:[Ar]3d^(10)4s^24p^5

Br^-:36:[Ar]3d^(10)4s^24p^6:[Kr]

Na:11:[Ne]3s^1

Na^-:12:[Ne]3s^2

Al:13:[Ne]3s^23p^1

Al^-:14:[Ne]3s^23p^2

S:16:[Ne]3s^23p^4

S^-:17:[Ne]3s^23p^5

As Bromine is short of only 1 electron to attain noble gas configuration, it will release energy as more stable species have less energy. Thus bromine would release most energy while adding an an electron to a neutral atom in the gas phase.

All other species Na, Al and S would not attain stable configuration on addition of electron and hence no energy would be released.

A solution containing 1000g of an unknown substance in 12.3g of naphthalene was found to freeze at 1.2∘C. What is the molar mass of the unknown substance?

Answers

Answer: Therefore, the molar mass of the unknown substance is 68.4 g/mol.

Explanation: We can use the freezing point depression equation to solve for the molar mass of the unknown substance:

ΔT = Kf × m

where ΔT is the change in freezing point, Kf is the freezing point depression constant of the solvent (naphthalene), and m is the molality of the solution.

First, we need to calculate the molality of the solution:

molality = moles of solute / mass of solvent (in kg)

We don't know the number of moles of the unknown substance, but we can assume that the naphthalene does not contribute significantly to the total mass of the solution (since its mass is much smaller than the mass of the unknown substance). Therefore, we can use the entire mass of the solution (1000g + 12.3g = 1012.3g) as the mass of solvent.

mass of solute = 1000g

mass of solvent = 12.3g

mass of solution = 1012.3g

molality = (1000g / molar mass) / (12.3g / 1000g) = 81.3 / molar mass

Next, we need to calculate the change in freezing point:

ΔT = 1.2∘C

Finally, we can use the freezing point depression constant of naphthalene to solve for the molar mass of the unknown substance:

Kf for naphthalene = 6.8∘C/m

ΔT = Kf × m

1.2 = 6.8 × (81.3 / molar mass)

molar mass = 68.4 g/mol

Therefore, the molar mass of the unknown substance is 68.4 g/mol.

Giving brainliest if correct!! please help someone out?

Answers

Answer:

protons: 36

neutrons:48

electrons:36

Explanation:

the number of protons in an element is = to the atomic # (36)

the number of neutrons is the atomic mass - atomic # (84-36=48)

In a neutral charged element the # of protons = # of electrons

Determine the percent yield for the reaction between 46.5 g of ZnS and 13.3 g of oxygen if 18.l4 g of ZnO is recovered along with an unknown quantity of sulfur
dioxide.
please show work thank you

Answers

The percentage yield of the reaction has been 46.74%.

Percentage yield can be given as the ratio of the actual yield to the theoretical yield.

For the theoretical yield, the balanced equation will be:

\rm 2\;ZnS\;+\;3\;O_2\;\rightarrow\;2\;ZnO\;+\;2\;SO_2

Thus, 2 moles of ZnS will give 2 moles of ZnO.

The moles of 46.5 g ZnS:

Moles = \rm (weight)/(molecular\;weight)

ZnS = \rm (46.5)/(97.474)

ZnS = 0.477 mol

The moles of 13.3 grams Oxygen:

Oxygen = \rm (13.3)/(32)

Oxygen = 0.415 mol.

The moles of 18.14 grams ZnO:

ZnO = \rm (18.14)/(81.38)

ZnO = 0.222 mol

According to the balanced chemical equation,

2 moles ZnO = 2 moles ZnS

0.222 mol ZnO = 0.222 mol ZnS

2 moles ZnO = 3 moles Oxygen

0.222 mol ZnO = 0.334 mol of Oxygen

Since, both the reactants are in enough concentration,

The theoretical yield can be calculated with any of the reactants. The theoretical yield of ZnO from 46.5 grams of ZnS can be given as:

1 mole ZnS = 1 mol ZnO

0.477 mol of ZnS = 0.477 mol of ZnO.

The mass of 0.477 mol of ZnO:

Mass = moles * molecular weight

Mass of ZnO = 0.477 * 81.38

Mass of ZnO = 38.818 grams.

The theoretical yield of ZnO = 38.818 g.

The actualyield of ZnO = 18.14 g.

Percentage yield = \rm (18.14)/(38.81)\;*\;100

Percentage yield = 46.74 %

The percentage yield of the reaction has been 46.74%.

For more information about the percentage yield, refer to the link:

brainly.com/question/11715808

Found an answer sheet :)

A weather balloon of known initial volume is released. The air pressures ar its initial and final altitudes are known. Why can't you find its new volume by using these known values and Boyle's law?

Answers

Answer: you cannot find its new volume by using these known values and Boyle's law because the temperature does not remain constant.


Explanation:


Boyle's law states that the volume of a fixed amount of gas, at a constant temperature, varies inversely with the pressure.


So, it is a condition that the temperature does not change.


For the wheater ballon case, as it travels through the atmosphere, the temperature at different altitudes will be different.


So, you might use other equation of states, such as the combined law, which does deal with changes in the three variables: volume, pressure, and temperature.


The mathematical formulation of Boyle's law is:


pV = constanjt ⇒ p₁ V₁ = p₂ V₂, at constant T.


The mathematical formulation of the combined law of gases is:


pV/T = constant ⇒ p₁ V₁ / T₁ = p₂ V₂ / T₂, for a fixed amount of gas, then it might work for the weather ballon (if you know the initial and end temperatures).



You cannot find the new volume by using initial volume of the weather balloon and air pressure ai its initial and final altitudes and Boyle’s law because the given values are not the same. Boyle’s law holds for the pressure and volume of the GAS at constant temperature. Here you are given the air pressure outside the weather balloon not the inside of the balloon. They have different gases and so it would not apply.