PHYSICS MIDDLE SCHOOL

Starting from rest, Christina experiences 24.5 m/s2 of acceleration to take off from an aircraft carrier for 5 seconds. How long does the runway need to be? Round to the nearest meter.

Answers

Answer 1

Answer:

Answer:

The length of the runway to the nearest meter is 306 m.

Explanation:

Given:

Initial velocity of Christina is, $u=0\ m/s(Rest)$

Time taken is, $t=5\ s$

Acceleration experienced by Christina is, $a=24.5\ m/s^2$

The length of the runway is, $d=?$

Now, we use Newton's equation of motion that relates the distance, initial velocity, time and acceleration.

So, we have the following equation of motion:

$d=ut+(1)/(2)at^2$

Plug in all the given values and solve for 'd'. This gives,

$d=0+(1)/(2)* 24.5* 5^2\n\nd=(1* 24.5* 25)/(2)\n\nd=(612.5)/(2)\n\nd=306.25\approx 306\ m(\textrm{Rounding to nearest meter})$

Therefore, the length of the runway to the nearest meter is 306 m.

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Answers

Answer:

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Answers

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Answers

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The chart shows data for four moving objects.Object
Final Velocity
(m/s)
29
Change in
Time (s)
Initial Velocity
(m/s)
11
10
12
20
W
X
Y
IZ
Which object has the greatest acceleration?
34
Ow
OZ

Answers

Answer:

Explanation:

The answer is y because,

W: (29-11)/6 = 3

X: (34-10)/12 =2

Y: (40-12)/7=4

Z= (28-20)/8=1

4 is greater then all, therefore the answer is Y

Answer:

Explanation:

v=u+at but t is constant so

a=v-u

for x

a=29-10

a=19

which marks the greater acceleration

Which substance is a combination of different atoms?

Answers

Answer:

Heterogeneous

Explanation:

A chemical substance is composed of one type of atom or molecule. A mixture is composed of different types of atoms or molecules that are not chemically bonded. A heterogeneous mixture is a mixture of two or more chemical substances where the various components can be visually distinguished.

a person pushing a stroller starts from rest, uniformly accelerating at a rate of 0.500 m/s2. What is the velocity of the stroller after it has traveled 4.75 m ?

Answers

Answer:

Approximately $2.18 m\cdot s^(-1)$ .

Explanation:

Consider one of the equations for constant acceleration ("SUVAT" equations)

$v^(2) - u^(2) = 2 \; a \cdot x$ ,

where

$v$ is the final velocity of the object,
$u$ is the initial velocity of the object,
$a$ is the acceleration of the object, and
$x$ is the distance that the object had traveled while its velocity changed from $u$ to $v$ .

Note that unlike other SUVAT equations, this one does not ask for the time required for the speed of the object to change from $u$ to $v$ . Since in this problem, time isn't given, this time-less equation would particular useful.

Here

$v$ the final velocity needs to be found.
$u = 0$ for the stroller started from rest.
$a =\rm 0.500 \;m \cdot s^(-2)$ is the acceleration of the stroller, and
$x = \rm 4.75\; m$ is the distance that the stroller traveled while its velocity changed from $u$ to $v$ .

Rearrange the equation to isolate the unknown, $v$ :

$v^(2) = u^(2) + 2 \; a \cdot x$ .

Make sure that all units are standard, so that the unit of the output will also be standard. Apply the equation:

$v = \sqrt{u^(2) + 2 \; a \cdot x} = √(0^2 + 2 * 0.500 * 4.75 )\approx \rm 2.18\; m\cdot s^(-1)$ .

Hence the final velocity will be approximately $\rm 2.18 m\cdot s^(-1)$ .

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