MATHEMATICS COLLEGE

Look at the steps used when solving 3(x - 2) = 3 for x Which step is the result of combining like terms? A) Step 1

B) Step 2

C) Step 3

D) Step 4

Answers

Answer 1

Answer:

Answer : The correct option is, (B) Step 2

Step-by-step explanation :

The given expression is:

3(x - 2) = 3

In this expression, 'x' is a variable.

By using distributive property, we get:

3x - 6 = 3

Now adding 6 on both side, we get:

3x - 6 + 6 = 3 + 6

Now combining like terms, we get:

3x = 9

Now dividing the expression by 3, we get the value of 'x'.

x = 3

The meaning of like terms in mathematics is that have the same variables and exponents.

Hence, the step result of combining like terms is, Step 2

Answer 2

Answer:

Answer:

Step 1

Step-by-step explanation:

Like terms are mathematical terms that have the exact same variables and exponents, this is why step 1 is the answer.

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Records show that the average number of phone calls received per day is 9.2. Find the probability of between 2 and 4 phone calls received (endpoints included) in a given day.

Answers

Answer:

4.76% probability of between 2 and 4 phone calls received (endpoints included) in a given day.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Records show that the average number of phone calls received per day is 9.2.

This means that $\mu = 9.2$ .

Find the probability of between 2 and 4 phone calls received (endpoints included) in a given day.

$(2 \leq X \leq 4) = P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)$

$P(X = 2) = (e^(-9.2)*(9.2)^(2))/((2)!) = 0.0043$

$P(X = 3) = (e^(-9.2)*(9.2)^(3))/((3)!) = 0.0131$

$P(X = 4) = (e^(-9.2)*(9.2)^(4))/((4)!) = 0.0302$

$(2 \leq X \leq 4) = P(X = 2) + P(X = 3) + P(X = 4) = 0.0043 + 0.0131 + 0.0302 = 0.0476$

4.76% probability of between 2 and 4 phone calls received (endpoints included) in a given day.

Problem 5.Joseph is told to dissolve a medicine he has to take in 1 pint 4 ounces of water. He has a
measuring cup marked in ounces. How many ounces of water should he pour?

Answers

Answer:

The amount of water he should pour in ounces(that is the only units the cup measures) is 16 + 4 = 20 ounces

Step-by-step explanation:

He is told to dissolve a medicine he has in 1 pint 4 ounces of water . He has a measuring cup marked in ounces .This means he can only measure the water quantity in ounces.

He definitely have to convert the pints to ounces.

1 pint = 16 ounces

Recall he has to dissolve the medicine in 1 pint 4 ounces of water.

Since 1 pint is equals to 16 ounces therefore, 16 ounces + 4 ounces = 20 ounces.

The amount of water he should pour in ounces(that is the only units the cup measures) is 16 + 4 = 20 ounces

40% of the groups budget was spent on activities. If $64,000 was spent on the activities, what was the full budget? solve with the aid of a diagram. State what type of problem this is. if it's division, which type? Explain your reasoning, not just by using an equation.

Answers

Answer:

The full budget has a total value of $160,000

Step-by-step explanation:

This is a simple ratio problem and can be solved using the Rule of Three property. The Rule of Three is used to compare two ratios and find the missing part. In this case the ratios would be the following.

$(64,000)/(40 percent) = (x)/(100 percent)$

$(64,000 * 100 percent)/(40 percent) = \frac{x}$

$(6,400,000)/(40 percent) = \frac{x}$

$160,000= \frac{x}$

So now we know that 100% (The full budget) has a total value of $160,000.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

Help asap !! will get branliest.

Answers

Answer:

0.8

Step-by-step explanation:

(2 x 10^-4)

= 0.0002

(4x10^3)

= 4000

0.0002 x 4000 = 0.8

A real estate developer is considering investing in a shopping mall on the outskirts of Atlanta, Georgia. Three parcels of land are being evaluated. Of particular importance is the income in the area surrounding the proposed mall. A random sample of four families is selected near each proposed mall. Following are the sample results. At the 0.05 significance level, can the developer conclude there is a difference in the mean income

Answers

Answer:

Step 1: The null and alternative hypothesis for the one way analysis of variance is,

H₀ : There is no difference in the means of each area.

H₁ : At least one mean is different.

The objective of this question is to test whether the income of the three areas are significantly different.

Step 2: The problem states to use 0.05 significance level.

Step 3: The test statistic follows the F-distribution.

Step 4: Decision rule is based on the critical value.

Numerator degrees of freedom is,

K - 1 = 3 - 1

= 2

Denominator degrees of freedom is 2.

n - k = 12 - 3

= 9

Using the F-distribution table for ∝=0.05 with numerator and denominator degrees freedom, the critical value is 4.26. The decision rule is to reject H₀ if the computed value of F exceeds 4.26.

Step 5: Calculations.

Using Excel follow the steps mentioned below.

1. Import or type the data into spreadsheet.

2. Data--------> Data Analysis----------> Anova: Single Factor, click OK.

3. Select Input Range, make a tick mark on Labels in the first row, enter 0.05 for alfa.

4. Click OK.

The obtained output for the one-way ANOVA is,

[ find the figure in attachment]

From the obtained output, the computed test statistic value, F = 14.18 , which is greater than the critical value of 4.26. So, reject H₀

Step 6: Interpretation. The average income of each area is different. It can be concluded that the average income is significantly different .

Final answer:

To determine if there is a difference in the mean income between three proposed mall locations, perform an analysis of variance (ANOVA) test.

Explanation:

To determine if there is a difference in the mean income between the three proposed mall locations, we can perform an analysis of variance (ANOVA) test. This test assesses whether there is a statistically significant difference among the means of multiple groups.

First, calculate the sample mean income for each location. Then, compute the sum of squares within groups (SSW) and the sum of squares between groups (SSB). Finally, use these values to calculate the F-statistic and compare it to the critical value from the F-distribution table at the 0.05 significance level to make a conclusion.

If the computed F-statistic is greater than the critical value, we reject the null hypothesis and conclude that there is a difference in the mean income.