MATHEMATICS COLLEGE

20% of the 35 vendors at a craft show sell jewelry. How many of the vendors sell jewelry? Please HURRYYYY

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Answer 1
Answer:

Answer:

what's the question tell please

Related Questions

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A microwave is placed on top of a stand. The stand is 2 feet 10 inches tall, and the microwave is 3 feet 3 inches tall. Together, how tall are they?Write your answer in feet and inches. Use a number less than 12 for inches.
What is 743x295What do I need to d
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How to work 48÷(4+2×10)-1​

Answers

Answer:

The answer is 1

Step-by-step explanation:

In order to do this equation you use PEMDAS Parentheses, Exponents, Multiplication , Division, Addition and Subtraction

So,

48 / (4+2X10)-1\n 48 /(4+20)-1\n 48/(24)-1\n48/24-1\n2-1\n1

Hoped this helped :D

How can I calculate this expression?

Answers

Answer:

26 whole 3/40

Step-by-step explanation:

Multiply the denominator with the number in middle and add to top,

13/3+ 17/5+ 46/16

LCM& Changing into lowest terms,

(65+51)/15+23/8

116/5+23/8

(928+115)/40

1043/40

26 whole 3/40
Idek dog you should know honestly

Find the missing values on the diagram below. Assume that each line is evenly divided

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Answer:

Step-by-step explanation:

Can the sides of a triangle have lengths 5, 8, and 11?

. Chad's pay rate for babysitting is y = 9x, where x is the number of hours he babysits, and y is the number of dollars he earns. Horatio's pay rate is shown in the graph below. Horatio's Babysitting Pay Rate. Which of the following statements is true? * HORATIO'S BABYSITTING PAY RATE 100 90 80 70 60 Dollars Earned (8.60) 50 40 30 20 10 (4, 30) 0 1 2 3 4 5 6 7 8 9 10 Hours A. Chad makes $1.00 more per hour than Horatio. O B. Chad makes $1.50 more per hour than Horatio. C. Chad makes $1.00 less per hour than Horatio. D. Chad makes $1.50 less per hour than Horatio.​

Answers

Answer: Chad Makes $1.50 more

Step-by-step explanation:

You have to divide 30 from 4 to see Horatio’s hourly rate which is 7.5 and then you will see that 9 - 7.5 is 1.5. I hope this helped

The following measurements were recorded for the drying time, in hours, of a certain brand of latex paint: 3.4, 2.5, 4.8, 2.9, 3.6, 2.8, 3.3, 5.6, 3.7, 2.8, 4.4, 4.0, 5.2, 3.0, 4.8. Assuming that the measurements represent a random sample from a normal population, find a 95% prediction interval for the drying time for the next trial of the paint.

Answers

Answer:

The 95% confidence interval for the mean is (3.249, 4.324).

We can predict with 95% confidence that the next trial of the paint will be within 3.249 and 4.324.

Step-by-step explanation:

We have to calculate a 95% confidence interval for the mean.

As the population standard deviation is not known, we will use the sample standard deviation as an estimation.

The sample mean is:

M=(1)/(15)\sum_(i=1)^(15)(3.4+2.5+4.8+2.9+3.6+2.8+3.3+5.6+3.7+2.8+4.4+4+5.2+3+4.8)\n\n\n M=(56.8)/(15)=3.787

The sample standard deviation is:

s=\sqrt{(1)/((n-1))\sum_(i=1)^(15)(x_i-M)^2}\n\n\ns=\sqrt{(1)/(14)\cdot [(3.4-(3.787))^2+(2.5-(3.787))^2+(4.8-(3.787))^2+...+(4.8-(3.787))^2]}\n\n\ns=\sqrt{(1)/(14)\cdot [(0.15)+(1.66)+(1.03)+...+(1.03)]}

s=\sqrt{(13.197)/(14)}=√(0.9427)\n\n\ns=0.971

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=3.787.

The sample size is N=15.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=(s)/(√(N))=(0.971)/(√(15))=(0.971)/(3.873)=0.2507

The t-value for a 95% confidence interval is t=2.145.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.145 \cdot 0.2507=0.538

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 3.787-0.538=3.249\n\nUL=M+t \cdot s_M = 3.787+0.538=4.324

The 95% confidence interval for the mean is (3.249, 4.324).

(a^(2)-1)/(2-5a) times (15a-6)/(a^(2)+5a-6)click on answer to see full problem

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\bf \cfrac{a^2-1}{2-5a}* \cfrac{15-6}{a^2+5a-6}\n\n-----------------------------\n\nrecall\quad \textit{difference of squares}\n \quad \n(a-b)(a+b) = a^2-b^2\qquad \qquad a^2-b^2 = (a-b)(a+b)\n\nthus\quad a^2-1\iff a^2-1^2\implies (a-1)(a+1)\n\n\nnow\quad a^2+5a-6\implies (a+6)(a-1)\n\n-----------------------------\n\nthus\n\n\n\cfrac{a^2-1}{2-5a}* \cfrac{15-6}{a^2+5a-6}\implies \cfrac{(a-1)(a+1)}{2-5a}* \cfrac{3(5a-2)}{(a+6)(a-1)}\n\n-----------------------------\n\n

\bf now\quad 3(5a-2) \iff -3(2-5a)\n\n-----------------------------\n\nthus\n\n\n\cfrac{\underline{(a-1)}(a+1)}{\underline{2-5a}}* \cfrac{-3\underline{(2-5a)}}{(a+6)\underline{(a-1)}}\implies \cfrac{-3(a+1)}{a+6}
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