Assume that the given procedure yields a binomial distribution with n trials and the probability of success for one trial is p. Use the given values of n and p to find the mean mu and standard deviation sigma. ​Also, use the range rule of thumb to find the minimum usual value mu minus 2 sigma and the maximum usual value mu plus 2 sigma. In an analysis of preliminary test results from a​ gender-selection method, 33 babies are born and it is assumed that​ 50% of babies are​ girls, so equals 33 and p equals 0.5.

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Answer 1
Answer:

Answer:

Step-by-step explanation:

Hello!

The study variable is:

X: Number of female babies in a sample of 33 babies.

The variable has binomial distribution, symbolically:

X~Bi(n; p)

n= 33

p= 0.5

The mean of the Binomial variable is:

E(X)= n*p

E(X)= 33*0.5

E(X)= 16.5

The variance of the Binomial is:

V(X)= n*p*q

q= (1 - p) (If "p" is the probability of "success", "q" represents the probability of "failure")

V(X)= 33*0.5*0.5

V(X)= 8.25

Then the standard deviation is:

√V(X)= √8.25= 2.87

E(X) + 2*(√V(X))= 22.24

E(X) - 2*(√V(X))= 10.76

I hope it helps!


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Select all the properties of a non -square rectangle ? 3 Same -Side angles supplemental

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Answer

Check Explanation

Explanation

Supplementary angles are angles that sum up to give 180 degrees.

And for all rectangles, whether a square one or non-square one, all of the angles of the rectangle are each 90 degrees.

So, it is clear that any two same side angles will be 90° + 90° = 180°

Meaning that same side angles of a non-square rectangle are supplemental.

Hope this Helps!!!

In the diagram, the measure of angle 6 is 98.what is the measure of angle 7?what is the measure of angle 7?

56 degrees
84 degrees
96 degrees
124 degrees

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the answer his 24 degrees

The residents of a certain dormitory have collected the following data: People who live in the dorm can be classified as either involved in a relationship or uninvolved. Among involved people, 10 percent experience a breakup of their relationship every month. Among uninvolved people, 15 percent will enter into a relationship every month. What is the steady-state fraction of residents who are uninvolved

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Answer:

The steady state proportion for the U (uninvolved) fraction is 0.4.

Step-by-step explanation:

This can be modeled as a Markov chain, with two states:

U: uninvolved

M: matched

The transitions probability matrix is:

\begin{pmatrix} &U&M\nU&0.85&0.15\nM&0.10&0.90\end{pmatrix}

The steady state is that satisfies this product of matrixs:

[\pi] \cdot [P]=[\pi]

being π the matrix of steady-state proportions and P the transition matrix.

If we multiply, we have:

(\pi_U,\pi_M)*\begin{pmatrix}0.85&0.15\n0.10&0.90\end{pmatrix}=(\pi_U,\pi_M)

Now we have to solve this equations

0.85\pi_U+0.10\pi_M=\pi_U\n\n0.15\pi_U+0.90\pi_M=\pi_M

We choose one of the equations and solve:

0.85\pi_U+0.10\pi_M=\pi_U\n\n\pi_M=((1-0.85)/0.10)\pi_U=1.5\pi_U\n\n\n\pi_M+\pi_U=1\n\n1.5\pi_U+\pi_U=1\n\n\pi_U=1/2.5=0.4 \n\n \pi_M=1.5\pi_U=1.5*0.4=0.6

Then, the steady state proportion for the U (uninvolved) fraction is 0.4.

2.23 round to the nearest tenth.

Answers

2.2

since the third number isn’t equal to or above 5, it rounds down.

Write a formula that will compute the final grade for the course, using G to represent the final grade, H to represent the homework average, Q to represent the quiz average, P to represent the project grade, T to represent the test average, and F to represent the final exam grade. Note: Keep in mind how you must write the percentages that show the weighting of each category when doing computations!

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Answer:

To calculate final grade we use the formula:

Final grade = H( the weight of h) + Q( the weight of q) + P (the weight of project) +T (the weight of test) + F(the weight of final exams).

This formula help us to calculate the grade we need to get.

Step-by-step explanation:

Solution:

Suppose grade breakdown for certain college course is as follow:

Homework = 15%

Quizzes = 20%

Project = 10%

Test = 40%

Final exam= 15%

Let G represent the final grade

H represents homework average,

Q represents quizzes and P represent project, T represent test average and F represent final exam.

To calculate final grade we use the formula:

Final grade = H( the weight of h) + Q( the weight of q) + P (the weight of project) +T (the weight of test) + F(the weight of final exams).

This formula help us to calculate the grade we need to get.

Final answer:

The final grade, G, can be computed by adding together the weighted values of the homework average, quiz average, project grade, test average, and final exam grade. This can be represented by the formula G = 0.20*H + 0.20*Q + 0.25*P + 0.15*T + 0.20*F.

Explanation:

To compute the final grade for the course, you will need to multiply each category by its weighting percentage, then add the results together. This can be represented as the following formula:

G = 0.20*H + 0.20*Q + 0.25*P + 0.15*T + 0.20*F

In this formula, G is the final grade, H is the homework average, Q is the quiz average, P is the project grade, T is the test average, and F is the final exam grade. The coefficients (0.20, 0.20, 0.25, 0.15, and 0.20) represent the weighting percentages in decimal form for each respective category.

Learn more about final grade calculation here:

brainly.com/question/33666307

#SPJ3

Please help I need help with this question??)):

Answers

Answer:

fourth degree monomial

Step-by-step explanation:

This is the answer by definition.

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