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Can you help me to do this please?Determine the inverse of the h(x)

Answers

Answer 1

Answer:

Answer:

$h^(-1)(x)=x^3+6x^2+12x+7$

Explanation:

Given the below function;

$h(x)=\sqrt[3]{x+1}-2$

We'll follow the below steps to determine the inverse of the above function;

Step 1: Replace h(x) with y;

$y=\sqrt[3]{x+1}-2$

Step 2: Switch x and y;

$x=\sqrt[3]{y+1}-2$

Step 3: Solve for y by first adding 2 to both sides;

$\begin{gathered} x+2=\sqrt[3]{y+1}-2+2 \n x+2=\sqrt[3]{y+1} \end{gathered}$

Step 4: Take the cube of both sides;

$\begin{gathered} (x+2)^3=(\sqrt[3]{y+1})^3 \n (x+2)^3=y+1 \end{gathered}$

Step 5: Expand the cube power;

Recall;

$(a+b)^3=a^3+3a^2b+3ab^2+b^3$

Applying the above, we'll have;

$\begin{gathered} (x+2)^3=y+1 \n x^3+3x^2\cdot2+3x\cdot2^2+2^3=y+1 \n x^3+6x^2+12x+8=y+1 \end{gathered}$

Step 6: Subtract 1 from both sides of the equation;

$\begin{gathered} x^3+6x^2+12x+8-1=y+1-1 \n x^3+6x^2+12x+7=y \n \therefore y=x^3+6x^2+12x+7 \end{gathered}$

Step 7: Replace y with h^-1(x);

$h^(-1)(x)=x^3+6x^2+12x+7$

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wo cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is selected. Find the probability of selecting a nine and then selecting an eight. The probability of selecting a nine and then selecting an eight is nothing.

Answers

Answer:

0.6%

Step-by-step explanation:

We have a standard deck of 52 playing cards, which is made up of 13 cards of each type (hearts, diamonds, spades, clubs)

Therefore there are one nine hearts, one nine diamonds, one nine spades and one nine clubs, that is to say that in total there are 4. Therefore the probability of drawing a nine is:

4/52

In the second card it is the same, an eight, that is, there are 4 eight cards, but there is already one less card in the whole deck, since it is not replaced, therefore the probability is:

4/51

So the final probability would be:

(4/52) * (4/51) = 0.006

Which means that the probability of the event is 0.6%

In the sixth grade class at Madison Middle School, for every 6 students, 4 of them play at least one sport. If there are 270 students on the sixth grade class, how many of them play at least one sport? a) 39
b) 180
c) 11
d) 405

Answers

Answer:

B is the answer

Step-by-step explanation:

Because we can make 4/6 into 2/3 and 2/3 of 270 is 180

both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. how high would this water rise if it were poured into the empty wide cylinder

Answers

The height of the water when poured into the empty wide cylinder is;

Option A; To the 7¹/₃ mark

Formula for volume of a cylinder is;

V = πr²h

where;

r is radius

h is height

We are told that water is poured into the wide cylinder up to the 4th mark. Thus, for the wide cylinder, h = 4. Thus;

V_wide = 4πR²

Similarly, we are told that water is poured into the narrow cylinder up to the 6th mark. Thus, for the narrow cylinder, h = 6. Thus;

V_narrow = 6πr²

Now, the volume of the water will be the same since it was the same quantity that was poured. Thus;

V_wide = V_narrow

4πR² = 6πr²

⇒ R²/r² = 6/4

simplifies to get; R²/r² = ³/₂

Now both cylinder were emptied and water poured rises to the 11th mark for the narrow cylinder. Thus;

πR²H = 11πr²

R²/r² = 11/H

Earlier, we saw that R²/r² = ³/₂. Thus;

11/H = ³/₂

H = 22/3

H = 7¹/₃

The complete question is;

Attached are the drawings of a wide and a narrow cylinder. The cylinders have equally spaced marks on them. Water is poured into the wide cylinder up to the 4th mark (see A). This water rises to the 6th mark when poured into the narrow cylinder (see B). Both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. How high would this water rise if it were poured into the empty wide cylinder?

A) To the 7¹/₃ mark

B)To the 8th mark

C) To the 7¹/₂mark

D)To the 9th mark

E) To the 11th mark

Read more at; brainly.com/question/16760517

Answer:

COMPLETE QUESTION:

To the right are drawings of a wide and a narrow cylinder. The cylinders have equally spaced marks on them. Water is poured into the wide cylinder up to the 4th mark (see A). This water rises to the 6th mark when poured into the narrow cylinder (see B). Both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. How high would this water rise if it were poured into the empty wide cylinder?

a)To the 7 1/2 mark b)To the 9th mark c)To the 8th mark d)To the 7 1/3 mark

e)To the 11th mark

ANSWER : Option D (To the 7 1/3 mark)

Step-by-step explanation:

First part of the question enables us to get the relationship between the radius of the wider cylinder (R) and the narrow cylinder(r) i.e

Volume of cylinders

π x R² x 4 = πxr²x 6

R²/r² = 6/4

after both cylinder were emptied

π x R² x h = π x r² x 11

R²/r² = 6/4 = 11/h

h = (4 x 11) /6 = 22/3 = 7 1/3 mark

Therefore, the height of the water in the wide cylinder is 7 1/3

HELP MEE ILL MARK BRAINLEIST

Answers

Answer:

3x-3 I think that's it.

Step-by-step explanation:

Answer:

The vertex is (1, -4)

Step-by-step explanation:

Which graph shows the solution to the system of linear inequalities? Y< 1/3x-1 y<1/3-31) All values that satisfy y<1/3-1 are solutions
2) All values that satisfy y<1/3-3 are solutions
3) All values that satisfy either equations are solutions
4) There are no solutions
(Edge 2020)

Answers

The solution of the system of linear inequalities is All values that satisfy y<1/3-3 are solutions. (option 2)

What is inequality?

A relationship between two expressions or values that are not equal to each other is called inequality.

Given is a graph of inequalities, y < 1/3x-1 and y < 1/3-3

The solution of the inequality A is the shaded area below the solid blue line and the solution of the inequality B is the shaded area below the solid red line,

That means all the solutions of inequality B will satisfy the inequality A also.

Hence, The solution of the system of linear inequalities is All values that satisfy y<1/3-3 are solutions. (option 2)

For more references on inequality, click;

brainly.com/question/28823603

#SPJ5

I think the best answer would probably be 1

What is the answers help me please part A B CGiving extra points

Correct answer

Answers

Answer:

A, 38, 40

Step-by-step explanation:

a. A has to be the first graph because it starts at $ 25 and it rises as more work needs to get done

b.if you go from 50 up until you get to the line, then look left at the axis is about $38

c. C=25+s*0.25, substitute c=35 and find s

35=25+s*0.25 subtreact 25 from both sides

35-25= s*0.25

10=s*0.25 divide both sides by 0.25

10/0.25=s

40=s

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