PLEASE HELP!! The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass. Starting with 195 grams of a radioactive isotope, how much will be left after 6 half-lives?
Use the calculator provided and round your answer to the nearest gram.

Answers

Answer 1
Answer:

Answer:

3.047

Step-by-step explanation:

I'm not completely sure but i think its close

Answer 2
Answer:

Final answer:

Applying the concept of half-life, if we start with 195 grams of a radioactive isotope, after 6 half-lives, we would be left with approximately 3 grams of the isotope.

Explanation:

The half-life concept is very important in Nuclear Physics, especially when we deal with Radioactive Isotopes. Regarding your question, if an isotope has a half-life, it means after each half-life, the quantity of the isotope decreases by half. So, to determine the remaining mass of a radioactive isotope after 6 half-lives, we have to consecutively halve the initial mass 6 times.

  • After the first half-life, 195 grams will become 97.5 grams.
  • After the second half-life, 97.5 grams will become 48.75 grams.
  • After the third half-life, 48.75 grams will become 24.375 grams.
  • After the fourth half-life, 24.375 grams will become 12.18 grams.
  • After the fifth half-life, 12.18 grams will become 6.09 grams.
  • After the sixth half-life, 6.09 grams will become around 3 grams (when rounded to the nearest gram).

So, after 6 half-lives, there will be approximately 3 grams of the isotope left.

Learn more about Half-life here:

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Answers

1). Flipping a coin or picking a number are not dependent.  The probability
of the result is the same every time.  It only changes if you leave out what
you picked the first time, because then the total number of possibilities is
different.
With this reasoning, they might say that iii. is dependent because you
don't replace what you draw the first time.  I'm not comfortable with that.
Sure, you don't replace the first number you picked, but how many odd
numbers are left ?  Still an infinite number.
So I think iii. is the answer they want here, but I don't think any of the
choices is really dependent.  

2). By the same reasoning, i. and ii. are independent.  The coins have
no memory.  They don't remember what happened last time.

3).  The probability of any result is

                              (number of successes)/(number of possibilities).

Total number of possibilities each time is 8.

Probability of an even number (2, 4, 6, or 8) the first time = 4/8 = 0.5

Probability of an odd number (1, 3, 5, or 7) the second time = 4/8 = 0.5

Probability of an 8 the third time = 1/8 = 0.125 .

Probability of all 3 events = (0.5) x (0.5) x (0.125) = 0.03125  (3.125%)
 

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Answers

The Answer to That Would Be 4.2380952381.

Approximately 4.2381 or if you want the exact number, you must write it as a fraction (89)/(21)

I need all the answers to question 2 PLEASE HELP ITS URGENT ILL MARK U AS BRAINLISY

Answers

Answer:

its all wht u require.....question no 2

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1.05×10^−15
1.05×10^−14
1.05×10^−13
1.05×10^15

Answers

(3.5 x 10^-5)(3 x 10^-10) = (3.5 x 3) x 10^(-5 - 10) = 10.5 x 10^-15 = 1.05 x 10(1 - 15) = 1.05 x 10^-14
B . 1.05 x 10^-14
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Answers

Answer:

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Step-by-step explanation:hard to explain maybe look at another response, they would probably do better

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Answers

Answer:

The simplified expression is16a^(8b)  

Step-by-step explanation:

we need to simplify the expression (4a^(4b))^(2)

(4a^(4b) )^(2)  

Using exponent rule : (a* b)^(n) = a^(n)b^(n)

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16(a ^(4b) )^2  

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16a^(8b)

Hence, simplified expression is  16a^(8b)

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(a ^(4b) )^2

Apply exponent rule :

 
(a^b)^c= a ^(b*c)

= a ^(8b)

= 4^2 = 16

=\ \textgreater \ 16 a ^(8b)

hope this helps!