the ionization constant for dichloroacetic acid HC2HO2Cl2 is 5.0 x 10^-2 . What is the pH of a 0.15 molar solution of this acid?

Answers

Answer 1
Answer:

Answer: pH = 1.19

Explanation:

The formula for Ka is:  Ka = [H+][A-]/[HA]

where:  [H+] = concentration of H+ ions

[A-] = concentration of conjugate base ions

[HA] = concentration of undissociated acid molecules

Equation of reaction:  Cl₂CHCOOH ---> H+ + Cl₂CHCOO-

From the equation above, dichloroacetic acid dissociates one H+ ion for every Cl₂CHCOO- ion,

so [H+] = [Cl₂CHCOO-].

Let x represent the concentration of H+ that dissociates from HA, then [HA] = C - x where C is the initial concentration.

Substituting these values into the Ka equation:

Ka = x · x / (C -x)

Ka = x²/(C - x)

(C - x)Ka = x²

x² = CKa - Kax

x² + Kax - CKa = 0

Solve for x using the quadratic formula:

x = [-b ± √(b² - 4ac)]/2a

Note: There are two solutions for x. However only the positive value of x is used since x represents a concentration of ions in solution, and so cannot be negative.

x = [-Ka + √(Ka² + 4CKa)]/2

Substitute the values for Ka and C in the equation above:  

Ka = 5.0 x 10^-2

C = 0.15 M  

x = {-5.0 x 10^-2 + √[(5.0. x 10^-2)² + 4(0.15)(5.0 x 10^-2)]}/2

x = (-5.0 x 10^-2 + 1.80 x 10^-1)/2

x = 0.13/2

x = 6.50 x 10^-2

To find pH, we use the formula;

pH = -log[H+]

pH = -log(x)

pH = -log(6.50 x 10^-2)

pH = -(-1.19)

pH = 1.19


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What is the mass of a neutron close to

Answers

Answer:

The free neutron has a mass of 939,565,413.3 eV/c2, or 1.674927471×10−27 kg, or 1.00866491588 u. The neutron has a mean square radius of about 0.8×10−15 m, or 0.8 fm, and it is a spin-½ fermion.

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Composition: 1 up quark, 2 down quarks

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4Ga + 3S2 → 2Ga2S3 1. How many grams of Gallium Sulfide would form if 20.5 moles of Gallium burned?

Answers

Answer:

m_(Ga_2S_3)=2415.31gGa_2S_3

Explanation:

Hello,

In this case, for the given chemical reaction, we can notice there is a 4:2 molar ratio between the burned moles of gallium and the yielded moles of gallium sulfide, therefore, we compute them as shown below:

n_(Ga_2S_3)=20.5molGa*(2molGa_2S_3)/(4molGa)=10.25mol Ga_2S_3

Then, by using the molar mass of gallium sulfide (235.64 g/mol), we directly compute the grams:

m_(Ga_2S_3)=10.25mol Ga_2S_3*(235.64gGa_2S_3)/(1molGa_2S_3) \n\nm_(Ga_2S_3)=2415.31gGa_2S_3

Best regards.

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Answers

Answer:

a. false

b. true

c. false

d. false

e. false

f. false

Q2: Both have electrons orbiting around the nucleus; Bohr's model is more detailed and expands on Rutherford's

Q5:

a.

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b.

Ne = 10 electrons/protons

Al = 13 electrons/protons

K = 19 electrons/protons

Joan has four containers. The chart below shows the mass and volume of each of the containers. Two of the containers are filled with solids, one is filled with a liquid, and one is filled with a gas.

Answers

Answer:

This question is incomplete

Explanation:

This question is incomplete. However, it should be noted that if the containers are compared with an equal average volume, the containers having solids will have larger masses than that containing liquid which will also have a larger mass than that containing gas. This is because solids have there molecules touching each other in compact manner which makes the molecule exert a certain combined force/mass. The molecules of liquid are also close to one another but are not compact like the solids and are hence exerting a lesser force/mass than solids. Gases have free molecules that are far apart and thus are usually the lightest when they occupy the same volume as liquids and solids.

Wich substances is most likely to form in a precipitation reaction?

Answers

Answer:

A precipitation reaction refers to the formation of an insoluble salt when two solutions containing soluble salts are combined. The insoluble salt that falls out of solution is known as the precipitate, hence the reaction's name.

Explanation:

Note: Please show all work and calculation setups to get full credit. T. he following may be used on this assignment: specific heat of (water=4.184 J/g oC; ice=2.03 J/g oC; steam=1.99 184 J/g oC); heat of fusion of water=80. cal/g; heat of vaporization=540 cal/g; 1cal=4.184J.Calculate the energy required (in J) to convert 25 g of ice at -15 oC to water at 75 oC.

Answers

Answer:

1.7 × 10⁴ J

Explanation:

Step 1: Calculate the heat required to raise the temperature of ice from -15 °C to 0°C

We will use the following expression.

Q₁ = c(ice) × m × ΔT

Q₁ = 2.03 J/g.°C × 25 g × [0°C - (-15°C)] = 7.6 × 10² J

Step 2: Calculate the heat required to melt 25 g of ice

We will use the following expression.

Q₂ = C(fusion) × m

Q₂ = 80. cal/g × 25 g × 4.184 J/1 cal = 8.4 × 10³ J

Step 3: Calculate the heat required to raise the temperature of water from 0°C to 75 °C

We will use the following expression.

Q₃ = c(water) × m × ΔT

Q₃ = 4.184 J/g.°C × 25 g × (75°C - 0°C) = 7.8 × 10³ J

Step 4: Calculate the total heat required

Q = Q₁ + Q₂ + Q₃

Q = 7.6 × 10² J + 8.4 × 10³ J + 7.8 × 10³ J = 1.7 × 10⁴ J