The sine of a 30 degree angle is equal to the cosine of a 60 degree angle.True
False

Answers

Answer 1

Answer:

Answer:

The sentence is True

Step-by-step explanation:

In Geometry, there is a theorem that relation the sine angle and the cosine angle. The theorem says: The sine of any acute angle is equal to the cosine of its complement.

So, let β represent an acute angle

sin (β)=cos(90-β)

Given β=30, let it replace in the formule:

sin (30)=cos(90-30)

sin (30)=cos(60)

Done.

Answer 2

Answer: The answer is True.........................

Related Questions

1. Your grandmother is in the hospital and is put on a liquid diet. After examining her chart, a mistake is found stating that her weight is 500 kg. What is the equivalent weight in pounds?
If y varies directly as x, and y is 6 when x is 72, which is the value of y when x is 8 ?
WILL MARK BRAINLIEST TO QUICKEST ANSWER! PLEASE HURRYThe graph of the even function f(x) has five x-intercepts. If (6, 0) is one of the intercepts, which set of points can be the other x-intercepts of the graph of f(x)?A.(–6, 0), (–2, 0), and (0, 0)B.(–6, 0), (–2, 0), and (4, 0)C. (–4, 0), (0, 0), and (2, 0)D.(–4, 0), (–2, 0), and (0, 0)
Find the value of x part 1a
Mrs. Ramiriz is making pies to sell at the local farmer’s market. It costs her $5 to make each pie, plus a one-time cost of $30 for baking supplies. She plans to sell the pies for $12 each. Which equation can be used to find the number of pies she needs to sell to break even?

Bubba can mow a field in 8 hours. If Skeeter helps, they both can do it together in 3 hours. How long would it take Skeeter to mow the field by himself?

Answers

When they work together, they do 1/3 of the job in one hour.

   (Bubba) + (Skeeter) = 1/3 job/hour

Subtract 'Bubba'
from each side:     Skeeter = (1/3 job/hour) - (Bubba)

Bubba, working alone, does 1/8 of the job in one hour.

      Skeeter = (1/3 job/hour) - (1/8 job/hour)

Can you subtract 1/8 from 1/3 ?

Before you can subtract, you'll need a common denominator.
I've got a nice one here . . . 24 .

   1/3 = 8/24
   1/8 = 3/24

   Skeeter = (1/3 job/hour) - (1/8 job/hour)

      = (8/24 job/hour) - (3/24 job/hour)

=    5/24 job/hour .

Skeeter mows at the rate of 5/24 field/hour.

The other way to look at that is: 24/5 hour/field = 4.8 hours .

Check:

   Bubba:   1/8     field per hour = 0.125
   Skeeter: 1/4.8 field per hour = 0.208333...

   Together: (0.125 + 0.208333)

   = 0.333... field per hour

   = 3 hours/field . yay!

Write an inequality to solve the following problem.Carlos wants to send a gift basket to his grandmother. Deliver Quick charges a
processing fee of $4.45 plus $1.05 per pound. If Carlos can only spend $15 or less
on shipping, what are the possible weights for the gift basket?
4.45+1.05x <15
4.45+ 1.05x >15
4.45x + 1.05 <15
4.45x + 1.05 >15

Answers

Answer:

The Correct Answer is A

4.45 + 1.05x <= 15

Step-by-step explanation:

Answer:

4.15x + 0.85x <- 15

Step-by-step explanation:

Got it wrong on the test and it said this was the right answer.

Miles and Nick each separately apply for and receive loans worth $5,000 apiece. Miles has a very good credit score, so his loan has an APR of 7.75%, compounded monthly. Nick’s credit score is rather low, so his loan has an APR of 13.10% interest, compounded monthly. If both of them repay their loans over a four year period, making equal monthly payments based on their own loan, how much more will Nick have paid than Miles? (Round all dollar values to the nearest cent.) a.$619.68 b.$267.50 c.$1,609.57 d.$1,070.00

Answers

Answer:

Ans. Nick paid $619.68 more than Miles (exactly $619.54). So the answer is A)

Step-by-step explanation:

Hi, first we need to find the equal monthly payments for both, Miles and Nick, for that, we need to find the effective monthly rate (because the payments are going to be made monthly), also, we need to convert that 4 year period into months. After doing all that, we need to use the following equation and solve for "A".

$Present Value=(A((1+r)^(n) -1))/(r(1+r)^(n) )$

Where:

A= monthly payments

r= rate of interest (for Miles is 0.075/12=0.006458 and Nick 0.131/12=0.010916)

n= number of periodic payments (both are 4*12=48 months)

First, let´s find out how much money Miles has to pay every month.

$5,000=(A((1+0.00645833)^(48) -1))/(0.00645833(1+0.00645833)^(48) )$

$5,000=A(41.1594758)$

$A=121.48$

So, Miles has to pay $121.48 every month, for 48 months, that is a total of $5,830.98 (121.48*48=5,830.98)

Now, let´s do Nick

$5,000=(A((1+0.01091667)^(48) -1))/(0.01091667(1+0.01091667)^(48) )$

$5,000=A(37.2063189)$

$A=134.39$

So, Nick has to pay $134.39 every month, for 48 months, that is a total of $6,450.52 (134.39*48=6,450.52)

The difference is 6,450.52- 5,830.98=619.54

Means that Nick has to pay $619.54 more than Miles. To your answers, the closest is A) $619.68.

Best of luck

Miles:7.75% (0.0775) x 5,000 = $387.5 x 4 = $1550 (over four year period)Nick:13.10% (0.131) x 5,000 = $655 x 4 = $2620$2620 - $1550 = $1,070 (rounded to nearest cent)So the answer is D.

A student received a 75% on an exam. If there were 20 questions on the exam, which ratio would show the number of questions answered correctly?A. 15:20
B. 20:15
C. 5:20
D. 20:5

Answers

Assuming the question is asking for the ratio of questions answered correctly to the number of questions, A is the correct answer. 75% of 20 is 15 ((20/4) x 3), so 15:20 is correct, though this can be cancelled to 3:4. If the question asks for the ratio of correct to incorrect answers, the ratio would be 15:5, or 3:1.

Which measures would be the side lengths of a right triangle?A. 2 cm, 5 cm, 7 cm
B. 9 cm, 14 cm, 17 cm
C. 7 cm, 17 cm, 24 cm
D. 5 cm, 12 cm, 13 cm

Answers

Conditions for side lenghts for triangle:
a<b+c and
b<c+a and
c<a+b
so we check all posibilities:
A) 2+5=7 we can see that one condition is not fulfilled so they can't be side lenghts of triangle
B) 9<14+17
14<9+17
17<14+19
All conditions are fulfilled so they can be side lenghts of triangle
C)7<17+24
17<7+24
24<17+7
All conditions are fulfilled so they can be side lenghts of triangle
D)5<12+13
12<5+13
13<5+12
All conditions are fulfilled so they can be side lenghts of triangle

How is 4.3 x 10^-3 the answer to this question? A sample of air from a home is found to contain 6.2 ppm of carbon monoxide. This means that if the total pressure is 695 torr, then the partial pressure of CO is..................4.3 x 10^-3.

Answers

The partial pressure of CO2 is equal to the total pressure * molar fraction of CO2.

To give 4.3 * 10^-3, they are using molar fraction = 6.2 * 10^ - 6

Because, 695 * 6.2-10^-6 = 0.004309 = 4.309 * 10^-3 = 4.3 * 10^-3.

Then the new question is why the molar fraction is consideres to be the same ppm concentration. This is because ppm means parts per million, and in this case, they are considering that the parts are moles (usually it is grams, but it is not the case, given the result).

6.2 ppm = 6.2 / 1,000,000 = 6.2*10^-6, which is the number used above to multiply the total pressure and get the partial pressure of CO2.

If you had not told me that the result was 4.3 * 10^-3, I had assumedthat 6.2 was referred to grams and not moles and I had made a conversionusing the molar masses of the air and the CO2 but, again, this is not the case.

Final answer:

The partial pressure of CO in a home with air containing 6.2 ppm CO, when the total air pressure is 695 torr, can be calculated by (6.2 ÷ 1,000,000) x 695, which equals 4.3 x 10^-3 torr.

Explanation:

The partial pressure of a gas is the individual pressure contribution a single type of gas makes to the overall pressure of a gas mixture. In this case, a sample of air from a home was found to contain 6.2 parts per million (ppm) of carbon monoxide (CO). To calculate the actual pressure of CO in the room, we can use the fact that 1 ppm = 1 part of the substance per 1,000,000 parts of air.

To do so, we need to multiply thetotal pressure of the air, which is 695 torr, by the ratio of the CO to the total volume of the air. That would be: (6.2 ÷ 1,000,000) x 695 = 4.3 x 10-3 torr. Hence, that is how 4.3 x 10-3 is derived as the partial pressure of CO in this context.