A 45.2-kg wagon is towed up a hill inclined at 18.5∘ with respect to the horizontal. The tow rope is parallel to the incline and has a tension of 191 N in it. Assume that the wagon starts from rest at the bottom of the hill, and neglect friction. How fast is the wagon going after moving 83.8 m up the hill?
Answers
Answer:
The speed is 29.9 m/s
Explanation:
The force created from gravity due to the wagon mass is:
140.55 N pull the wagon down. Two parallel rope with tension of 191N creates 382 N on the wagon. Therefore:
241.45 N force is pulling up the wagon. Then we need to find the acceleration of the wagon under this force:
acceleration is 5.34 m/s^2. The distance is multiplication of acceleration and square of the time.
After 5.6 second the wagon will ride 83.8 m up to hill. And the speed of wagon at that point is:
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ikkkkrtrrr
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b. Explain why the two recordings would sound different after being replayed 100 times.
Answers
a)The analog signal'spitch and frequency change each time. It is continuous in the digital signal.
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Answers
The correct answer to the question is: Direction
EXPLANATION:
The average velocity of a body is defined as the rate of change of displacement.
We know that displacement is a vector quantity. Hence, it has magnitude as well as direction for its specification.
On the other hand, the average speed of a body is defined as the rate of change of distance travelled. Hence, the average speed of a body is a scalar quantity. It means that it has only magnitude.
Hence, during the calculation of average velocity,we have to think of its direction.
Answers
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plasma is the 4th state
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Explanation:
Apparently the answer is 4 but I have no idea why
Answers
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(2). 9.19 x 10² Hz = 919 Hz . . . that's lower
(3). 1.00 x 10³ Hz = 1,000 Hz . . . that's exactly the same
(4). 1.10 x 10³ Hz = 1,100 Hz . . . that's the only choice that's higher than 1,000 Hz.