To find the planet's radius in terms of the radius Rg of Earth, use the equation g = GM/R^2 and substitute 2g for g. Solve for R to get R = sqrt(1/(2gMg)) * Rg.
To find the planet's radius in terms of the radius Rg of Earth, we need to understand the relationship between the gravitational field and the mass and radius of a planet. The magnitude of the gravitational field on the surface of a planet is given by g = GM/R2, where G is the gravitational constant, M is the mass of the planet, and R is its radius. For the planet in question, we are told that the magnitude of the gravitational field is 2g and its mass is half the mass of Earth. Since the gravitational field is 2g, we can substitute g with 2g in the equation and solve for R in terms of Rg:
2g = GM/R2 → 2gR2 = GM → 2gR2 = (GMg)/(2Rg) → R2/Rg = 1/(2gMg) → R = sqrt(1/(2gMg)) * Rg
#SPJ12
To find the radius of a planet with a gravitational field twice that of Earth's and half the mass, the radius is calculated to be half of Earth's radius.
The magnitude of the gravitational field strength g on a planet is given by the equation g = G(M/R^2), where G is the universal gravitation constant, M is the planet's mass, and R is the planet's radius. Given that the gravitational field on the surface of the particular planet is 2g where g is Earth's gravitational field, and the planet's mass is half of Earth's mass, we can derive the planet's radius in terms of Earth's radius Rg. Setting up the proportion (G(1/2M_Earth)/(R^2)) / (G(M_Earth)/(Rg^2)) = 2, and simplifying, we find that R^2 = (1/4)Rg^2. Taking the square root of both sides gives us the final relation R = (1/2)Rg.
#SPJ3
Hi Kayla
Examples are ;
1) Gymnosperms
2) Angiosperms
Hint; Gymnosperms create cones to house their seeds
Angiosperms; Create their seeds inside fruits
I hope that's help:0
B. Prominences
C. Solar flares
D. Sunspots
b rolling ball going down a hill
c moving car
d orbiting satellite
Explanation:
Simple harmonic motion requires a restoring force.
Simple harmonic motion should be periodic.
Option A:
When a rubber band is stretched,the internal forces of the rubber band pulls the band inside.So,internal forces are the restoring forces in a rubber band.
The motion is periodic as well since the the rubber band makes to an fro motion expanding ans contracting.
So,this performs SHM.
Option B:
There is no restoring force and no periodicity.
So,this is not SHM.
Option C:
There is no restoring force and no periodicity.
So,this is not SHM.
Option D:
There is periodicity but no restoring force.
So,this is not SHM.
apply.
A. Gravity exists only on Earth.
O
B. Gravity exists between two objects that have mass.
O
C. Gravity is a force that pulls two objects together.
D. Gravity exists in the whole universe.
E. Gravity doesn't exist between Earth and the sun.