A certain lightning bolt moves 40 C of charge. How many fundamental units of charge |qe| is this?

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Answer 1

Answer: Answer to A certain lightning bolt moves 40.0 C of charge. How many fundamental units of charge | qe | is this? . ... charge, N is the total number of electron or protons that constitute total charge Q.

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To see how two traveling waves of the same frequency create a standing wave. Consider a traveling wave described by the formula y1(x,t)=Asin(kx−ωt)
This function might represent the lateral displacement of a string, a local electric field, the position of the surface of a body of water, or any of a number of other physical manifestations of waves.
1. Find ye(x) and yt(t). Keep in mind that yt(t) should be a trigonometric function of unit amplitude.
2. At the position x=0, what is the displacement of the string (assuming that the standing wave ys(x,t) is present)?
3. At certain times, the string will be perfectly straight. Find the first time t1>0 when this is true.
4. Which one of the following statements about the wave described in the problem introduction is correct?
A. The wave is traveling in the +x direction.
B. The wave is traveling in the −x direction.
C. The wave is oscillating but not traveling.
D. The wave is traveling but not oscillating.
Which of the expressions given is a mathematical expression for a wave of the same amplitude that is traveling in the opposite direction? At time t=0this new wave should have the same displacement as y1(x,t), the wave described in the problem introduction.
A. Acos(kx−ωt)
B. Acos(kx+ωt)
C. Asin(kx−ωt)
D. Asin(kx+ωt)

Answers

The definition of standing wave and trigonometry allows to find the results for the questions about the waves are:

1. For the standing wave its parts are: spatial $y_e = A' \ sin \ kx$ and

temporal part $y_t = A' \ cos \ wt$

2. The string moves with an oscillating motion y = A’ cos wt.

3. Thefirst displacement is zero for $t = (\pi )/(2w)$

4. the correct result is:

A. The wave is traveling in the +x direction.

5. The correct result is:

D. Asin(kx+ωt)

Traveling waves are periodic movements of the media that transport energy, but not matter, the expression to describe it is:

y₁ = A sin (kx -wt)

Where A is the amplitude of the wave k the wave vector, w the angular velocity and x the position and t the time.

1. Ask us to find the spatial and temporal part of the standing wave.

To form the standing wave, two waves must be added, the reflected wave is:

y₂ = A sin (kx + wt)

The sum of a waves

y = y₁ + y₂

y = A (sin kx-wt + sin kx + wt)

We develop the sine function and add.

Sin (a ± b) = sin a cos b ± sin b cos a

The result is:

y = 2A sin kx cos wt

They ask that the function be unitary therefore

The amplitude of each string

A_ {chord} = A_ {standing wave} / 2

The spatial part is

$y_e$ = A 'sin kx

The temporary part is:

$y_t$ = A ’cos wt

2. At position x = 0, what is the displacement of the string?

y = A ’cos wt

The string moves in an oscillating motion.

3. At what point the string is straight.

When the string is straight its displacement is zero x = 0, the position remains.

y = A ’cos wt

For the amplitude of the chord to be zero, the cosine function must be zero.

wt = (2n + 1) $(\pi)/(2)$

the first zero occurs for n = 0

wt = $(\pi )/(2)$

t = $(\pi )/(2w)$

4) The traveling wave described in the statement is traveling in the positive direction of the x axis, therefore the correct statement is:

A. The wave is traveling in the +x direction.

5) The wave traveling in the opposite direction is

y₂ = A sin (kx + wt)

The correct answer is:

D. Asin(kx+ωt)

In conclusion using the definition of standing wave and trigonometry we can find the results for the questions about the waves are:

1. For the standing wave its parts are: spatial $y_e = A' \ sin \ kx$ and

temporal part $y_t = A' \ cos \ wt$

2. The string moves with an oscillating motion y = A’ cos wt.

3. Thefirst displacement is zero for $t = (\pi )/(2w)$

4. the correct result is:

A. The wave is traveling in the +x direction.

5. The correct result is:

D. Asin(kx+ωt)

Learn more about standing waves here: brainly.com/question/1121886

A simple pendulum takes 2.20 s to make one compete swing. If we now triple the length, how long will it take for one complete swing?

Answers

Answer:

Time taken for 1 swing = 3.81 second

Explanation:

Given:

Time taken for 1 swing = 2.20 Sec

Find:

Time taken for 1 swing , when triple the length(T2)

Computation:

Time taken for 1 swing = 2π[√l/g]

2.20 = 2π[√l/g].......Eq1

Time taken for 1 swing , when triple the length (3L)

Time taken for 1 swing = 2π[√3l/g].......Eq2

Squaring and dividing the eq(1) by (2)

4.84 / T2² = 1 / 3

T2 = 3.81 second

Time taken for 1 swing = 3.81 second

For a very rough pipe wall the friction factor is constant at high Reynolds numbers. For a length L1 the pressure drop over the length is p1. If the length of the pipe is then doubled, what is the relation of the new pressure drop p2 to the original pressure drop p1 at the original mass flow rate?

Answers

Answer: ∆p2 = 2* ∆p1

Explanation:

Given that all other factors remain constant. The pressure drop across the pipeline is directly proportional to the length.

i.e ∆p ~ L

Therefore,

∆p2/L2 = ∆p1/L1

Since L2 = 2 * L1

∆p2/2*L1 = ∆p1/L1

Eliminating L1 we have,

∆p2/2 = ∆p1

Multiplying both sides by 2

∆p2 = 2 * ∆p1

g A particular guitar string has a length of 60.0 cm, and a mass per unit length of 2.00 grams/meter. You hear a pure tone of 660 Hz when a particular standing wave, represented by the animation above, is excited on the string. Calculate the wavelength of this standing wave.

Answers

Answer:

wavelength of the standing wave will be equal to 30 cm

Explanation:

We have given length of the guitar string L = 60 cm

Mass per unit length $\mu =2gram/m$

Frequency is given f = 660 Hz

We have to find the wavelength of the standing wave

Length of the string will be 2 times of the wavelength of the wave

So $L=2\lambda$

$\lambda =(L)/(2)=(60)/(2)=30cm$

So wavelength of the standing wave will be equal to 30 cm

A large convex lens stands on the floor. The lens is 180 cm tall, so the principal axis is 90 cm above the floor. A student holds a flashlight 120 cm off the ground, shining straight ahead (parallel to the floor) and passing through the lens. The light is bent and intersects the principal axis 60 cm behind the lens. Then the student moves the flashlight 30 cm higher (now 150 cm off the ground), also shining straight ahead through the lens. How far away from the lens will the light intersect the principal axis now?A. 30 cm
B. 60 cm
C. 75 cm
D. 90 cm

Answers

B. 60 cm

All parallel light rays are bent through the focal point of a convex lens, so the rays from the flashlight 150 cm above the floor must go through the same point on the principal axis as the rays from the flashlight 120 cm above the floor. The location of the focal point does not change when the position of the object is moved either vertically or horizontally.

Please use Gauss’s law to find the electric field strength E at a distance r from the center of a sphereof radius R with volume charge density ???? = cr 3 and total charge ????. Your answer should NOT contain c. Be sure to consider regions inside and outside the sphere.

Answers

Answer:

See the explaination for the details.

Explanation:

Gauss Law states that the total electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux in an area is defined as the electric field multiplied by the area of the surface projected in a plane and perpendicular to the field.

According to the Gauss law, the total flux linked with a closed surface is 1/ε0 times the charge enclosed by the closed surface.

Please kindly check attachment for the step by step explaination of the answer.

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