MATHEMATICS MIDDLE SCHOOL

Pls help ASAP!!!On a certain hot summer's day, 622 people used the public swimming pool. The daily prices are $ 1.75 for children and $ 2.50 for adults. The receipts for admission totaled $ 1375.00. How many children and how many adults swam at the public pool that day? 22 POINTS

Answers

Answer 1

Answer:

240 children and 382 adult swam at the public pool that day

Solution:

Let "c" be the number of childrens

Let "a" be the number of adults

Cost of 1 child ticket = $ 1.75

Cost of 1 adult ticket = $ 2.50

622 people used the public swimming pool

Therefore,

number of childrens + number of adults = 622

c + a = 622 ------ eqn 1

The receipts for admission totaled $ 1375.00

Therefore, we can frame a equation as:

number of childrens x Cost of 1 child ticket + number of adults x Cost of 1 adult ticket = 1375.00

$c * 1.75 + a * 2.50 = 1375$

1.75c + 2.50a = 1375 ----- eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

c = 622 - a -------- eqn 3

Substitute eqn 3 in eqn 2

1.75(622 - a) + 2.50a = 1375

1088.5 - 1.75a + 2.50a = 1375

0.75a = 1375 - 1088.5

0.75a = 286.5

a = 382

Substitute a = 382 in eqn 3

c = 622 - 382

c = 240

Thus 240 children and 382 adult swam at the public pool that day

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Answers

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It is the conversion of one unit to another unit with its standard conversion.

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Learn more about unitconversion here:

brainly.com/question/13899873

#SPJ6

0
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Answers

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Answers

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