7. An 8.92 kilogram bar of steel at 25°C is heated in order to shape it into a beam. The amount of heat energytransferred to the steel is found to be 5.82 x 103 kJ. If the specific heat capacity of steel is 0.51 op what was the
change in the temperature of the steel?
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Answer:
1279 °C
Explanation:
Data Given:
Amount of Heat absorb = 5.82 x 10³ KJ
Convert KJ to J
1 KJ = 1000 J
5.82 x 10³ KJ = 5.82 x 10³ x 1000 = 5.82 x10⁶ J
mass of sample = 8.92 Kg
Convert Kg to g
1 kg = 1000 g
8.92 Kg = 8.92 x 1000 = 8920 g
Cs of steel = 0.51 J/g °C
change in temperature = ?
Solution:
Formula used
Q = Cs.m.ΔT
rearrange the above equation to calculate the mass of steel sample
ΔT = Q / Cs.m .... . . . . . (1)
Where:
Q = amount of heat
Cs = specific heat of steel = 0.51 J/g °C
m = mass
ΔT = Change in temperature
Put values in above equation 1
ΔT = 5.82 x10⁶ J / 0.51 (J/g °C) x 8920 g
ΔT = 5.82 x10⁶ J /4549.2 (J/°C)
ΔT = 1279 °C
So,
change in temperature = 1279 °C
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Can someone help me fast plz. I will really appreciate
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The equation is not balanced because the number of atoms of Oxygen present in the reactants and product sides are not equal
The equation being referred to in the question can be written properly as
S + 3O₂ → SO₃
To determine whether the equation is balanced or not
We will check if the coefficient in the equation gives equal numbers of atoms for each element in the reactants and product
- For the reactants side
S = 1
O = 6
- For the product side
S = 1
O = 3
We can observe that, the coefficient does not give equal number of atoms for the element, Oxygen (O), in the reactants and product sides
∴ The equation is NOT balanced
Hence, the equation is not balanced because the number of atoms of Oxygen present in the reactants and product sides are not equal
Learn more here: brainly.com/question/24943155
Answer:
This equation is not balanced because you don't have the same amount of each element on each side of the chemical reaction. The balanced equation is:
2 S + 3 ⇒ 2
Explanation:
The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.
Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts.
The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.
By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.
Then, taking into account all of the above, you can determine the amount of elements on each side of the equation:
Left side: 1 sulfur S and 6 oxygen O (coefficient 3 multiplied by sub-index 2)
Right side: 1 sulfur S and 3 oxygen O (subindice value)
As you can see, you have the same amount of sulfur on both sides of the equation but the amount of oxygen is different. This indicates that the chemical equation is not balanced. To balance it, as the amount of sulfur is the same, the amount of oxygen must be balanced, which is different on each side of the reaction.
A simple way is to balance the equation is to multiply the product by 2, that is, add a coefficient 2 in front of the SO3 molecule, the reaction being as follows:
S + 3 ⇒ 2
Now the amount of elements on each side of the equation is:
Left side: 1 sulfur S and 6 oxygen O (coefficient 3 multiplied by subindice 2)
Right side: 2 sulfur S and 6 oxygen O (coefficient 2 multiplied by subindice 3)
The oxygen is now balanced, but the amount of sulfur on both sides of the reaction varies. To balance the quantities of sulfur, as now on the right side you have an amount of 2, you can add the coefficient to sulfur. The chemical equation is as follows:
2 S + 3 ⇒ 2
Now the amount of elements on each side of the equation is:
Left side: 2 sulfur S and 6 oxygen O (coefficient 3 multiplied by subindice 2)
Right side: 2 sulfur S and 6 oxygen O (coefficient 2 multiplied by subindice 3)
Finally you have the same amount of sulfur and oxygen on both sides of the reaction. So the chemical equation is finally balanced.
Answers
Answer:
m = density x volume
The density of O2 is 1.429g/L
1.429g/L x 1L = 1.429g
1.429g/32g/mol = 0.045 moles
Explanation:
2)An internal combustion engine doesn't have a cylinder and a piston.
3)The burning of fuel occurs inside the cylinder with the piston in an internal combustion engine.
4)An external combustion engine doesn't have a cylinder and a piston
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Answer: The correct answer is option (3).
Explanation:
Internal combustion engine: An engine which generates motive power by burning the fuel with air inside the engine. Heat produced is used to move piston or to perform other work as they expand.
External combustion engine : An engine where motive power is generated by providing the heat to the fluid present inside the engine from the external source. Here combustion of the fuel is not inside the engine.
Hence,the correct answer is option (3).
The answer is 3) The burning of fuel occurs inside the cylinder with the piston in an internal combustion engine.
Explanation: I took the test :)
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Answer:
The number of protons of the Pb is 82.
The number of electrons of the Pb²⁺ is 80.
Explanation:
Each chemical element is characterized by the number of protons in its nucleus, which is called the atomic number Z.
The atomic number is used to classify the elements within the periodic table of the elements. In it, you can read in the upper left. In this case, the lead Pb has an atomic number of 82. This indicates that the number of protons of the Pb²⁺ is 82.
In every electrically neutral atom the number of protons in the nucleus is equal to the number of electrons in their orbitals. But in this case it is a cation, that is, it is a positively charged ion. A cation is formed when electrons are lost (which have a negative charge), thus acquiring the positive charge ion. In this case then, Pb²⁺ indicates that the cation has a +2 charge. So this means that 2 electrons have been lost. So, if it were electrically neutral, the lead Pb would have 82 electrons, but with the loss of two of its electrons, the number of electrons of the Pb²⁺ is 80.
There are 82 protons and 80 electrons in one Pb²⁺ ion. Lead (Pb) has an atomic number of 82.
The atomic number of an element represents the number of protons in its nucleus. Since lead (Pb) has an atomic number of 82, it means that a neutral lead atom has 82 protons.
When the Pb²⁺ ion is formed, it means that the atom has lost two electrons. The +2 charge indicates that the atom now has two more protons than electrons. Since electrons have a negative charge, losing two of them results in a net positive charge on the ion.
Since a neutral lead atom has 82 electrons, subtracting two electrons from it gives us 80 electrons in the Pb²⁺ ion. However, the number of protons remains the same at 82. The loss of electrons creates a positive charge, and the number of protons determines the element's identity.
In summary, the Pb²⁺ ion has 82 protons and 80 electrons. The 2+ charge indicates the loss of two electrons, resulting in a net positive charge on the ion.
To learn more about protons and electrons, here
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