CHEMISTRY HIGH SCHOOL

In a closed container, the vapor pressure of 10 mL of ethanol at 20 degrees C is 5.85 kPa. What is the vapor pressure of 20 mL of ethanol at the same temperature?

Answers

Answer 1
Answer:

Answer:

{P_2}=2.925\ kPa

Explanation:

At same temperature and same number of moles, Using Boyle's law  

{P_1}* {V_1}={P_2}* {V_2}

Given ,  

V₁ = 10 mL

V₂ = 20 mL

P₁ = 5.85 kPa

P₂ = ?

Using above equation as:

{P_1}* {V_1}={P_2}* {V_2}

{5.85\ kPa}* {10\ mL}={P_2}* {20\ mL}

{P_2}=\frac{{5.85}* {10}}{20}\ kPa

{P_2}=2.925\ kPa

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Answers

Answer:

b) the metals strips

Explanation:

In an experimental design, an independent variable is a variable that is changed or manipulated in a series of experiments. An independent variable is not dependent on any other variable in the experiment. The hypothesis for this experiment is stated to be: "If the chemical activity of the metallic wrapper is increased, then less rusting of iron will occur. The independent variable relates to the type of metal wrapping strip, and the dependent variables are the amount of rusting and color of the water.

3. 56 g of N₂ reacts 9 g of H₂ in a closed vessel to form NH3. Which reactant is left in excess and how 2207 much? 1) N₂, 10. g +3th = 2013/ (3) N₂, 14 g (2) H₂, 4 g (4) H₂,3 g N₂- to d A​

Answers

Answer:  the reactant left in excess is H₂, and the amount of excess H₂ is 4.5 moles - 3 moles = 1.5 moles.

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Moles of H₂ = 9 g / 2 g/mol = 4.5 moles

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Answers

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Answers

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Answer:

The answer is D, the circulatory system.

Explanation:

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Answers

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Answers

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